Time and Travelling Word Problems 1

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Question 1 of 5

1. Question
A plane departs from Hanoi, Vietnam and is on its way to arrive in Sydney. Find its time of arrival given the following:

Sydney $(34 ° S, 151 ° E)$ $(34°S,151°E)$

Hanoi $(21 ° N, 106 ° E)$ $(21°N,106°E)$

Departure: $8 : 30$ $8:30$ pm Tuesday

Flight Time: $9$ $9$ hours $20$ $20$ minutes
- 1. $9 : 30$ $9:30$ am Wednesday
- 2. $11 : 30$ $11:30$ pm Tuesday
- 3. $8 : 50$ $8:50$ am Wednesday
- 4. $2 : 50$ $2:50$ am Wednesday
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The prime meridian is a line of longitude at $0 °$ $0°$

On the opposite side of the prime meridian lies the $180 °$ $180°$ meridian.

Finding the Time Difference

$1 °$ $1°$ of longitude to the west $=$ $=$ subtract 4 minutes (West = lest)

$1 °$ $1°$ of longitude to the east $=$ $=$ add 4 minutes (East = beast)

First, find the local time in Sydney when the time in Hanoi is $8 : 30$ $8:30$ pm

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This line represents a minus sign, which means we must get the difference between the two longitudes

We find the difference because both cities are on one side of $U T C$ $UTC$

$151 ° - 106 °$ $151°-106°$ $=$ $=$ $45 °$ $45°$

Next, multiply by $4$ $4$ to solve for the time difference

Since $1 ° = 4$ $1°=4$ minutes

$45 °$ $45°$ $\times 4$ $xx4$ $=$ $=$ $180$ $180$ minutes

Since Sydney is to the east of Hanoi, add $180$ $180$ minutes to $8 : 30$ $8:30$ pm

$8 : 30$ $8:30$ pm $+ 180$ $+180$ minutes

$=$ $=$ $8 : 30$ $8:30$ pm $+ 3$ $+3$ hours Divide minutes by $60$ $60$ to convert to hours

$=$ $=$ $11 : 30$ $11:30$ pm

When it is $8 : 30$ $8:30$ pm in Hanoi, at the same moment, it is $11 : 30$ $11:30$ pm in Sydney

Finally, add the flight time to $11 : 30$ $11:30$ pm to get the time of arrival in Sydney

Flight time: $9$ $9$ hours $20$ $20$ minutes

$11 : 30$ $11:30$ pm $+ 9$ $+9$ hours $20$ $20$ minutes

$=$ $=$ $23 : 30 + 9$ $23:30+9$ hours $20$ $20$ minutes Convert to military time by adding $12$ $12$

$=$ $=$ $32 : 50$ $32:50$

Since it is greater than $24$ $24$ , it means a day has passed and the time of arrival is on Wednesday

Subtract $24$ $24$ hours to get a normal time format

$32 : 50 - 24$ $32:50-24$ hours

$=$ $=$ $8 : 50$ $8:50$ am

The time of arrival in Sydney is $8 : 50$ $8:50$ am Wednesday

$8 : 50$ $8:50$ am, Wednesday

Question 2 of 5

A plane departs from San Francisco and is on its way to arrive in Dallas. Find its time of arrival given the following:

Dallas

(32 ° N, 96 ° W)

$(32°N,96°W)$

San Francisco

(37 ° N, 122 ° W)

$(37°N,122°W)$

Departure:

10

$10$ am

Flight Time:

3

$3$ hours

30

$30$ minutes

1. $03 : 30$ $03:30$ am
2. $05 : 20$ $05:20$ am
3. $03 : 14$ $03:14$ pm
4. $10 : 16$ $10:16$ pm

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The prime meridian is a line of longitude at

0 °

$0°$

On the opposite side of the prime meridian lies the $180 °$ $180°$ meridian.

