Money Word Problems

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Question 1 of 7

1. Question

Frank earns

$ 14

$$14$ per hour for the first

3

$3$ hours of work and

$ 12.50

$$12.50$ an hour after that. How many hours did he work to earn

$ 117

$$117$ ?

$x =$ $x=$ (6)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of hours worked after

3

$3$ hrs:

x

$x$

Translate the problem into an equation based on the diagram

3 ($ 14) + x ($ 12.50)

$3($14)+x($12.50)$

=

$=$

$ 117

$$117$

Solve for

x

$x$

$3 ($ 14) + x ($ 12.50)$ $3($14)+x($12.50)$	$=$ $=$	$$ 117$ $$117$
$42 + 12.5 x$ $42+12.5x$	$=$ $=$	$117$ $117$
$42 + 12.5 x$ $42+12.5x$ $- 42$ $-42$	$=$ $=$	$117$ $117$ $- 42$ $-42$	Subtract $42$ $42$ from both sides
$12.5 x$ $12.5x$	$=$ $=$	$75$ $75$
$12.5 x$ $12.5x$ $\div 12.5$ $-:12.5$	$=$ $=$	$75$ $75$ $\div 12.5$ $-:12.5$	Divide both sides by $12.5$ $12.5$
$x$ $x$	$=$ $=$	$6$ $6$

x = 6

$x=6$

Question 2 of 7

2. Question

A school concert was attended by adults and students. The tickets cost

$ 15

$$15$ per adult and

$ 6

$$6$ per student. The total ticket sales was

$ 2235

$$2235$ . If

95

$95$ adults attended the concert, how many students were there?

(135)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of students in the concert:

n

$n$

Translate the problem into an equation based on the diagram

95 ($ 15) + n ($ 6)

$95($15)+n($6)$

=

$=$

$ 2235

$$2235$

Solve for

n

$n$

$95 ($ 15) + n ($ 6)$ $95($15)+n($6)$	$=$ $=$	$$ 2235$ $$2235$
$1425 + 6 n$ $1425+6n$	$=$ $=$	$2235$ $2235$
$1425 + 6 n$ $1425+6n$ $- 1425$ $-1425$	$=$ $=$	$2235$ $2235$ $- 1425$ $-1425$	Subtract $1425$ $1425$ from both sides
$6 n$ $6n$	$=$ $=$	$810$ $810$
$6 n$ $6n$ $\div 6$ $-:6$	$=$ $=$	$810$ $810$ $\div 6$ $-:6$	Divide both sides by $6$ $6$
$n$ $n$	$=$ $=$	$135$ $135$

135

$135$

Question 3 of 7

3. Question

I have

60

$60$ coins. Some are

10 ¢

$10¢$ and the rest are

20 ¢

$20¢$ coins. Altogether, they total

$ 10.80

$$10.80$ . How many of each of the coins do I have?

Number of $10 ¢$ $10¢$ coins: (12)

Number of $20 ¢$ $20¢$ coins: (48)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of

10 ¢

$10¢$ coins:

n

$n$

number of

20 ¢

$20¢$ coins:

60 - n

$60-n$

Translate the problem into an equation based on the diagram and make sure all values are in the same units

$10 ¢ (n) + 20 ¢ (60 - n)$ $10¢(n)+20¢(60-n)$	$=$ $=$	$$ 10.80$ $$10.80$
$10 ¢ (n) + 20 ¢ (60 - n)$ $10¢(n)+20¢(60-n)$	$=$ $=$	$1080 ¢$ $1080¢$

Solve for

n

$n$

$10 ¢ (n) + 20 ¢ (60 - n)$ $10¢(n)+20¢(60-n)$	$=$ $=$	$1080 ¢$ $1080¢$
$10 n + 1200 - 20 n$ $10n+1200-20n$	$=$ $=$	$1080$ $1080$
$1200 - 10 n$ $1200-10n$	$=$ $=$	$1080$ $1080$
$1200 - 10 n$ $1200-10n$ $- 1200$ $-1200$	$=$ $=$	$1080$ $1080$ $- 1200$ $-1200$	Subtract $1200$ $1200$ from both sides
$- 10 n$ $-10n$	$=$ $=$	$- 120$ $-120$
$- 10 n$ $-10n$ $\div (- 10)$ $-:(-10)$	$=$ $=$	$- 120$ $-120$ $\div (- 10)$ $-:(-10)$	Divide both sides by $- 10$ $-10$
$n$ $n$	$=$ $=$	$12$ $12$	number of $10 ¢$ $10¢$ coins

Solve for

60 - n

$60-n$

	$60 - n$ $60-n$
$=$ $=$	$60 - 12$ $60-12$	Substitute $n$ $n$
$=$ $=$	$48$ $48$	number of $20 ¢$ $20¢$ coins

Number of

10 ¢

$10¢$ coins:

12

$12$

Number of

20 ¢

$20¢$ coins:

48

$48$

Question 4 of 7

4. Question

A bank teller orders a payroll in

$ 20

$$20$ and

$ 50

$$50$ notes. She needs

82

$82$ notes totalling

$ 2450

$$2450$ . Calculate how many of each note she must order.

