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Interpret Frequency Tables 2Interpret Frequency Tables 2
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Question 1 of 8
1. Question
Complete the frequency distribution table and find the mode.Score `(x)` Frequency `(f)` 8 2 9 3 10 7 11 4 12 8 13 2 14 1 - `\text(Mode )=` (12)
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The mode is the value that appears most often in a set of data.Notice that the highest value in the Frequency column is `8` and it corresponds to `12`.Score `(x)` Frequency `(f)` 8 2 9 3 10 7 11 4 12 8 13 2 14 1 In other words, the score `12` occurs the most frequently, and is therefore the mode.`\text(Mode)=12` -
Question 2 of 8
2. Question
Find the mean of the following frequency distribution table.Score `(x)` Tally Frequency `(f)` 0 6 1 10 2 6 3 4 4 3 5 0 6 1 `\text(Total) =30` Round your answer to two decimal places.- `\text(Mean )=` (1.73)
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Mean Formula
$$\text{Mean}=\frac{\color{#314EC4}{\sum f⋅x}}{\color{#9202AA}{\sum f}}$$A frequency distribution table displays how many times a particular score has occurred in a set of data.Add an `f⋅x` column to the table. Fill it in by multiplying `x` and `f` on each row.Score `(x)` Tally Frequency `(f)` `f⋅x` 0 6 0 1 10 10 2 6 12 3 4 12 4 3 12 5 0 0 6 1 6 `\text(Total) =30` Find the sum of the `f⋅x` column.`sum f⋅x` `=` `0+10+12+12+12+0+6` `=` `52` Score `(x)` Tally Frequency `(f)` `f⋅x` 0 6 0 1 10 10 2 6 12 3 4 12 4 3 12 5 0 0 6 1 6 `\text(Total) =30` `\text(Total) =52` Use the formula to compute for the mean.`\text(Mean)` `=` $$\frac{\color{#314EC4}{\sum f⋅x}}{\color{#9202AA}{\sum f}}$$ Mean Formula `\text(Mean)` `=` $$\frac{\color{#314EC4}{52}}{\color{#9202AA}{30}}$$ Substitute values `\text(Mean)` `=` `1.73` Rounded to two decimal places `\text(Mean)=1.73` -
Question 3 of 8
3. Question
Find the mode of the frequency distribution table.Goals in a Hockey Game Goals `(x)` Frequency `(f)` 3 4 5 5 6 1 7 5 10 1 - `\text(Mode )=` (5, 7) and (7, 5)
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The mode is the value that appears most often in a set of data.Notice that the highest value in the Frequency column is `5` and it corresponds to both `5` and `7`.Goals `(x)` Frequency `(f)` 3 4 5 5 6 1 7 5 10 1 In other words, the scores `5` and `7` occur the most frequently, and are therefore the modes.`\text(Mode)=5` and `7` -
Question 4 of 8
4. Question
Complete the frequency distribution table and find the mean.Score `(x)` Frequency `(f)` `f⋅x` 8 2 9 3 10 7 11 4 12 8 13 2 14 1 Round your answer to two decimal places.- `\text(Mean )=` (10.85)
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Mean Formula
$$\text{Mean}=\frac{\color{#314EC4}{\sum f⋅x}}{\color{#9202AA}{\sum f}}$$A frequency distribution table displays how many times a particular score has occurred in a set of data.To complete the table, fill in the `f⋅x` column by multiplying `x` and `f` on each row.Score `(x)` Frequency `(f)` `f⋅x` 8 2 16 9 3 27 10 7 70 11 4 44 12 8 96 13 2 26 14 1 14 Find the sum of both the Frequency and `f⋅x` columns.`sum f` `=` `2+3+7+4+8+2+1` `=` `27` `sum f⋅x` `=` `16+27+70+44+96+26+14` `=` `293` Score `(x)` Frequency `(f)` `f⋅x` 8 2 16 9 3 27 10 7 70 11 4 44 12 8 96 13 2 26 14 1 14 `\text(Total) =27` `\text(Total) =293` Use the formula to compute for the mean.`\text(Mean)` `=` $$\frac{\color{#314EC4}{\sum f⋅x}}{\color{#9202AA}{\sum f}}$$ Mean Formula `\text(Mean)` `=` $$\frac{\color{#314EC4}{293}}{\color{#9202AA}{27}}$$ Substitute values `\text(Mean)` `=` `10.85` Rounded to two decimal places `\text(Mean)=10.85` -
Question 5 of 8
5. Question
Find the mode of the frequency distribution table.Adult Male Heights Inches `(x)` Frequency `(f)` 65 1 70 3 71 4 75 1 - `\text(Mode )=` (71)
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The mode is the value that appears most often in a set of data.Notice that the highest value in the Frequency column is `4` and it corresponds to `71`.Inches `(x)` Frequency `(f)` 65 1 70 3 71 4 75 1 In other words, the score `71` occurs the most frequently, and is therefore the mode.`\text(Mode)=71` -