Finding the Time Difference

1 °

$1°$ of longitude to the west

=

$=$ subtract 4 minutes (West = lest)

1 °

$1°$ of longitude to the east

=

$=$ add 4 minutes (East = beast)

First, find the local time in Dallas when the time in San Francisco is

10

$10$ am

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This line represents a minus sign, which means we must get the difference between the two longitudes

We find the difference because both cities are on one side of

U T C

$UTC$

122 ° - 96 °

$122°-96°$

=

$=$

26 °

$26°$

Next, multiply by

4

$4$ to solve for the time difference

Since

1 ° = 4

$1°=4$ minutes

$26 °$ $26°$

\times 4

$xx4$

=

$=$

104

$104$ minutes

Since Dallas is to the east of San Francisco, add

104

$104$ minutes to

10

$10$ am

	$10$ $10$ am $+ 104$ $+104$ minutes
$=$ $=$	$10$ $10$ am $+ 1$ $+1$ hour $44$ $44$ minutes	Divide minutes by $60$ $60$ to convert to hours
$=$ $=$	$11 : 44$ $11:44$ am

When it is

10

$10$ am in San Francisco, at the same moment, it is

11 : 44

$11:44$ am in Dallas

Finally, add the flight time to

11 : 44

$11:44$ am to get the time of arrival in Dallas

Flight time:

3

$3$ hours

30

$30$ minutes

	$11 : 44$ $11:44$ am $+ 3$ $+3$ hours $30$ $30$ minutes
$=$ $=$	$11 ° 44 ° + 03 ° 30 °$ $11°44°+03°30°$	Press the DMS button for every $°$ $°$
$=$ $=$	$15 ° 14 ’$ $15°14’$
$=$ $=$	$15 : 14$ $15:14$

The time is in pm or in the afternoon since it is greater than

12

$12$ .

Subtract

12

$12$ hours to get a proper time format

		$15 : 14 - 12$ $15:14-12$ hours
	$=$ $=$	$03 : 14$ $03:14$ pm

The plane arrived in Dallas at $03 : 14$ $03:14$ pm

03 : 14

$03:14$ pm

Question 3 of 5

A plane departs from Melbourne and is on its way to arrive in Honolulu. Find its time of arrival given the following:

Honolulu

(158 ° W)

$(158°W)$

Melbourne

(145 ° E)

$(145°E)$

Departure:

5 : 30

$5:30$ pm Saturday

Flight Time:

10

$10$ hours

30

$30$ minutes

1. $7 : 48$ $7:48$ am Saturday
2. $7 : 48$ $7:48$ am Sunday
3. $7 : 48$ $7:48$ pm Friday
4. $7 : 18$ $7:18$ pm Friday

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The prime meridian is a line of longitude at

0 °

$0°$

On the opposite side of the prime meridian lies the $180 °$ $180°$ meridian.

Finding the Time Difference

1 °

$1°$ of longitude to the west

=

$=$ subtract 4 minutes (West = lest)

1 °

$1°$ of longitude to the east

=

$=$ add 4 minutes (East = beast)

First, find the local time in Honolulu when the time in Melbourne is

5 : 30

$5:30$ pm

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This represents a plus sign, which means we must get the sum of the two longitudes

We find the sum because both cities are on either side of

U T C

$UTC$

158 ° + 145 °

$158°+145°$

=

$=$

303 °

$303°$

Next, multiply by

4

$4$ to solve for the time difference

Since

1 ° = 4

$1°=4$ minutes

$303 °$ $303°$

\times 4

$xx4$

=

$=$

1212

$1212$ minutes

Since Honolulu is to the west of Melbourne, subtract

1212

$1212$ minutes from

5 : 30

$5:30$ pm

	$5 : 30$ $5:30$ pm $- 1212$ $-1212$ minutes
$=$ $=$	$17 : 30 - 20$ $17:30-20$ hours $12$ $12$ minutes	Divide minutes by $60$ $60$ to convert to hours
$=$ $=$	$17 ° 30 ° - 20 ° 12 °$ $17°30°-20°12°$	Press the DMS button for every $°$ $°$
$=$ $=$	$- 2 ° 42 ’$ $-2°42’$

Since the answer is negative, it means the time we are looking for occurs the day before which is Friday

Simply add

24

$24$ hours to convert it to military time

		$- 2 ° 42 ’ + 24 °$ $-2°42’+24°$
	$=$ $=$	$21 ° 18 ’$ $21°18’$
	$=$ $=$	$09 : 18$ $09:18$ pm

When it is

5 : 30

$5:30$ pm Saturday in Melbourne, at the same moment, it is

9 : 18

$9:18$ pm Friday in Honolulu

Finally, add the flight time to

9 : 18

$9:18$ pm to get the time of arrival in Honolulu

Flight time:

10

$10$ hours

30

$30$ minutes

	$09 : 18$ $09:18$ pm $+ 10$ $+10$ hours $30$ $30$ minutes
$=$ $=$	$21 ° 18 ° + 10 ° 30 °$ $21°18°+10°30°$	Press the DMS button for every $°$ $°$
$=$ $=$	$31 ° 48 ’$ $31°48’$

