A direct variation is a relationship between two variables, where if one increases the other also increases. Similarly, if one variable decreases the other also decreases.
First, solve for kk, the constant of variation, by plugging in the known values to the Direct Variation Formula.
yy
==
600600 km
xx
==
88 hours
yy
==
kkxx
Direct Variation Formula
600600
==
kk(8)(8)
Substitute known values
600600
==
8k8k
600600÷8÷8
==
8k8k÷8÷8
Divide both sides by 88
7575
==
kk
kk
==
7575
Next, rewrite the Direct Variation Formula with kk substituted.
yy
==
kxkx
yy
==
75x75x
Substitute kk
Finally, use the new formula and substitute 1111 hours
yy
==
75x75x
New formula
yy
==
75(11)75(11)
Substitute 1111 hours
yy
==
825825
Hence, the car would travel 825825 km in 1111 hours
825825kmkm
Question 3 of 3
3. Question
The time taken, TT, for a pendulum to swing varies directly at the square root of its length. If one swing of a 100100-centimetre pendulum takes 22 seconds, find the time taken for one swing of a 3636 centimetre pendulum.
A direct variation is a relationship between two variables, where if one increases the other also increases. Similarly, if one variable decreases the other also decreases.
First, rewrite the Direct Variation Formula according to the problem given.
TT
varies directly
at the square root of its length
TT
==
k√Lk√L
Insert kk, the constant of variation
Now, solve for kk by plugging in the known values to the new formula.
TT
==
22 seconds
LL
==
100100 cm
TT
==
kk√L√L
New formula
22
==
kk√100√100
Substitute known values
22
==
10k10k
22÷10÷10
==
10k10k÷10÷10
Divide both sides by 1010
0.20.2
==
kk
kk
==
0.20.2
Add in the value of kk to the new formula.
TT
==
k√Lk√L
TT
==
0.2√L0.2√L
Substitute kk
Finally, use the updated formula and substitute 3636cm to the length
TT
==
0.2√L0.2√L
Updated formula
TT
==
0.2√360.2√36
Substitute 3636cm
TT
==
0.2(6)0.2(6)
TT
==
1.21.2
Hence, the 3636 centimetre pendulum would take 1.21.2 seconds to do one full swing.