Simple Probability 3
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Question 1 of 7
1. Question
Find the probability of spinning the following spinners and getting:
`(i)` Pink or Green
`(ii)` Yellow or BlueWrite fractions in the format “a/b”-
`(i)` (2/5, 0.4)`(ii)` (3/4, 0.75)
Hint
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Nice Job!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(i)` Find the probability of the arrow landing on Pink or Green.
favourable outcomes`=``2` (`1` Pink `+1` Green)total outcomes`=``5` (Pink, Green, Orange, Blue, Yellow)$$ \mathsf{P(Pink\:or\:Green)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{2}}{\color{#007DDC}{5}}$$ Substitute values `(ii)` Find the probability of the arrow landing on Yellow or Blue.
favourable outcomes`=``3` (`2` Yellow `+1` Blue)total outcomes`=``4` (Orange, Blue, and `2` Yellow)$$ \mathsf{P(Yellow\:or\:Blue)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{3}}{\color{#007DDC}{4}}$$ Substitute values `(i) 2/5``(ii) 3/4` -
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Question 2 of 7
2. Question
A six-sided dice does not have a side with `6` dots but instead has two sides with `1` dot. Find the probability of the rolling the dice and getting:`(d) 6``(e)` greater than `1`Write fractions in the format “a/b”-
`(d)` (0, 0/6)`(e)` (2/3, 4/6, 0.67)
Hint
Help VideoCorrect
Fantastic!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(d)` Find the probability of rolling the dice and getting `6`.favourable outcomes`=``0` (no sides have `6` dots)total outcomes`=``6` (`1,1,2,3,4,5`)$$ \mathsf{P(}6\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{0}}{\color{#007DDC}{6}}$$ Substitute values `=` $$0$$ `(e)` Find the probability of rolling the dice and getting greater than `1`.favourable outcomes`=``4` (`2,3,4,5`)total outcomes`=``6` (`1,1,2,3,4,5`)$$ \mathsf{P(greater\:than\:}1\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{4}}{\color{#007DDC}{6}}$$ Substitute values `=` $$\frac{2}{3}$$ `(d) 0``(e) 4/6` or `2/3` -
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Question 3 of 7
3. Question
A normal six-sided dice is rolled. Find the probability of getting:`(d) 3` or `6``(e) “>“3``(f) “<“7`Write fractions in the format “a/b”-
`(d)` (1/3, 2/6, 0.17)`(e)` (1/2, 3/6, 0.5)`(f)` (1, 6/6)
Hint
Help VideoCorrect
Correct!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(d)` Find the probability of the rolling the dice and getting `3` or `6`.favourable outcomes`=``2` (`3,6`)total outcomes`=``6` (`1,2,3,4,5,6`)$$ \mathsf{P(}3\:\mathsf{or}\:6\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{2}}{\color{#007DDC}{6}}$$ Substitute values `=` $$\frac{1}{3}$$ `(e)` Find the probability of the rolling the dice and getting `>“3`.favourable outcomes`=``3` (`4,5,6`)total outcomes`=``6` (`1,2,3,4,5,6`)$$ \mathsf{P(}>3\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{3}}{\color{#007DDC}{6}}$$ Substitute values `=` $$\frac{1}{2}$$ `(f)` Find the probability of the rolling the dice and getting `<“7`.favourable outcomes`=``6` (`1,2,3,4,5,6`)total outcomes`=``6` (`1,2,3,4,5,6`)$$ \mathsf{P(}<7\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{6}}{\color{#007DDC}{6}}$$ Substitute values `=` $$1$$ `(d) 1/3``(e) 1/2``(f) 1` -
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Question 4 of 7
4. Question
A jar contains `5` red marbles, `6` yellow marbles and `3` black marbles. Find the probability of drawing a marble at random and getting:`(c)` Black or Red`(d)` BlueWrite fractions in the format “a/b”-
`(c)` (4/7, 8/14, 0.57)`(d)` (0, 0/14)
Hint
Help VideoCorrect
Fantastic!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(c)` Find the probability of the drawing a marble at random and getting a Black or Red marble.favourable outcomes`=``8` (`3` Black, `5` Red)total outcomes`=``14` (`5` Red, `6` Yellow, `3` Black)$$ \mathsf{P(Black\:or\:Red)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{8}}{\color{#007DDC}{14}}$$ Substitute values `=` $$\frac{4}{7}$$ `(d)` Find the probability of the drawing a marble at random and getting a Blue marble.favourable outcomes`=``0` (there are no Blue marbles)total outcomes`=``14` (`5` Red, `6` Yellow, `3` Black)$$ \mathsf{P(Blue)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{0}}{\color{#007DDC}{14}}$$ Substitute values `=` $$0$$ `(c) 4/7``(d) 0` -
