Time and Travelling Word Problems 1

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Question 1 of 5

1. Question
A plane departs from Hanoi, Vietnam and is on its way to arrive in Sydney. Find its time of arrival given the following:

Sydney $(34°S,151°E)$

Hanoi $(21°N,106°E)$

Departure: $8:30$ pm Tuesday

Flight Time: $9$ hours $20$ minutes
- 1. $8:50$ am Wednesday
- 2. $2:50$ am Wednesday
- 3. $11:30$ pm Tuesday
- 4. $9:30$ am Wednesday
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The prime meridian is a line of longitude at $0°$

On the opposite side of the prime meridian lies the $180°$ meridian.

Finding the Time Difference

$1°$ of longitude to the west $=$ subtract 4 minutes (West = lest)

$1°$ of longitude to the east $=$ add 4 minutes (East = beast)

First, find the local time in Sydney when the time in Hanoi is $8:30$ pm

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This line represents a minus sign, which means we must get the difference between the two longitudes

We find the difference because both cities are on one side of $UTC$

$151°-106°$ $=$ $45°$

Next, multiply by $4$ to solve for the time difference

Since $1°=4$ minutes

$45°$ $xx4$ $=$ $180$ minutes

Since Sydney is to the east of Hanoi, add $180$ minutes to $8:30$ pm

$8:30$ pm $+180$ minutes

$=$ $8:30$ pm $+3$ hours Divide minutes by $60$ to convert to hours

$=$ $11:30$ pm

When it is $8:30$ pm in Hanoi, at the same moment, it is $11:30$ pm in Sydney

Finally, add the flight time to $11:30$ pm to get the time of arrival in Sydney

Flight time: $9$ hours $20$ minutes

$11:30$ pm $+9$ hours $20$ minutes

$=$ $23:30+9$ hours $20$ minutes Convert to military time by adding $12$

$=$ $32:50$

Since it is greater than $24$ , it means a day has passed and the time of arrival is on Wednesday

Subtract $24$ hours to get a normal time format

$32:50-24$ hours

$=$ $8:50$ am

The time of arrival in Sydney is $8:50$ am Wednesday

$8:50$ am, Wednesday
Question 2 of 5

2. Question
A plane departs from San Francisco and is on its way to arrive in Dallas. Find its time of arrival given the following:

Dallas $(32°N,96°W)$

San Francisco $(37°N,122°W)$

Departure: $10$ am

Flight Time: $3$ hours $30$ minutes
- 1. $10:16$ pm
- 2. $05:20$ am
- 3. $03:30$ am
- 4. $03:14$ pm
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The prime meridian is a line of longitude at $0°$

On the opposite side of the prime meridian lies the $180°$ meridian.

Finding the Time Difference

$1°$ of longitude to the west $=$ subtract 4 minutes (West = lest)

$1°$ of longitude to the east $=$ add 4 minutes (East = beast)

First, find the local time in Dallas when the time in San Francisco is $10$ am

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This line represents a minus sign, which means we must get the difference between the two longitudes

We find the difference because both cities are on one side of $UTC$

$122°-96°$ $=$ $26°$

Next, multiply by $4$ to solve for the time difference

Since $1°=4$ minutes

$26°$ $xx4$ $=$ $104$ minutes

Since Dallas is to the east of San Francisco, add $104$ minutes to $10$ am

$10$ am $+104$ minutes

$=$ $10$ am $+1$ hour $44$ minutes Divide minutes by $60$ to convert to hours

$=$ $11:44$ am

When it is $10$ am in San Francisco, at the same moment, it is $11:44$ am in Dallas

Finally, add the flight time to $11:44$ am to get the time of arrival in Dallas

Flight time: $3$ hours $30$ minutes

$11:44$ am $+3$ hours $30$ minutes

$=$ $11°44°+03°30°$ Press the DMS button for every $°$

$=$ $15°14’$

$=$ $15:14$

The time is in pm or in the afternoon since it is greater than $12$ .

Subtract $12$ hours to get a proper time format

$15:14-12$ hours

$=$ $03:14$ pm

The plane arrived in Dallas at $03:14$ pm

$03:14$ pm

Question 3 of 5

A plane departs from Melbourne and is on its way to arrive in Honolulu. Find its time of arrival given the following:

Honolulu

$(158°W)$

Melbourne

$(145°E)$

Departure:

$5:30$ pm Saturday

Flight Time:

$10$ hours

$30$ minutes

1. $7:48$ am Sunday
2. $7:18$ pm Friday
3. $7:48$ pm Friday
4. $7:48$ am Saturday

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The prime meridian is a line of longitude at

$0°$

On the opposite side of the prime meridian lies the $180°$ meridian.

