To confirm that 44 is less thanxx, substitute x=5x=5 to the original inequality
11+x11+x
>>
1515
11+11+55
>>
1515
Substitute x=5x=5
1616
>>
1515
Since the inequality is true, the representation is correct
xx>>44
Question 2 of 5
2. Question
Donald has saved $700$700 for one-on-one tennis coaching. A coach recommends 2020 hours of coaching. Write an inequality for the possible hourly rate that Donald could afford to pay for the coaching.
Recommended hours of training=20Recommended hours of training=20
Rate per hour=rRate per hour=r
First, form an inequality from the problem
Since we know that Donald can only pay a maximum of $700$700 for 2020 hours of training, the amount he can pay hourly can only be less than or equal to a certain amount.
Hence, the inequality can be written as:
700r700r
≤≤
201201
Next, make sure that only rr is on the left side
700r700r
≤≤
201201
20r20r
≤≤
700700
Cross multiply
20r20r÷20÷20
≤≤
700700÷20÷20
Divide both sides by 2020
rr
≤≤
3535
r≤35r≤35
Question 3 of 5
3. Question
The perimeter of this triangle must be no more than 75.8 cm. Find an expression that represents all possible xx values.
The perimeter of a triangle is the sum of all sides.
First, form an inequality from the problem
The perimeter of the triangle
must be no more than
75.875.8
19.1+31.6+x19.1+31.6+x
≤≤
75.875.8
Next, make sure that only xx is on the left side
19.1+31.6+x19.1+31.6+x
≤≤
75.875.8
50.750.7+x+x
≤≤
75.875.8
Combine like terms
50.7+x50.7+x-50.7−50.7
≤≤
75.875.8-50.7−50.7
Subtract 50.750.7 from both sides
xx
≤≤
25.125.1
x≤25.1x≤25.1
Question 4 of 5
4. Question
The total maximum weight of luggage on a first-class international flight is 5050 kg per person. If Lucy has three suitcases and the first suitcase weighs 1717 kg and the second weighs 1515 kg, how much will the third bag weigh?
Maximum weight of luggage=50kgMaximum weight of luggage=50kg
Weight of first bag=17kgWeight of first bag=17kg
Weight of second bag=15kgWeight of second bag=15kg
Weight of third bag=xWeight of third bag=x
First, form an inequality from the problem
Since the maximum weight of luggage Lucy can bring is 5050 kg, the total weight of all her bags must be less than or equal to5050 kg.
Hence, the inequality can be written as:
17+15+x17+15+x
≤≤
5050
Next, make sure that only xx is on the left side
17+15+x17+15+x
≤≤
5050
32+x32+x
≤≤
5050
Combine like terms
32+x32+x-32−32
≤≤
5050-32−32
Subtract 3232 from both sides
xx
≤≤
1818
x≤18x≤18
Question 5 of 5
5. Question
Jane has $85$85 to spend with her friends. They ordered $33$33 worth of pizzas, $11$11 worth of bread and $17$17 on drinks. How much can Jane spend on desserts?