Solve Equations using the Distributive Property 1

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Question 1 of 4

1. Question
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$2 (x + 4) = 12$ $2(x+4)=12$
- $x =$ $x=$ (2)
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Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

Distributive Property

$a$ $a$ $(b + c) =$ $(b+c)=$ $a$ $a$ $b +$ $b+$ $a$ $a$ $c$ $c$

To solve for $x$ $x$ , it needs to be alone on one side.

Start by expanding the left side of the equation by using the Distributive Property.

$2$ $2$ $($ $($ $x$ $x$ $+ 4)$ $+4)$ $=$ $=$ $12$ $12$

$2$ $2$ $x$ $x$ $+$ $+$ $2$ $2$ $(4)$ $(4)$ $=$ $=$ $12$ $12$

$2$ $2$ $x$ $x$ $+ 8$ $+8$ $=$ $=$ $12$ $12$

Next, move $8$ $8$ to the other side by subtracting $8$ $8$ from both sides of the equation.

$2$ $2$ $x$ $x$ $+ 8$ $+8$ $=$ $=$ $12$ $12$

$2$ $2$ $x$ $x$ $+ 8$ $+8$ $- 8$ $-8$ $=$ $=$ $12$ $12$ $- 8$ $-8$

$2$ $2$ $x$ $x$ $=$ $=$ $4$ $4$ $8 - 8$ $8-8$ cancels out

Finally, remove $2$ $2$ by dividing both sides of the equation by $2$ $2$ .

$2$ $2$ $x$ $x$ $=$ $=$ $4$ $4$

$2$ $2$ $x$ $x$ $\div 2$ $divide2$ $=$ $=$ $4$ $4$ $\div 2$ $divide2$

$x$ $x$ $=$ $=$ $2$ $2$ $2 \div 2$ $2divide2$ cancels out

Check our work

To confirm our answer, substitute $x = 2$ $x=2$ to the original equation.

$2 (x + 4)$ $2(x+4)$ $=$ $=$ $12$ $12$

$2 [(2) + 4]$ $2[(2)+4]$ $=$ $=$ $12$ $12$ Substitute $x = 2$ $x=2$

$2 (6)$ $2(6)$ $=$ $=$ $12$ $12$

$12$ $12$ $=$ $=$ $12$ $12$

Since the equation is true, the answer is correct.

$x = 2$ $x=2$
Question 2 of 4

2. Question
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$8 (y - 6) = 16$ $8(y-6)=16$
- $y =$ $y=$ (8)
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Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

Distributive Property

$a$ $a$ $(b + c) =$ $(b+c)=$ $a$ $a$ $b +$ $b+$ $a$ $a$ $c$ $c$

To solve for $y$ $y$ , it needs to be alone on one side.

Start by expanding the left side of the equation by using the Distributive Property.

$8$ $8$ $($ $($ $y$ $y$ $- 6)$ $-6)$ $=$ $=$ $16$ $16$

$8$ $8$ $y$ $y$ $-$ $-$ $8$ $8$ $(6)$ $(6)$ $=$ $=$ $16$ $16$

$8$ $8$ $y$ $y$ $- 48$ $-48$ $=$ $=$ $16$ $16$

Next, move $48$ $48$ to the other side by adding $48$ $48$ to both sides of the equation.

$8$ $8$ $y$ $y$ $- 48$ $-48$ $=$ $=$ $16$ $16$

$8$ $8$ $y$ $y$ $- 48$ $-48$ $+ 48$ $+48$ $=$ $=$ $16$ $16$ $+ 48$ $+48$

$8$ $8$ $y$ $y$ $=$ $=$ $64$ $64$ $- 48 + 48$ $-48+48$ cancels out

Finally, remove $8$ $8$ by dividing both sides of the equation by $8$ $8$ .

$8$ $8$ $y$ $y$ $=$ $=$ $64$ $64$

$8$ $8$ $y$ $y$ $\div 8$ $divide8$ $=$ $=$ $64$ $64$ $\div 8$ $divide8$

$y$ $y$ $=$ $=$ $8$ $8$ $8 \div 8$ $8divide8$ cancels out

Check our work

To confirm our answer, substitute $y = 8$ $y=8$ to the original equation.

$8 (y - 6)$ $8(y-6)$ $=$ $=$ $16$ $16$

$8 [(8) - 6]$ $8[(8)-6]$ $=$ $=$ $16$ $16$ Substitute $y = 8$ $y=8$

$8 (2)$ $8(2)$ $=$ $=$ $16$ $16$

$16$ $16$ $=$ $=$ $16$ $16$

Since the equation is true, the answer is correct.

