Topics
>
Precalculus>
Trigonometry>
Trigonometry Mixed Review: Part 2>
Trigonometry Mixed Review: Part 2 (2)Trigonometry Mixed Review: Part 2 (2)
Try VividMath Premium to unlock full access
Time limit: 0
Quiz summary
0 of 7 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
- 6
- 7
Information
–
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Loading...
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- Answered
- Review
-
Question 1 of 7
1. Question
Solve for angle BRound your answer to one decimal degree- ∠B= (25.9)°
Correct
Nice Job!
Incorrect
Cosine Rule (finding a length)
b2=a2+c2-2ac×cosBCosine Rule (finding an angle)
cosB=a2+c2−b22acRemember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Cosine Rule (finding an angle) to solve for BcosB = a2+c2−b22ac Cosine Rule Formula cosB = 25.42+17.32−12.422(25.4)(12.4) Plug in known values cosB = 645.16+299.29-153.76878.84 Evaluate cosB = 0.8996973283 Use the inverse function for cos on your calculator to get B by itselfB = cos-1(0.8996973283) The inverse of cos is cos-1 B = 25.88168913 Use the shift cos function on your calculator B = 25.9° Rounded to one decimal place B=25.9° -
Question 2 of 7
2. Question
Solve for angle BRound your answer to one decimal degree- ∠B= (58.1)°
Correct
Correct!
Incorrect
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find angle BbsinB = csinC Sine Rule Formula 28sinB = 31sin70° Plug in the values sinB×31 = 28×sin70° Cross multiply sinB = 28×sin70°31 Divide 31 from each side to isolate sinB sinB = 0.849 Evaluate Use the inverse function for sin on your calculator to get B by itselfB = sin-1(0.849) The inverse of sin is sin-1 B = 58.1030 Use the shift sin function on your calculator B = 58.1° Rounded to one decimal place ∠B=58.1° -
Question 3 of 7
3. Question
Solve for angle ARound your answer to the nearest minute- ∠A= (61)° (45)′
Hint
Help VideoCorrect
Excellent!
Incorrect
Need TextPlayCurrent Time 0:00/Duration Time 0:00Remaining Time -0:00Stream TypeLIVELoaded: 0%Progress: 0%0:00Fullscreen00:00MutePlayback Rate1x- 2x
- 1.5x
- 1.25x
- 1x
- 0.75x
- 0.5x
Subtitles- subtitles off
Captions- captions off
- English
Chapters- Chapters
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find angle AasinA = csinC Sine Rule Formula 12.5sinA = 8.4sin36°18′ Plug in the values sinA×8.4 = 12.5×sin36°18’ Cross multiply sinA = 12.5×sin36°18′8.4 Divide 8.4 from each side to isolate sinA sinA = 0.88097 Evaluate Use the inverse function for sin on your calculator to get A by itselfA = sin-1(0.88097) The inverse of sin is sin-1 A = 61.75959621 Use the shift sin function on your calculator A = 61° 45′ 34.55” Use the degrees button on your calculator A = 61°45’ Round up the minutes ∠A=61°45’ -
Question 4 of 7
4. Question
Solve for side aRound your answer as a whole number- a= (34) km
Correct
Nice Job!
Incorrect
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find side aasinA = csinC Sine Rule Formula asin96° = 15sin26° Plug in the values a×sin26° = sin96°×15 Cross multiply a = sin96°×15sin26° Divide sin26° from each side to isolate a a = 34 km Rounded to a whole number a=34 km -
Question 5 of 7
5. Question
Solve for angle CRound your answer to one decimal degree- ∠C= (101.2)°
Correct
Excellent!
Incorrect
Cosine Rule (finding a length)
c2=a2+b2-2ab×cosCCosine Rule (finding an angle)
cosC=a2+b2−c22abRemember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Cosine Rule (finding an angle) to solve for CcosC = a2+b2−c22ab Cosine Rule Formula cosC = 82+192−2222(8)(19) Plug in known values cosC = 64+361-484304 Evaluate cosC = -0.19407 Use the inverse function for cos on your calculator to get C by itselfC = cos-1(-0.19407) The inverse of cos is cos-1 C = 101.190923 Use the shift cos function on your calculator C = 101.2° Rounded to one decimal place C=101.2° -
Question 6 of 7
6. Question
Find the length of aRound your answer to one decimal place- a= (15.3)cm
Hint
Help VideoCorrect
Great Work!
Incorrect
Need TextPlayCurrent Time 0:00/Duration Time 0:00Remaining Time -0:00Stream TypeLIVELoaded: 0%Progress: 0%0:00Fullscreen00:00MutePlayback Rate1x- 2x
- 1.5x
- 1.25x
- 1x
- 0.75x
- 0.5x
Subtitles- subtitles off
Captions- captions off
- English
Chapters- Chapters
Cosine Rule (finding a length)
a2=b2+c2-2bc×cosACosine Rule (finding an angle)
cosA=a2+b2−c22abRemember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Cosine Rule (finding a length) to find the length of aa2 = b2+c2-2bc×cosA Cosine Rule Formula a2 = 172+202-2(17)(20)×cos48° Plug in the values a2 = 289+400-680×cos48° Evaluate a2 = 234 √a2 = √234 Take the square root of both sides a = 15.3 cm Rounded to a whole number a=15.3 cm -
Question 7 of 7
7. Question
Solve for side xRound off answer to 1 decimal place- x= (13.3) m
Correct
Excellent!
Incorrect
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find side xxsinX = zsinZ Sine Rule Formula xsin42° = 18sin65° Plug in the values x×sin65° = sin42°×18 Cross multiply x = sin42°×18sin65° Divide sin46° from each side to isolate x x = 13.3 m Rounded to 1 decimal place x=13.3 m
Quizzes
- Intro to Trigonometric Ratios (SOH CAH TOA) 1
- Intro to Trigonometric Ratios (SOH CAH TOA) 2
- Round Angles (Degrees, Minutes, Seconds)
- Evaluate Trig Expressions using a Calculator 1
- Evaluate Trig Expressions using a Calculator 2
- Trig Ratios: Solving for a Side 1
- Trig Ratios: Solving for a Side 2
- Trig Ratios: Solving for an Angle
- Angles of Elevation and Depression
- Trig Ratios Word Problems: Solving for a Side
- Trig Ratios Word Problems: Solving for an Angle
- Area of Non-Right Angled Triangles 1
- Area of Non-Right Angled Triangles 2
- Law of Sines: Solving for a Side
- Law of Sines: Solving for an Angle
- Law of Cosines: Solving for a Side
- Law of Cosines: Solving for an Angle
- Trigonometry Word Problems 1
- Trigonometry Word Problems 2
- Trigonometry Mixed Review: Part 1 (1)
- Trigonometry Mixed Review: Part 1 (2)
- Trigonometry Mixed Review: Part 1 (3)
- Trigonometry Mixed Review: Part 1 (4)
- Trigonometry Mixed Review: Part 2 (1)
- Trigonometry Mixed Review: Part 2 (2)
- Trigonometry Mixed Review: Part 2 (3)