Find the Hypotenuse 2
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Question 1 of 4
1. Question
Find the hypotenuse of this triangle.
- (15) cm
Hint
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Fantastic!
Incorrect
Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=x``a=9` cm`b=12` cm$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{x}}^2$$ `=` $${\color{#9a00c7}{9}}^2 + {\color{#007DDC}{12}}^2$$ `x^2` `=` `81+144` `x^2` `=` `225` `sqrt(x^2)` `=` `sqrt225` Get the square root of both sides `x` `=` `15` cm `15` cm -
Question 2 of 4
2. Question
Find the hypotenuse of this triangle.
- (50) m
Hint
Help VideoCorrect
Excellent!
Incorrect
Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=t``a=14` m`b=48` m$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{t}}^2$$ `=` $${\color{#9a00c7}{14}}^2 + {\color{#007DDC}{48}}^2$$ `t^2` `=` `196+2304` `t^2` `=` `2500` `sqrt(t^2)` `=` `sqrt2500` Get the square root of both sides `t` `=` `50` m `50` m -
Question 3 of 4
3. Question
Find the hypotenuse of this triangle.
- (73) mm
Hint
Help VideoCorrect
Nice Job!
Incorrect
Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=t``a=48` mm`b=55` mm$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{t}}^2$$ `=` $${\color{#9a00c7}{48}}^2 + {\color{#007DDC}{55}}^2$$ `t^2` `=` `2304+3025` `t^2` `=` `5329` `sqrt(t^2)` `=` `sqrt5329` Get the square root of both sides `t` `=` `73` mm `73` mm -
Question 4 of 4
4. Question
Solve for `y`.
Round off answer to `1` decimal place- (12.8)cm
Hint
Help VideoCorrect
Fantastic!
Incorrect
Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=y``a=8` cm`b=10` cm$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{y}}^2$$ `=` $${\color{#9a00c7}{8}}^2 + {\color{#007DDC}{10}}^2$$ `y^2` `=` `64+100` `y^2` `=` `164` `sqrt(y^2)` `=` `sqrt164` Get the square root of both sides `y` `=` `12.8062` cm `y` `=` `12.8` cm Round off to `1` decimal place `12.8` cm