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Question 1 of 2
Find the integral
∫π2π4cosxdx
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Integrals of Trigonometric Functions
First, integrate the trigonometric function
∫π2π4cosxdx |
= |
[sinx]π2π4 |
Integrate cosx |
Finally, get the difference of the upper and lower limits substituted to the integral as x.
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[sinx]π2π4 |
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|
= |
sinπ2−sinπ4 |
Substitute the limits |
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|
= |
1-1√2 |
Evaluate |
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Question 2 of 2
Find the integral
∫π303sinx2dx
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Integrals of Trigonometric Functions
First, integrate the trigonometric function
∫π30sinx2dx |
= |
[3(−cosx2)]π30 |
Integrate 3sin x2 |
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|
= |
[−6cosx2]π30 |
Simplify |
Finally, get the difference of the upper and lower limits substituted to the integral as x.
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[−6cosx2]π30 |
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|
= |
−6cosπ32−[−6cos02] |
Substitute the limits |
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= |
-6 cos(π6)+(6⋅1) |
Evaluate |
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= |
-6⋅√32+6 |
cos π6=√32 |
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|
= |
-3√3+6 |
Simplify |