Number of $$ 20$ $$20$ notes: (55)

Number of $$ 50$ $$50$ notes: (27)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of

$ 20

$$20$ notes:

x

$x$

number of

$ 50

$$50$ notes:

82 - x

$82-x$

Translate the problem into an equation based on the diagram

$ 20 (x) + $ 50 (82 - x)

$$20(x)+$50(82-x)$

=

$=$

$ 2450

$$2450$

Solve for

x

$x$

$$ 20 (x) + $ 50 (82 - x)$ $$20(x)+$50(82-x)$	$=$ $=$	$$ 2450$ $$2450$
$20 x + 4100 - 50 x$ $20x+4100-50x$	$=$ $=$	$2450$ $2450$
$4100 - 30 x$ $4100-30x$	$=$ $=$	$2450$ $2450$
$4100 - 30 x$ $4100-30x$ $- 4100$ $-4100$	$=$ $=$	$2450$ $2450$ $- 4100$ $-4100$	Subtract $4100$ $4100$ from both sides
$- 30 x$ $-30x$	$=$ $=$	$- 1650$ $-1650$
$- 30 x$ $-30x$ $\div (- 30)$ $-:(-30)$	$=$ $=$	$- 1650$ $-1650$ $\div (- 30)$ $-:(-30)$	Divide both sides by $- 30$ $-30$
$x$ $x$	$=$ $=$	$55$ $55$	number of $$ 20$ $$20$ notes

Solve for

82 - x

$82-x$

	$82 - x$ $82-x$
$=$ $=$	$82 - 55$ $82-55$	Substitute $x$ $x$
$=$ $=$	$27$ $27$	number of $$ 50$ $$50$ notes

Number of

$ 20

$$20$ notes:

55

$55$

Number of

$ 50

$$50$ notes:

27

$27$

Question 5 of 7

5. Question

Anna has

$ 8

$$8$ more than Julie, and Pina has

$ 15

$$15$ less than Anna. If they have

$ 37

$$37$ altogether, how much does each person have?

Anna: $$$ $$$ (20)

Julie: $$$ $$$ (12)

Pina: $$$ $$$ (5)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

Anna:

x

$x$

Julie:

x - 8

$x-8$

Pina:

x - 15

$x-15$

Translate the problem into an equation based on the diagram

x + (x - 8) + (x - 15)

$x+(x-8)+(x-15)$

=

$=$

$ 37

$$37$

Solve for

x

$x$

$x + (x - 8) + (x - 15)$ $x+(x-8)+(x-15)$	$=$ $=$	$$ 37$ $$37$
$3 x - 23$ $3x-23$	$=$ $=$	$37$ $37$
$3 x - 23$ $3x-23$ $+ 23$ $+23$	$=$ $=$	$37$ $37$ $+ 23$ $+23$	Add $23$ $23$ to both sides
$3 x$ $3x$	$=$ $=$	$60$ $60$
$3 x$ $3x$ $\div 3$ $-:3$	$=$ $=$	$60$ $60$ $\div 3$ $-:3$	Divide both sides by $3$ $3$
$x$ $x$	$=$ $=$	$$ 20$ $$20$	Anna’s money

Solve for

x - 8

$x-8$

	$x - 8$ $x-8$
$=$ $=$	$20 - 8$ $20-8$	Substitute $x$ $x$
$=$ $=$	$$ 12$ $$12$	Julie’s money

Solve for

x - 15

$x-15$

	$x - 15$ $x-15$
$=$ $=$	$20 - 15$ $20-15$	Substitute $x$ $x$
$=$ $=$	$$5$	Pina’s money

Anna:

$$20$

Julie:

$$12$

Pina:

$$5$

Question 6 of 7

6. Question

James earns

$$20$ a day more than Tom and

$$27$ a day less than Bob. The

$3$ friends’ total earnings for one day is

$$733$ . Find the daily earning of each friend.

James: $$$ (242)

Tom: $$$ (222)

Bob: $$$ (269)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

James:

$x$

Tom:

$x-20$

Bob:

$x+27$

Translate the problem into an equation based on the diagram

$x+(x-20)+(x+27)$

$=$

$$733$

Solve for

$x$

$x+(x-20)+(x+27)$	$=$	$$733$
$3x+7$	$=$	$733$
$3x+7$ $-7$	$=$	$733$ $-7$	Subtract $7$ from both sides
$3x$	$=$	$726$
$3x$ $-:3$	$=$	$726$ $-:3$	Divide both sides by $3$
$x$	$=$	$$242$	James’ daily earnings

Solve for

$x-20$

	$x-20$
$=$	$242-20$	Substitute $x$
$=$	$$222$	Tom’s daily earnings

Solve for

$x+27$

	$x+27$
$=$	$242+27$	Substitute $x$
$=$	$$269$	Bob’s daily earnings

James:

$$242$

Tom:

$$222$

Bob:

$$269$

Question 7 of 7

7. Question

Zoe has a certain number of

$10¢$ coins and

$4$ times that number are her

$50¢$ coins. The total value of all her coins is

$$37.80$ . How many of each coin does she have?

number of $10¢$ coins: (18)

number of $50¢$ coins: (72)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of

$10¢$ coins:

$n$

Translate the problem into an equation based on the diagram, then make sure all units are the same

$10¢(n)+50¢(4n)$	$=$	$$37.80$
$10¢(n)+50¢(4n)$	$=$	$3780¢$

Solve for

$n$

$10¢(n)+50¢(4n)$	$=$	$3780¢$
$10n+200n$	$=$	$3780$
$210n$	$=$	$3780$
$210n$ $-:210$	$=$	$3780$ $-:210$	Divide both sides by $210$
$n$	$=$	$18$	number of $10¢$ coins

Solve for

$4n$

	$4n$
$=$	$4(18)$	Substitute $n$
$=$	$72$	number of $50¢$ coins

number of

$10¢$ coins:

$18$

number of

$50¢$ coins:

$72$

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