$y = 8$ $y=8$
Question 3 of 4

3. Question
Solve

$21 = 3 (t - 3)$ $21=3(t-3)$
- $t =$ $t=$ (10)
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Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

Distributive Property

$a$ $a$ $(b + c) =$ $(b+c)=$ $a$ $a$ $b +$ $b+$ $a$ $a$ $c$ $c$

To solve for $t$ $t$ , it needs to be alone on one side.

Start by expanding the right side of the equation by using the Distributive Property.

$21$ $21$ $=$ $=$ $3$ $3$ $($ $($ $t$ $t$ $- 3)$ $-3)$

$21$ $21$ $=$ $=$ $3$ $3$ $t$ $t$ $+$ $+$ $3$ $3$ $(- 3)$ $(-3)$

$21$ $21$ $=$ $=$ $3$ $3$ $t$ $t$ $- 9$ $-9$

Next, move $- 9$ $-9$ to the other side by adding $9$ $9$ to both sides of the equation.

$21$ $21$ $=$ $=$ $3$ $3$ $t$ $t$ $- 9$ $-9$

$21$ $21$ $+ 9$ $+9$ $=$ $=$ $3$ $3$ $t$ $t$ $- 9$ $-9$ $+ 9$ $+9$

$30$ $30$ $=$ $=$ $3$ $3$ $t$ $t$ $- 9 + 9$ $-9+9$ cancels out

Finally, remove $3$ $3$ by dividing both sides of the equation by $3$ $3$ .

$30$ $30$ $=$ $=$ $3$ $3$ $t$ $t$

$30$ $30$ $\div 3$ $divide3$ $=$ $=$ $3$ $3$ $t$ $t$ $\div 3$ $divide3$

$10$ $10$ $=$ $=$ $t$ $t$ $3 \div 3$ $3divide3$ cancels out

$t$ $t$ $=$ $=$ $10$ $10$

Check our work

To confirm our answer, substitute $t = 10$ $t=10$ to the original equation.

$21$ $21$ $=$ $=$ $3 (t - 3)$ $3(t-3)$

$21$ $21$ $=$ $=$ $3 (10 - 3)$ $3(10-3)$ Substitute $t = 10$ $t=10$

$21$ $21$ $=$ $=$ $3 (7)$ $3(7)$

$21$ $21$ $=$ $=$ $21$ $21$

Since the equation is true, the answer is correct.

$t = 10$ $t=10$
Question 4 of 4

4. Question
Solve

$3 (14 - a) = 3$ $3(14-a)=3$
- $a =$ $a=$ (13)
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Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

Distributive Property

$a$ $a$ $(b + c) =$ $(b+c)=$ $a$ $a$ $b +$ $b+$ $a$ $a$ $c$ $c$

To solve for $a$ $a$ , it needs to be alone on one side.

Start by expanding the left side of the equation by using the Distributive Property.

$3$ $3$ $(14 -$ $(14-$ $a$ $a$ $)$ $)$ $=$ $=$ $3$ $3$

$3$ $3$ $(14) -$ $(14)-$ $3$ $3$ $a$ $a$ $=$ $=$ $3$ $3$

$42 - 3$ $42-3$ $a$ $a$ $=$ $=$ $3$ $3$

Next, move $42$ $42$ to the other side by subtracting $42$ $42$ from both sides of the equation.

$42 - 3$ $42-3$ $a$ $a$ $=$ $=$ $3$ $3$

$42 - 3$ $42-3$ $a$ $a$ $- 42$ $-42$ $=$ $=$ $3$ $3$ $- 42$ $-42$

$- 3$ $-3$ $a$ $a$ $=$ $=$ $- 39$ $-39$ $42 - 42$ $42-42$ cancels out

Finally, remove $- 3$ $-3$ by dividing both sides of the equation by $- 3$ $-3$ .

$- 3$ $-3$ $a$ $a$ $=$ $=$ $- 39$ $-39$

$- 3$ $-3$ $a$ $a$ $\div - 3$ $divide-3$ $=$ $=$ $- 39$ $-39$ $\div - 3$ $divide-3$

$a$ $a$ $=$ $=$ $13$ $13$ $- 3 \div - 3$ $-3divide-3$ cancels out

Check our work

To confirm our answer, substitute $a = 13$ $a=13$ to the original equation.

$3 (14 - a)$ $3(14-a)$ $=$ $3$

$3[14-(13)]$ $=$ $3$ Substitute $a=13$

$3(1)$ $=$ $3$

$3$ $=$ $3$

Since the equation is true, the answer is correct.

$a=13$

Solve Equations using the Distributive Property 1

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Quiz summary

Information

1. Question

Hint

Great Work!

