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Question 1 of 6
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Imaginary numbers has the property i 2 = - 1 .
To solve 6 1 + i , multiply the numerator and the denominator by the conjugate of the denominator and then simplify. The conjugate of 6 1 + i is 1 - i .
6 1 + i
Multiply the numerator and the denominator by the conjugate 1 - i .
=
6 1 + i × 1 - i 1 - i
=
6 - 6 i 1 - i + i - i 2
Combine like terms - i and i .
=
6 - 6 i 1 - i 2
Remember that i 2 = - 1 .
=
6 - 6 i 1 - ( - 1 )
Simplify
=
6 - 6 i 2
Divide both terms in the numerator by 2 .
=
3 - 3 i
Question 2 of 6
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Imaginary numbers has the property i 2 = - 1 .
To solve - 7 - 3 i 4 i , multiply the numerator and the denominator by i and then simplify.
- 7 - 3 i 4 i
Multiply the numerator and the denominator by i .
=
- 7 - 3 i 4 i × i i
=
- 7 i - 3 i 2 4 i 2
Remember that i 2 = - 1 .
=
- 7 i - 3 ( - 1 ) 4 ( - 1 )
Simplify
=
- 7 i + 3 - 4
Divide both terms in the numerator by - 4 .
=
7 4 i - 3 4
Reverse the order of the terms. The term with the i should be the second term.
=
- 3 4 + 7 4 i
Question 3 of 6
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Imaginary numbers has the property i 2 = - 1 .
To solve i 1 - 3 i , multiply the numerator and the denominator by the conjugate of the denominator and then simplify. The conjugate of i 1 - 3 i is 1 + 3 i .
i 1 - 3 i
Multiply the numerator and the denominator by the conjugate 1 + 3 i .
=
i 1 - 3 i × 1 + 3 i 1 + 3 i
=
i + 3 i 2 1 2 – ( 3 i ) 2
Take the square of ( 3 i ) 2 .
=
i + 3 i 2 1 – 9 i 2
Remember that i 2 = - 1 .
=
i - 3 1 + 9
Simplify
=
i 10 - 3 10
Divide both terms in the numerator by 10 .
=
- 3 10 + i 10
Rearrange.
Question 4 of 6
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Imaginary numbers has the property i 2 = - 1 .
To solve - 7 - 2 i 5 i , multiply the numerator and the denominator by the conjugate of the denominator and then simplify. The conjugate of - 7 - 2 i 5 i is i .
- 7 - 2 i 5 i
Multiply the numerator and the denominator by the conjugate i .
=
- 7 - 2 i 5 i × i i
=
- 7 i - 2 i 2 5 i 2
Remember that i 2 = - 1 .
=
- 7 i + 2 - 5
Divide both terms in the numerator by - 5 .
=
- 7 i - 5 + 2 - 5
Rearrange.
=
2 - 5 – 7 i - 5
Simplify.
=
- 2 5 + 7 i 5
Question 5 of 6
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Imaginary numbers has the property i 2 = - 1 .
To solve 5 - 9 i 1 + i , multiply the numerator and the denominator by the conjugate of the denominator and then simplify. The conjugate of 5 - 9 i 1 + i is 1 - i .
5 - 9 i 1 + i
Multiply the numerator and the denominator by the conjugate 1 - i .
=
5 - 5 i - 9 i + 9 i 2 1 2 - i 2
Remember that i 2 = - 1 .
=
5 - 5 i - 9 i - 9 1 + 1
Combine the terms with i .
=
5 - 14 i - 9 1 + 1
Combine the real numbers.
=
- 4 - 14 i 2
Divide both terms in the numerator by 2 .
=
- 4 2 - 14 i 2
Simplify.
=
- 2 - 7 i
Question 6 of 6
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Imaginary numbers has the property i 2 = - 1 .
To solve 2 + 3 i 3 + 2 i , multiply the numerator and the denominator by the conjugate of the denominator and then simplify. The conjugate of 2 + 3 i 3 + 2 i is 3 - 2 i .
2 + 3 i 3 + 2 i
Multiply the numerator and the denominator by the conjugate 3 - 2 i .
=
`(2+3i)/(3+2i)timescolor(red)(3-2i)/color(red)(3-2i)
=
6 - 4 i + 9 i - 6 i 2 3 2 - ( 2 i ) 2
Take the square of ( 2 i ) 2 and 3 2 .
=
6 - 4 i + 9 i - 6 i 2 9 - 4 i 2
Remember that i 2 = - 1 .
=
6 - 4 i + 9 i + 6 9 + 4
Combine the terms with i .
=
6 + 5 i + 6 9 + 4
Combine all real numbers.
=
12 + 5 i 13
Divide both terms in the numerator by 13 .
=
12 13 + 5 i 13