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Question 1 of 4
Solve
-7(3-y)=-28−7(3−y)=−28
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
To solve for yy, it needs to be alone on one side.
Start by expanding the left side of the equation by using the Distributive Property.
-7−7(3-(3−yy)) |
== |
-28−28 |
-7−7(3)-((3)−(-7−7)()(yy)) |
== |
-28−28 |
-21+7−21+7yy |
== |
-28−28 |
Next, move -21−21 to the other side by adding 2121 to both sides of the equation.
-21+7−21+7yy |
== |
-28−28 |
-21+7−21+7yy +21+21 |
== |
-28−28 +21+21 |
77yy |
== |
-7−7 |
-21+21−21+21 cancels out |
Finally, remove 77 by dividing both sides of the equation by 77.
77yy |
== |
-7−7 |
77yy÷7÷7 |
== |
-7−7÷7÷7 |
yy |
== |
-1−1 |
7÷77÷7 cancels out |
Check our work
To confirm our answer, substitute y=-1y=−1 to the original equation.
-7(3-y)−7(3−y) |
== |
-28−28 |
-7[3-(-1)]−7[3−(−1)] |
== |
-28−28 |
Substitute y=-1y=−1 |
-7(3+1)−7(3+1) |
== |
-28−28 |
-7(4)−7(4) |
== |
-28−28 |
-28−28 |
== |
-28−28 |
Since the equation is true, the answer is correct.
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Question 2 of 4
Solve for xx
5-(3-2x)=105−(3−2x)=10
Incorrect
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To solve for xx, get xx by itself
Subtract 55 from both sides of the equation
5-(3-2x)5−(3−2x) -5−5 |
== |
1010 -5−5 |
55-(3-2x)−(3−2x)-5−5 |
== |
1010 -5−5 |
5-55−5 cancels out |
-3+2x−3+2x |
== |
55 |
Distribute negative sign |
Next, add 33 to both sides of the equation
-3+2x−3+2x +3+3 |
== |
55 +3+3 |
-3−3+2x+2x +3+3 |
== |
55 +3+3 |
-3+3−3+3 cancels out |
2x2x |
== |
88 |
Finally, divide both sides of the equation by 22
2x2x÷2÷2 |
== |
88÷2÷2 |
22xx÷2÷2 |
== |
88÷2÷2 |
×2÷2×2÷2 cancels out |
xx |
== |
44 |
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Question 3 of 4
Solve for kk
-9(-8+k)=252−9(−8+k)=252
Incorrect
To solve for kk, get kk by itself
Distribute the value inside the parenthesis.
-9−9(-8+k)(−8+k) |
== |
252252 |
((-8)×((−8)×(-9)(−9))+(k×)+(k×(-9)(−9))) |
== |
252252 |
72-9k72−9k |
== |
252252 |
Get the kk variable on one side of the equation
72-9k72−9k -72−72 |
== |
252252 -72−72 |
Subtract 7272 from both sides |
7272-9k−9k -72−72 |
== |
252252 -72−72 |
72-7272−72 cancels out |
-9k−9k |
== |
180180 |
-9k−9k÷(-9)÷(−9) |
== |
180180÷(-9)÷(−9) |
Divide both sides by -9−9 |
-9−9kk÷(-9)÷(−9) |
== |
180180÷(-9)÷(−9) |
×(-9)÷(-9)×(−9)÷(−9) cancels out |
kk |
== |
-20−20 |
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Question 4 of 4
Solve for aa
-12(a+11)=-108−12(a+11)=−108
Incorrect
To solve for aa, get aa by itself
Distribute the value inside the parenthesis.
-12−12(a+11)(a+11) |
== |
-108−108 |
(a×(a×(-12)(−12))+(11×)+(11×(-12)(−12))) |
== |
-108−108 |
-12a-132−12a−132 |
== |
-108−108 |
Get the kk variable on one side of the equation
-12a-132−12a−132 +132+132 |
== |
-108−108 +132+132 |
Add 132132 to both sides |
-12a−12a-132−132 +132+132 |
== |
-108−108 +132+132 |
-132+132−132+132 cancels out |
-12a−12a |
== |
2424 |
-12a−12a÷(-12)÷(−12) |
== |
2424÷(-12)÷(−12) |
Divide both sides by -12−12 |
-12−12aa÷(-12)÷(−12) |
== |
2424÷(-12)÷(−12) |
×(-12)÷(-12)×(−12)÷(−12) cancels out |
aa |
== |
-2−2 |