Inverse Operations

Distributive Property

2. Question

Hint

Correct!

Inverse Operations

Distributive Property

3. Question

Hint

Excellent!

Inverse Operations

Distributive Property

4. Question

Hint

Well Done!

Inverse Operations

Distributive Property

Quizzes

$2$ $2$ $($ $($ $x$ $x$ $+ 4)$ $+4)$	$=$ $=$	$12$ $12$
$2$ $2$ $x$ $x$ $+$ $+$ $2$ $2$ $(4)$ $(4)$	$=$ $=$	$12$ $12$
$2$ $2$ $x$ $x$ $+ 8$ $+8$	$=$ $=$	$12$ $12$

$2$ $2$ $x$ $x$	$=$ $=$	$4$ $4$
$2$ $2$ $x$ $x$ $\div 2$ $divide2$	$=$ $=$	$4$ $4$ $\div 2$ $divide2$
$x$ $x$	$=$ $=$	$2$ $2$	$2 \div 2$ $2divide2$ cancels out

$2 (x + 4)$ $2(x+4)$	$=$ $=$	$12$ $12$
$2 [(2) + 4]$ $2[(2)+4]$	$=$ $=$	$12$ $12$	Substitute $x = 2$ $x=2$
$2 (6)$ $2(6)$	$=$ $=$	$12$ $12$
$12$ $12$	$=$ $=$	$12$ $12$

$8$ $8$ $($ $($ $y$ $y$ $- 6)$ $-6)$	$=$ $=$	$16$ $16$
$8$ $8$ $y$ $y$ $-$ $-$ $8$ $8$ $(6)$ $(6)$	$=$ $=$	$16$ $16$
$8$ $8$ $y$ $y$ $- 48$ $-48$	$=$ $=$	$16$ $16$

$8$ $8$ $y$ $y$	$=$ $=$	$64$ $64$
$8$ $8$ $y$ $y$ $\div 8$ $divide8$	$=$ $=$	$64$ $64$ $\div 8$ $divide8$
$y$ $y$	$=$ $=$	$8$ $8$	$8 \div 8$ $8divide8$ cancels out

$8 (y - 6)$ $8(y-6)$	$=$ $=$	$16$ $16$
$8 [(8) - 6]$ $8[(8)-6]$	$=$ $=$	$16$ $16$	Substitute $y = 8$ $y=8$
$8 (2)$ $8(2)$	$=$ $=$	$16$ $16$
$16$ $16$	$=$ $=$	$16$ $16$

$21$ $21$	$=$ $=$	$3$ $3$ $($ $($ $t$ $t$ $- 3)$ $-3)$
$21$ $21$	$=$ $=$	$3$ $3$ $t$ $t$ $+$ $+$ $3$ $3$ $(- 3)$ $(-3)$
$21$ $21$	$=$ $=$	$3$ $3$ $t$ $t$ $- 9$ $-9$

$30$ $30$	$=$ $=$	$3$ $3$ $t$ $t$
$30$ $30$ $\div 3$ $divide3$	$=$ $=$	$3$ $3$ $t$ $t$ $\div 3$ $divide3$
$10$ $10$	$=$ $=$	$t$ $t$	$3 \div 3$ $3divide3$ cancels out
$t$ $t$	$=$ $=$	$10$ $10$

$21$ $21$	$=$ $=$	$3 (t - 3)$ $3(t-3)$
$21$ $21$	$=$ $=$	$3 (10 - 3)$ $3(10-3)$	Substitute $t = 10$ $t=10$
$21$ $21$	$=$ $=$	$3 (7)$ $3(7)$
$21$ $21$	$=$ $=$	$21$ $21$

$3$ $3$ $(14 -$ $(14-$ $a$ $a$ $)$ $)$	$=$ $=$	$3$ $3$
$3$ $3$ $(14) -$ $(14)-$ $3$ $3$ $a$ $a$	$=$ $=$	$3$ $3$
$42 - 3$ $42-3$ $a$ $a$	$=$ $=$	$3$ $3$

$- 3$ $-3$ $a$ $a$	$=$ $=$	$- 39$ $-39$
$- 3$ $-3$ $a$ $a$ $\div - 3$ $divide-3$	$=$ $=$	$- 39$ $-39$ $\div - 3$ $divide-3$
$a$ $a$	$=$ $=$	$13$ $13$	$- 3 \div - 3$ $-3divide-3$ cancels out

$3 (14 - a)$ $3(14-a)$	$=$	$3$
$3[14-(13)]$	$=$	$3$	Substitute $a=13$
$3(1)$	$=$	$3$
$3$	$=$	$3$