Intro to Sequences
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Question 1 of 6
1. Question
Given the sequence 1+5+9…, find:(i) The common difference(ii) The 11th term-
(i) d= (4)(ii) U11= (41)
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Common Difference Formula
d=U2−U1=U3−U2General Rule of an Arithmetic Sequence
Un=a+[(n−1)d](i) Finding the common differenceFirst, identify the consecutive valuesU1 = 1 U2 = 5 U3 = 9 Next, use the formula to solve for the common differenced = U2-U1 = 5-1 Substitute known values = 4 (ii) Finding the 10th termSubstitute the known values to the general ruleNumber of terms[n] = 11 First term[a] = 1 Common Difference[d] = 4 Un = a+[(n−1)d] U11 = 1+[(11−1)4] Substitute known values = 1+[(10)4] Evaluate = 41 (i) d=4(ii) U11=41 -
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Question 2 of 6
2. Question
Given the sequence 87,83,79,75…, find:(i) If the expression is an arithmetic sequence(ii) The general rule form(iii) The 38th term(iv) If -132 is part of the sequenceFor part i and iv, write Y for yes and N for no-
(i) (Y, y)(ii) Un= (91-4n)(iii) U38= (-61)(iv) (N, n)
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Common Difference Formula
d=U2−U1=U3−U2General Rule of an Arithmetic Sequence
Un=a+[(n−1)d](i) Finding if the expression is an arithmetic sequenceFirst, identify the consecutive valuesU1 = 1 U2 = 5 U3 = 9 Next, use the formula to solve for the common difference and check if it is consistent with the consecutive valuesd = U2-U1 = 83-87 Substitute known values = -4 d = U3-U2 = 79-83 Substitute known values = -4 d = U4-U3 = 75-79 Substitute known values = -4 The common difference is consistent. Therefore, the expression is an arithmetic sequence.(ii) Finding the general rule formSubstitute the known values to the general ruleNumber of terms[n] = n First term[a] = 87 Common Difference[d] = -4 Un = a+[(n−1)d] Un = 87+[(n−1)−4] Substitute known values = 87-4n+4 Distribute = 91-4n (iii) Finding the 38th termUse the answer from part ii to find the 38th termUn = 91-4n U38 = 91-4(38) Substitute known values = 91-152 Evaluate = -61 (iv) Finding if -132 is part of the sequenceUse the answer from part ii and have Un=-132. Then solve for nUn = 91-4n -132 = 91-4n Substitute Un=-132 -132 -91 = 91-4n -91 Subtract 91 from both sides -223 ÷(-4) = -4n ÷(-4) Divide both sides by -4 55.75 = n n = 55.75 The value of n is not a whole integer. Therefore, -132 is not part of the sequence(i) Yes(ii) Un=91-4n(iii) U38=-61(iv) No -
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Question 3 of 6
3. Question
Given the expression Un=5n+2, find:(i) The common difference(ii) The 10th term-
(i) d= (5)(ii) U10= (52)
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Common Difference Formula
d=U2−U1=U3−U2(i) Finding the common differenceFirst, substitute consecutive values to nUn = 5n+2 U1 = 5(1)+2 = 7 U2 = 5(2)+2 = 12 U3 = 5(3)+2 = 17 U4 = 5(4)+2 = 22 Next, use the formula to solve for the common differenced = U2-U1 = 12-7 Substitute known values = 5 (ii) Finding the 10th termSimply substitute 10 to nUn = 5n+2 U10 = 5(10)+2 Substitute n=10 = 52 (i) d=5(ii) U10=52 -
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Question 4 of 6
4. Question
Find the 18th term92,77,62,47…- U18= (-163)
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Common Difference Formula
d=U2−U1=U3−U2General Rule of an Arithmetic Sequence
Un=a+[(n−1)d]First, solve for the value of d.d = U2−U1 = 77-92 Substitute the first and second term = -15 Next, substitute the known values to the general ruleNumber of terms[n] = 18 First term[a] = 92 Common Difference[d] = -15 Un = a+[(n−1)d] U18 = 92+[(18−1)−15] Substitute known values = 92+[17⋅(-15)] Evaluate = 92-255 = -163 U18=-163 -
Question 5 of 6
5. Question
Find the first positive term1047-1012-977…- First positive term = (3)
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Common Difference Formula
d=U2−U1=U3−U2General Rule of an Arithmetic Sequence
Un=a+[(n−1)d]First, solve for the value of d.d = U2−U1 = -1012-(-1047) Substitute the first and second term = 35 Next, transform the sequence into general rule formNumber of terms[n] = n First term[a] = -1047 Common Difference[d] = 35 Un = a+[(n−1)d] Un = −1047+[(n−1)35] Substitute known values = -1047+35n-35 Distribute = 35n-1082 Next, use the general rule form and solve for the value of n that is greater than 035n-1082 > 0 35n-1082 +1082 > 0 +1082 Add 1082 to both sides 35n ÷35 > 1082 ÷35 Divide both sides by 35 n = 31 Rounded to a whole number Therefore, the first positive term would be the 31st termFinally, use the general rule form to find the value of the 31st termU31 = 35(31)−1082 Substitute known values = 1085-1082 Evaluate = 3 U31=3 -
Question 6 of 6
6. Question
Find the 10th term given that:U3=16U12=61- U10= (51)
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General Rule of an Arithmetic Sequence
Un=a+[(n−1)d]First, transform the 3rd and 12th terms into general rule form3rd TermUn = a+[(n−1)d] U3 = a+[(3−1)d] Substitute known values 16 = a+2d Distribute 12th TermUn = a+[(n−1)d] U12 = a+[(12−1)d] Substitute known values 61 = a+11d Distribute Next, solve for the value of d by subtracting the 3rd term’s general rule form from the 12th term’s general rule form61-16 = (a+2d)-(a+11d) 45÷9 = 9d÷9 Divide both sides by 9 5 = d d = 5 Next, substitute d to one of the general rule forms to solve for a16 = a+2d 16 = a+2(5) Substitute d=5 16 -10 = a+10 -10 Subtract 10 from both sides 6 = a a = 6 Finally, substitute the known values to the general rule to find the 10th termNumber of terms[n] = 10 First term[a] = 6 Common Difference[d] = 5 Un = a+[(n−1)d] U10 = 6+[(10−1)5] Substitute known values = 6+(9⋅5) Evaluate = 6+45 = 51 U10=51