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Question 1 of 7
Find the equation of a line with the slope m=-12m=−12 and passing through the point (5,-3)(5,−3).
Incorrect
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Point Gradient Form: y-y−y1y1==mm(x-(x−x1x1))
- mm is the gradient of the line
- (x1,y1)(x1,y1) is a point that lies on the line
Substitute the given gradient and point into the formula.
Point: (x1,y1)=(5,-3)(x1,y1)=(5,−3)
Gradient: m=-12m=−12
y-y−y1y1 |
== |
mm(x-(x−x1x1)) |
Point-Gradient Formula |
|
y-y−(-3)(−3) |
== |
(-12)(−12)(x-5) |
Plug in the values |
|
y+3 |
= |
-12x+52 |
|
2y+6 |
= |
-x+5 |
Multiply both sides by 2 |
2y+6 +x-5 |
= |
-x+5 +x-5 |
Add x-5 to both sides |
x+2y+1 |
= |
0 |
Simplify |
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Question 2 of 7
Find the equation of a line with the slope m=2 and passing through the point (-5,-6).
Incorrect
Point Slope Form: y-y1=m(x-x1)
- m is the slope of the line
- (x1,y1) is a point that lies on the line
Substitute the given slope and point into the formula.
Point: (x1,y1)=(-5,-6)
Slope: m=2
y-y1 |
= |
m(x-x1) |
Point Slope formula |
|
y--6 |
= |
(2)(x-(-5)) |
Plug in the values |
|
y+6 |
= |
2x+10 |
|
|
|
|
|
y+6-y-6 |
= |
2x+10-y-6 |
Add -y-6 to both sides |
0 |
= |
2x-y+4 |
Simplify |
2x-y+4 |
= |
0 |
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Question 3 of 7
Find the equation of a line with the slope m=-12 and passing through the point (2,3).
Incorrect
Point Slope Form: y-y1=m(x-x1)
- m is the slope of the line
- (x1,y1) is a point that lies on the line
Substitute the given slope and point into the formula.
Point: (x1,y1)=(2,3)
Slope: m=-12
y-y1 |
= |
m(x-x1) |
Point Slope formula |
|
y-3 |
= |
(-12)(x-(2)) |
Plug in the values |
|
y-3 |
= |
-12x+1 |
|
2y-6 |
= |
x–2 |
Multiply both sides by -2 |
-2y+6+2y-6 |
= |
x–2+2y-6 |
Add 2y-6 to both sides |
0 |
= |
x+2y-8 |
Simplify |
x+2y-8 |
= |
0 |
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Question 4 of 7
Find the equation of a line passing through the points (-1,-7) and (1,3).
Incorrect
Solve for the slope first using the given points.
Point: (x1,y1)=(-1,-7)
Point: (x2,y2)=(1,3)
y-y1x-x1 |
= |
y2-y1x2-x1 |
Two Point Formula |
|
y--7x--1 |
= |
3--71--1 |
Plug in the values |
|
y+7x+1 |
= |
102 |
|
y+7x+1 |
= |
5 |
|
y+7 |
= |
5x+5 |
Multiply both sides by x+1 |
y+7-2 |
= |
5x+5-2 |
Add -2 to both sides |
y |
= |
5x+3 |
Simplify |
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Question 5 of 7
Find the equation of a line passing through the points (0,2) and (1,-2).
Incorrect
Solve for the slope first using the given points.
Point: (x1,y1)=(0,2)
Point: (x2,y2)=(1,-2)
y-y1x-x1 |
= |
y2-y1x2-x1 |
Two Point Formula |
|
y-2x-0 |
= |
-2-21-0 |
Plug in the values |
|
y-2x |
= |
-41 |
|
y-2x |
= |
-4 |
|
y-2 |
= |
-4x |
Multiply both sides by x |
y-2+2 |
= |
-4x+2 |
Add 2 to both sides |
y |
= |
-4x+2 |
Simplify |
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Question 6 of 7
Find the equation of a line passing through the points (-6,8) and (4,8).
Incorrect
Solve for the slope first using the given points.
Point: (x1,y1)=(-6,8)
Point: (x2,y2)=(4,8)
y-y1x-x1 |
= |
y2-y1x2-x1 |
Two Point Formula |
|
y-8x--6 |
= |
8-84--6 |
Plug in the values |
|
y-8x+6 |
= |
04+6 |
|
y-8x+6 |
= |
0 |
|
y-8 |
= |
0 |
|
y-8+8 |
= |
0+8 |
Add 8 to both sides |
y |
= |
8 |
Simplify |
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Question 7 of 7
Find the equation of a line passing through the points (1,8) and (-2,2).
Incorrect
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Point Gradient Form: y-y1=m(x-x1)
- m is the gradient of the line
- (x1,y1) is a point that lies on the line
Solve for the gradient first using the given points.
Point: (x1,y1)=(1,8)
Point: (x2,y2)=(-2,2)
m |
= |
y2−y1x2−x1 |
Gradient Formula |
|
|
= |
2−8−2−1 |
Plug in the Values |
|
|
= |
-6-3 |
|
m |
= |
2 |
Substitute the calculated gradient and one point into the Point-Gradient Formula.
Point: (x1,y1)=(1,8)
Gradient: m=2
y-y1 |
= |
m(x-x1) |
Point-Gradient Formula |
y-8 |
= |
(2)(x-1) |
Plug in the values |
y-8 |
= |
2x-2 |
y-8 +8 |
= |
2x-2 +8 |
Add 8 to both sides |
y |
= |
2x+6 |
Simplify |