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Question 5 of 7
5. Question
Find the probability of drawing from a standard deck of cards and getting:`(c)` Picture`(d)` Red or BlackWrite fractions in the format “a/b”-
`(c)` (3/13, 12/52, 0.23)`(d)` (1, 52/52)
Hint
Help VideoCorrect
Correct!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(c)` Find the probability of drawing from a standard deck of cards and getting a Picture card.favourable outcomes`=3*4=``12` (a standard deck has `3` Picture cards for each of the `4` suits)total outcomes`=``52` (a standard deck has `52` cards)$$ \mathsf{P(Picture)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{12}}{\color{#007DDC}{52}}$$ Substitute values `=` $$\frac{3}{13}$$ `(d)` Find the probability of drawing from a standard deck of cards and getting a Red or Black card.favourable outcomes`=``52` (all cards from a standard deck are either Red or Black)total outcomes`=``52` (a standard deck has `52` cards)$$ \mathsf{P(Red\:or\:Black)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{52}}{\color{#007DDC}{52}}$$ Substitute values `=` $$1$$ `(c) 3/13``(d) 1` -
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Question 6 of 7
6. Question
Find the probability of drawing from a standard deck of cards and getting:`(c)` Red or a Black `9``(d)` Red `4`Write fractions in the format “a/b”-
`(c)` (7/13, 28/52, 0.52)`(d)` (2/52, 1/26, 0.04)
Hint
Help VideoCorrect
Well Done!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(c)` Find the probability of drawing from a standard deck of cards and getting a Red or a Black `9` card.favourable outcomes`=26+1+1=``28` (`26` Red, one `9` of Clubs, one `9` of Spades)total outcomes`=``52` (a standard deck has `52` cards)$$ \mathsf{P(Red\:or\:a\:Black\:}9\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{28}}{\color{#007DDC}{52}}$$ Substitute values `=` $$\frac{7}{13}$$ `(d)` Find the probability of drawing from a standard deck of cards and getting a Red `4` card.favourable outcomes`=``2` (one `4` of Hearts, one `4` of Diamonds)total outcomes`=``52` (a standard deck has `52` cards)$$ \mathsf{P(Red\:}4\mathsf{)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{2}}{\color{#007DDC}{52}}$$ Substitute values `=` $$\frac{1}{26}$$ `(c) 28/52` or `7/13``(d) 2/52` or `1/26` -
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Question 7 of 7
7. Question
Find the probability of drawing from a standard deck of cards and getting:`(c)` Black Jack`(d)` Queen or `3` of DiamondsWrite fractions in the format “a/b”-
`(c)` (2/52, 1/26, 0.04)`(d)` (5/52, [0.10)
Hint
Help VideoCorrect
Exceptional!
Incorrect
Help VideoProbability Formula
$$\mathsf{P(E)}=\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$Addition Principle
If two or more events are joined by OR, their probabilities should be added.`(c)` Find the probability of drawing from a standard deck of cards and getting a Black Jack.favourable outcomes`=``2` (`1` Jack of Spades, `1` Jack of Clubs)total outcomes`=``52` (a standard deck has `52` cards)$$ \mathsf{P(Black\:Jack)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{2}}{\color{#007DDC}{52}}$$ Substitute values `=` $$\frac{1}{26}$$ `(d)` Find the probability of drawing from a standard deck of cards and getting a Queen or a `3` of Diamonds card.favourable outcomes`=(4*1)+1=``5` (each of the `4` suits have `1` Queen card, one `3` of Diamonds)total outcomes`=``52` (a standard deck has `52` cards)$$ \mathsf{P(Queen\:or\:}3\:\mathsf{of\:Diamonds)} $$ `=` $$\frac{\color{#e65021}{\mathsf{favourable\:outcomes}}}{\color{#007DDC}{\mathsf{total\:outcomes}}}$$ Probability Formula `=` $$\frac{\color{#e65021}{5}}{\color{#007DDC}{52}}$$ Substitute values `(c) 2/52` or `1/26``(d) 5/52` -
Quizzes
- Simple Probability 1
- Simple Probability 2
- Simple Probability 3
- Simple Probability 4
- Complementary Probability 1
- Compound Events 1
- Compound Events 2
- Venn Diagrams (Non Mutually Exclusive)
- Independent Events 1
- Independent Events 2
- Dependent Events (Conditional Probability)
- Probability Tree (Independent)
- Probability Tree (Dependent)