Find a Side 3
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Question 1 of 3
1. Question
Solve for `x`.
Round off answer to `1` decimal place- (7.5)cm
Hint
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Excellent!
Incorrect
Finding a Side
Use $$\large\textbf{-}$$
$${\color{#9a00c7}{a}}^2={\color{#00880a}{c}}^2 \hspace{1mm} \large\textbf{-} \hspace{1mm} \normalsize{\color{#007DDC}{b}}^2$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem (side).
`c=19.5` cm`a=x``b=18` cm$${\color{#9a00c7}{a}}^2$$ `=` $${\color{#00880a}{c}}^2-{\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#9a00c7}{x}}^2$$ `=` $${\color{#00880a}{19.5}}^2-{\color{#007DDC}{18}}^2$$ `x^2` `=` `380.25-324` `x^2` `=` `56.25` `sqrt(x^2)` `=` `sqrt56.25` Get the square root of both sides `x` `=` `7.5` cm `7.5` cm -
Question 2 of 3
2. Question
Solve for `x`.
Round off answer to `2` decimal places- (24.91)m
Hint
Help VideoCorrect
Keep Going!
Incorrect
Finding a Side
Use $$\large\textbf{-}$$
$${\color{#9a00c7}{a}}^2={\color{#00880a}{c}}^2 \hspace{1mm} \large\textbf{-} \hspace{1mm} \normalsize{\color{#007DDC}{b}}^2$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem (side).
`c=30.5` m`a=x``b=17.6` m$${\color{#9a00c7}{a}}^2$$ `=` $${\color{#00880a}{c}}^2-{\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#9a00c7}{x}}^2$$ `=` $${\color{#00880a}{30.5}}^2-{\color{#007DDC}{17.6}}^2$$ `x^2` `=` `930.25-309.76` `x^2` `=` `620.49` `sqrt(x^2)` `=` `sqrt620.49` Get the square root of both sides `x` `=` `24.9096…` cm `x` `=` `24.91` m Round off to `2` decimal places `24.91` m -
Question 3 of 3
3. Question
Solve for `y`.
Round off answer to `2` decimal places- (10.33)m
Hint
Help VideoCorrect
Great Work!
Incorrect
Finding a Side
Use $$\large\textbf{-}$$
$${\color{#9a00c7}{a}}^2={\color{#00880a}{c}}^2 \hspace{1mm} \large\textbf{-} \hspace{1mm} \normalsize{\color{#007DDC}{b}}^2$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem (side).
`c=17` m`a=y``b=13.5` m$${\color{#9a00c7}{a}}^2$$ `=` $${\color{#00880a}{c}}^2-{\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#9a00c7}{y}}^2$$ `=` $${\color{#00880a}{17}}^2-{\color{#007DDC}{13.5}}^2$$ `y^2` `=` `289-182.25` `y^2` `=` `106.75` `sqrt(y^2)` `=` `sqrt106.75` Get the square root of both sides `y` `=` `10.3319` m `x` `=` `10.33` m Round off to `2` decimal places `10.33` m