Question 6 of 8
6. Question
Complete the frequency distribution table and find the mode.Score `(x)` Frequency `(f)` 8 3 9 4 10 8 11 2 12 11 13 3 14 10 - `\text(Mode )=` (12)
Hint
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Incorrect
The mode is the value that appears most often in a set of data.Notice that the highest value in the Frequency column is `11` and it corresponds to `12`.Score `(x)` Frequency `(f)` 8 3 9 4 10 8 11 2 12 11 13 3 14 10 In other words, the score `12` occurs the most frequently, and is therefore the mode.`\text(Mode)=12` -
Question 7 of 8
7. Question
Find the mean of the following frequency distribution table.Score `(x)` Frequency `(f)` 3 2 5 3 6 4 7 1 10 1 12 1 15 2 18 1 Round your answer to two decimal places.- `\text(Mean )=` (8.13)
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Mean Formula
$$\text{Mean}=\frac{\color{#314EC4}{\sum f⋅x}}{\color{#9202AA}{\sum f}}$$A frequency distribution table displays how many times a particular score has occurred in a set of data.Add an `f.x` column to the table. Fill it in by multiplying `x` and `f` on each row.Score `(x)` Frequency `(f)` `f⋅x` 3 2 6 5 3 15 6 4 24 7 1 7 10 1 10 12 1 12 15 2 30 18 1 18 Find the sum of both the Frequency and `f.x` columns.`sum f` `=` `2+3+4+1+1+1+2+1` `=` `15` `sum f.x` `=` `6+15+24+7+10+12+30+18` `=` `122` Score `(x)` Frequency `(f)` `f⋅x` 3 2 6 5 3 15 6 4 24 7 1 7 10 1 10 12 1 12 15 2 30 18 1 18 `\text(Total) =15` `\text(Total) =122` Use the formula to compute for the mean.`\text(Mean)` `=` $$\frac{\color{#314EC4}{\sum f⋅x}}{\color{#9202AA}{\sum f}}$$ Mean Formula `\text(Mean)` `=` $$\frac{\color{#314EC4}{122}}{\color{#9202AA}{15}}$$ Substitute values `\text(Mean)` `=` `8.13` Rounded to two decimal places `\text(Mean)=8.13` -
Question 8 of 8
8. Question
Complete the frequency distribution table and find the median.Score `(x)` Frequency `(f)` 8 2 9 3 10 7 11 4 12 8 13 2 14 1 - `\text(Median )=` (11)
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The median is the middle value of a data set.If there are two middle values on a data set, we get their sum and halve it to get the median.First, find the sum of the frequency columnScore `(x)` Frequency `(f)` 8 2 9 3 10 7 11 4 12 8 13 2 14 1 `\text(Total)=27` Knowing that the median is the middle value, simply halve the total `(27)` and round it up to get the exact position of the middle value.`27xx1/2` `=` `13.5` `=` `14` Round up This means that the median is in the `14`th position.Now, find the corresponding `14`th score by counting down the frequency column row by row until we reach `14`Score `(x)` Frequency `(f)` 8 2 The `1`st and `2`nd score is `8` 9 2+3=5 The `3`rd to `5`th score is `9` 10 5+7=12 The `6`th to `12`th score is `10` 11 12+4=16 The `13`th to `16`th score is `11` 12 8 13 2 14 1 `\text(Total)=27` The `14`th score is between the `13`th and `16`th.Therefore, the median is `11`.`\text(Median)=11`
Quizzes
- Find Mean, Mode, Median and Range 1
- Find Mean, Mode, Median and Range 2
- Find Mean, Mode, Median and Range 3
- Create Frequency Tables & Graphs
- Interpret Frequency Tables 1
- Interpret Frequency Tables 2
- Create and Interpret Bar & Line Graphs (Histograms)
- Interpret Cumulative Frequency Tables and Charts 1
- Interpret Cumulative Frequency Tables and Charts 2
- Create Grouped Frequency Tables and Graphs
- Interpret Grouped Frequency Tables
- Create and Interpret Dot Plots (Line Plots) 1
- Create and Interpret Dot Plots (Line Plots) 2
- Finding the Interquartile Range 1
- Finding the Interquartile Range 2
- Create and Interpret Box & Whisker Plots 1
- Create and Interpret Box & Whisker Plots 2
- Create and Interpret Box & Whisker Plots 3
- Create and Interpret Box & Whisker Plots 4
- Create and Interpret Stem & Leaf Plots 1
- Create and Interpret Stem & Leaf Plots 2
- Create and Interpret Stem & Leaf Plots 3
- Create and Interpret Stem & Leaf Plots 4