Finding the Time Difference

$1°$ of longitude to the west

$=$ subtract 4 minutes (West = lest)

$1°$ of longitude to the east

$=$ add 4 minutes (East = beast)

First, find the local time in Honolulu when the time in Melbourne is

$5:30$ pm

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This represents a plus sign, which means we must get the sum of the two longitudes

We find the sum because both cities are on either side of

$UTC$

$158°+145°$

$=$

$303°$

Next, multiply by

$4$ to solve for the time difference

Since

$1°=4$ minutes

$303°$

$xx4$

$=$

$1212$ minutes

Since Honolulu is to the west of Melbourne, subtract

$1212$ minutes from

$5:30$ pm

	$5:30$ pm $-1212$ minutes
$=$	$17:30-20$ hours $12$ minutes	Divide minutes by $60$ to convert to hours
$=$	$17°30°-20°12°$	Press the DMS button for every $°$
$=$	$-2°42’$

Since the answer is negative, it means the time we are looking for occurs the day before which is Friday

Simply add

$24$ hours to convert it to military time

		$-2°42’+24°$
	$=$	$21°18’$
	$=$	$09:18$ pm

When it is

$5:30$ pm Saturday in Melbourne, at the same moment, it is

$9:18$ pm Friday in Honolulu

Finally, add the flight time to

$9:18$ pm to get the time of arrival in Honolulu

Flight time:

$10$ hours

$30$ minutes

	$09:18$ pm $+10$ hours $30$ minutes
$=$	$21°18°+10°30°$	Press the DMS button for every $°$
$=$	$31°48’$

Since it is greater than

$24$ , it means a day has passed and the time of arrival is on Saturday

Subtract

$24$ hours to get a normal time format

		$31°48′-24°$
	$=$	$7:48$ am

The time of arrival in Honolulu is $7:48$ am Saturday

$7:48$ am Saturday

Question 4 of 5

A rally car departs from Perth and is on its way to Sydney. Find its time of arrival given the following:

Sydney

$(151°E)$

Perth

$(116°E)$

Departure:

$9$ am Saturday

Travel Time:

$85$ hours

1. $08:20$ pm Tuesday
2. $08:00$ am Monday
3. $12:20$ am Wednesday
4. $01:20$ am Tuesday

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The prime meridian is a line of longitude at

$0°$

On the opposite side of the prime meridian lies the $180°$ meridian.

Finding the Time Difference

$1°$ of longitude to the west

$=$ subtract 4 minutes (West = lest)

$1°$ of longitude to the east

$=$ add 4 minutes (East = beast)

First, find the local time in Sydney when the time in Perth is

$9$ am

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This line represents a minus sign, which means we must get the difference between the two longitudes

We find the difference because both cities are on one side of

$UTC$

$151°-116°$

$=$

$35°$

Next, multiply by

$4$ to solve for the time difference

Since

$1°=4$ minutes

$35°$

$xx4$

$=$

$140$ minutes

Since Sydney is to the east of Perth, add

$140$ minutes to

$9$ am

	$9$ am $+140$ minutes
$=$	$9$ am $+2$ hours $20$ minutes	Divide minutes by $60$ to convert to hours
$=$	$11:20$ am

When it is

$9$ am in Perth, at the same moment, it is

$11:20$ am in Sydney

Finally, add the time to

$11:20$ am to get the time of arrival in Sydney

Flight time:

$85$ hours

	$11:20$ am $+85$ hours
	$11:20$ am $+3$ days $13$ hours	$1$ day is $24$ hours
	$11:20$ am $+13$ hours, Tuesday
$=$	$11°20°+13°$ , Tuesday	Press the DMS button for every $°$
$=$	$24°20′,$ Tuesday

Since it is greater than

$24$ , it means another day has passed and the time of arrival is on Wednesday

Subtract

$24$ hours to get a normal time format

		$24°20′-24°$
	$=$	$0:20$
	$=$	$12:20$ am

The time of arrival in Sydney is $12:20$ am Wednesday

$12:20$ am Wednesday

Question 5 of 5

A plane departed from Beijing and has arrived in London. Find the flight time of the plane given the following:

Beijing

$(116°E)$ Departure:

$6$ pm

London

$(0°E)$ Arrival:

$9:16$ pm

(11) hours

Time and Travelling Word Problems 1

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Quiz summary

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1. Question

Hint

Great Work!

Finding the Time Difference

2. Question

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Correct!

Finding the Time Difference

3. Question

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Keep Going!

Finding the Time Difference

4. Question

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Fantastic!

Finding the Time Difference

5. Question

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Excellent!

Finding the Time Difference

Quizzes

	$8:30$ pm $+180$ minutes
$=$	$8:30$ pm $+3$ hours	Divide minutes by $60$ to convert to hours
$=$	$11:30$ pm

	$11:30$ pm $+9$ hours $20$ minutes
$=$	$23:30+9$ hours $20$ minutes	Convert to military time by adding $12$
$=$	$32:50$

	$10$ am $+104$ minutes
$=$	$10$ am $+1$ hour $44$ minutes	Divide minutes by $60$ to convert to hours
$=$	$11:44$ am

	$11:44$ am $+3$ hours $30$ minutes
$=$	$11°44°+03°30°$	Press the DMS button for every $°$
$=$	$15°14’$
$=$	$15:14$

	$6$ pm $-464$ minutes
$=$	$6$ pm $-7$ hours $44$ minutes	Divide minutes by $60$ to convert to hours
$=$	$18°00°-07°44°$	Press the DMS button for every $°$
$=$	$10°16’$
$=$	$10:16$ am

	$09:16$ pm $-10:16$ am
$=$	$21°16°-10°16°$	Press the DMS button for every $°$
$=$	$11°00’$
$=$	$11$ hours

		$32:50-24$ hours
	$=$	$8:50$ am

		$15:14-12$ hours
	$=$	$03:14$ pm