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Zero Powers 1

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Question 1 of 4

1. Question
Simplify

$3 x^{0}$ $3x^0$
- (3)
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Power of Zero

$\color{#A57200}{a^0}=\color{#A57200}{1}$

Apply the Power of Zero, then simplify.

$3\color{#A57200}{x^0}2$

$=$ $=$ $3 \times \color{#A57200}{1}$ $a^{0} = 1$ $a^0 =1$

$=$ $=$ $3$ $3$

$3$ $3$
Question 2 of 4

2. Question
Simplify

${(453)}^{0}$ $(453)^0$
- (1)
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Power of Zero

$\color{#A57200}{a^0}=\color{#A57200}{1}$

Apply the Power of Zero, then simplify.

$(453)^0$

$=$ $=$ $453^{1 \times 0}$

$=$ $=$ $\color{#A57200}{453^0}$

$=$ $=$ $\color{#A57200}{1}$ $a^{0} = 1$ $a^0 =1$

$1$ $1$
Question 3 of 4

3. Question
Simplify

${(3 a^{0})}^{2}$ $(3a^0)^2$
- (9)
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Power of Zero

$\color{#A57200}{a^0}=\color{#A57200}{1}$

Apply the Power of Zero, then simplify.

${(3\color{#A57200}{a^0})}^2$

$=$ $=$ ${(3 \times \color{#A57200}{1})}^2$ $a^{0} = 1$ $a^0 =1$

$=$ $=$ $3^{2}$ $3^2$

$=$ $=$ $9$ $9$

$9$ $9$
Question 4 of 4

4. Question
Simplify

${(7 y^{0})}^{2}$ $(7y^0)^2$
- (49)
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Power of Zero

$\color{#A57200}{a^0}=\color{#A57200}{1}$

Apply the Power of Zero, then simplify.

$(7\color{#A57200}{y^0})^2$

$=$ $=$ $(7 \times \color{#A57200}{1})^2$ $a^{0} = 1$ $a^0 =1$

$=$ $=$ ${(7)}^{2}$ $(7)^2$

$=$ $=$ $49$ $49$

$49$ $49$