Since it is greater than

24

$24$ , it means a day has passed and the time of arrival is on Saturday

Subtract

24

$24$ hours to get a normal time format

		$31°48′-24°$
	$=$	$7:48$ am

The time of arrival in Honolulu is $7:48$ am Saturday

$7:48$ am Saturday

Question 4 of 5

A rally car departs from Perth and is on its way to Sydney. Find its time of arrival given the following:

Sydney

$(151°E)$

Perth

$(116°E)$

Departure:

$9$ am Saturday

Travel Time:

$85$ hours

1. $08:20$ pm Tuesday
2. $08:00$ am Monday
3. $01:20$ am Tuesday
4. $12:20$ am Wednesday

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The prime meridian is a line of longitude at

$0°$

On the opposite side of the prime meridian lies the $180°$ meridian.

Finding the Time Difference

$1°$ of longitude to the west

$=$ subtract 4 minutes (West = lest)

$1°$ of longitude to the east

$=$ add 4 minutes (East = beast)

First, find the local time in Sydney when the time in Perth is

$9$ am

Start by drawing a rectangle with the Prime Meridian and the two longitudes

The Prime Meridian is also called Coordinated Universal Time (UTC)

Draw a line that connects the two longitudes

This line represents a minus sign, which means we must get the difference between the two longitudes

We find the difference because both cities are on one side of

$UTC$

$151°-116°$

$=$

$35°$

Next, multiply by

$4$ to solve for the time difference

Since

$1°=4$ minutes

$35°$

$xx4$

$=$

$140$ minutes

Since Sydney is to the east of Perth, add

$140$ minutes to

$9$ am

	$9$ am $+140$ minutes
$=$	$9$ am $+2$ hours $20$ minutes	Divide minutes by $60$ to convert to hours
$=$	$11:20$ am

When it is

$9$ am in Perth, at the same moment, it is

$11:20$ am in Sydney

Finally, add the time to

$11:20$ am to get the time of arrival in Sydney

Flight time:

$85$ hours

	$11:20$ am $+85$ hours
	$11:20$ am $+3$ days $13$ hours	$1$ day is $24$ hours
	$11:20$ am $+13$ hours, Tuesday
$=$	$11°20°+13°$ , Tuesday	Press the DMS button for every $°$
$=$	$24°20′,$ Tuesday

Since it is greater than

$24$ , it means another day has passed and the time of arrival is on Wednesday

Subtract

$24$ hours to get a normal time format

		$24°20′-24°$
	$=$	$0:20$
	$=$	$12:20$ am

The time of arrival in Sydney is $12:20$ am Wednesday

$12:20$ am Wednesday

Question 5 of 5

A plane departed from Beijing and has arrived in London. Find the flight time of the plane given the following:

Beijing

$(116°E)$ Departure:

$6$ pm

London

$(0°E)$ Arrival:

$9:16$ pm

(11) hours

Time and Travelling Word Problems 1

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Quiz summary

Information

1. Question

Hint

Great Work!

Finding the Time Difference

2. Question

Hint

Correct!

Finding the Time Difference

3. Question

Hint

Keep Going!

Finding the Time Difference

4. Question

Hint

Fantastic!

Finding the Time Difference

5. Question

Hint

Excellent!

Finding the Time Difference

Quizzes

	$8 : 30$ $8:30$ pm $+ 180$ $+180$ minutes
$=$ $=$	$8 : 30$ $8:30$ pm $+ 3$ $+3$ hours	Divide minutes by $60$ $60$ to convert to hours
$=$ $=$	$11 : 30$ $11:30$ pm

	$11 : 30$ $11:30$ pm $+ 9$ $+9$ hours $20$ $20$ minutes
$=$ $=$	$23 : 30 + 9$ $23:30+9$ hours $20$ $20$ minutes	Convert to military time by adding $12$ $12$
$=$ $=$	$32 : 50$ $32:50$

	$6$ pm $-464$ minutes
$=$	$6$ pm $-7$ hours $44$ minutes	Divide minutes by $60$ to convert to hours
$=$	$18°00°-07°44°$	Press the DMS button for every $°$
$=$	$10°16’$
$=$	$10:16$ am

	$09:16$ pm $-10:16$ am
$=$	$21°16°-10°16°$	Press the DMS button for every $°$
$=$	$11°00’$
$=$	$11$ hours