Inverse Variation 1
Try VividMath Premium to unlock full access
Time limit: 0
Quiz summary
0 of 4 questions completed
Questions:
 1
 2
 3
 4
Information
–
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Loading...
 1
 2
 3
 4
 Answered
 Review

Question 1 of 4
1. Question
Given the following, find the equation for the inverse variation and then solve for the missing `y` value`y=8` when `x=4``y=?` when `x=6`Write fractions in the format “a/b”
`(i)` Equation: `y=` (32/x)`(ii)` Missing value: `y=` (5 1/3)
Hint
Help VideoCorrect
Great Work!
Incorrect
Inverse Variation Formula
$$\color{#9a00c7}{y}=\frac{k}{\color{#004ec4}{x}}$$where `k≠0` and is the constant of variationRemember
An inverse variation is a relationship between two variables where if one decreases, the other increases. Similarly, if one variable increases, the other decreases.First, solve for `k`, the constant of variation, by plugging in the known values to the Inverse Variation Formula.`y` `=` `8` `x` `=` `4` `y` `=` $$\frac{k}{\color{#004ec4}{x}}$$ Inverse Variation Formula `8` `=` $$\frac{k}{\color{#004ec4}{4}}$$ Substitute known values `8``times4` `=` `k/(4)``times4` Multiply `4` to both sides `32` `=` `k` `k` `=` `32` Next, rewrite the Inverse Variation Formula with `k` substituted.`y` `=` `k/x` `y` `=` `(32)/x` Substitute `k` Finally, use the new formula and substitute `x=6``y` `=` `(32)/x` New formula `y` `=` `(32)/6` Substitute `x=6` `y` `=` `5 1/3` `(i)` Equation: `y=(32)/x``(ii)` Missing value: `y=5 1/3` 

Question 2 of 4
2. Question
Given the following, find the equation for the inverse variation and then solve for the missing `x` value`y=9.5` when `x=1``y=0.5` when `x=?`Write fractions in the format “a/b”
`(i)` Equation: `y=` (9.5/x)`(ii)` Missing value: `x=` (19)
Hint
Help VideoCorrect
Correct!
Incorrect
Inverse Variation Formula
$$\color{#9a00c7}{y}=\frac{k}{\color{#004ec4}{x}}$$where `k≠0` and is the constant of variationRemember
An inverse variation is a relationship between two variables where if one decreases, the other increases. Similarly, if one variable increases, the other decreases.First, solve for `k`, the constant of variation, by plugging in the known values to the Inverse Variation Formula.`y` `=` `9.5` `x` `=` `1` `y` `=` $$\frac{k}{\color{#004ec4}{x}}$$ Inverse Variation Formula `9.5` `=` $$\frac{k}{\color{#004ec4}{1}}$$ Substitute known values `9.5``times1` `=` `k/(1)``times1` Multiply `1` to both sides `9.5` `=` `k` `k` `=` `9.5` Next, rewrite the Inverse Variation Formula with `k` substituted.`y` `=` `k/x` `y` `=` `(9.5)/x` Substitute `k` Finally, use the new formula and substitute `y=0.5``y` `=` `(9.5)/x` New formula `0.5` `=` `(9.5)/x` Substitute `y=0.5` `0.5``times x` `=` `(9.5)/x``times x` Multiply `x` to both sides `0.5x` `=` `(9.5)` `0.5x``divide0.5` `=` `(9.5)``divide0.5` Divide both sides by `0.5` `x` `=` `19` `(i)` Equation: `y=(9.5)/x``(ii)` Missing value: `x=19` 

Question 3 of 4
3. Question
Given the following, find the equation for the inverse variation and then solve for the missing `x` value`y=6.8` when `x=4.2``y=3` when `x=?`Write fractions in the format “a/b”
`(i)` Equation: `y=` (28.56/x)`(ii)` Missing value: `x=` (9.52)
Hint
Help VideoCorrect
Keep Going!
Incorrect
Inverse Variation Formula
$$\color{#9a00c7}{y}=\frac{k}{\color{#004ec4}{x}}$$where `k≠0` and is the constant of variationRemember
An inverse variation is a relationship between two variables where if one decreases, the other increases. Similarly, if one variable increases, the other decreases.First, solve for `k`, the constant of variation, by plugging in the known values to the Inverse Variation Formula.`y` `=` `6.8` `x` `=` `4.2` `y` `=` $$\frac{k}{\color{#004ec4}{x}}$$ Inverse Variation Formula `6.8` `=` $$\frac{k}{\color{#004ec4}{4.2}}$$ Substitute known values `6.8``times4.2` `=` `k/(4.2)``times4.2` Multiply `4.2` to both sides `28.56` `=` `k` `k` `=` `28.56` Next, rewrite the Inverse Variation Formula with `k` substituted.`y` `=` `k/x` `y` `=` `(28.56)/x` Substitute `k` Finally, use the new formula and substitute `y=3``y` `=` `(28.56)/x` New formula `3` `=` `(28.56)/x` Substitute `y=3` `3``times x` `=` `(28.56)/x``times x` Multiply `x` to both sides `3x` `=` `28.56` `3x``divide3` `=` `28.56``divide3` Divide both sides by `3` `x` `=` `9.52` `(i)` Equation: `y=(28.56)/x``(ii)` Missing value: `x=9.52` 

Question 4 of 4
4. Question
Given the following, find the equation for the inverse variation and then solve for the missing `y` value`y=?` when `x=3``y=11` when `x=7`Write fractions in the format “a/b”
`(i)` Equation: `y=` (77/x)`(ii)` Missing value: `y=` (25 2/3)
Hint
Help VideoCorrect
Fantastic!
Incorrect
Inverse Variation Formula
$$\color{#9a00c7}{y}=\frac{k}{\color{#004ec4}{x}}$$where `k≠0` and is the constant of variationRemember
An inverse variation is a relationship between two variables where if one decreases, the other increases. Similarly, if one variable increases, the other decreases.First, solve for `k`, the constant of variation, by plugging in the known values to the Inverse Variation Formula.`y` `=` `11` `x` `=` `7` `y` `=` $$\frac{k}{\color{#004ec4}{x}}$$ Inverse Variation Formula `11` `=` $$\frac{k}{\color{#004ec4}{7}}$$ Substitute known values `11``times7` `=` `k/(7)``times7` Multiply `7` to both sides `77` `=` `k` `k` `=` `77` Next, rewrite the Inverse Variation Formula with `k` substituted.`y` `=` `k/x` `y` `=` `77/x` Substitute `k` Finally, use the new formula and substitute `x=3``y` `=` `77/x` New formula `y` `=` `77/3` Substitute `x=3` `y` `=` `25 2/3` `(i)` Equation: `y=77/x``(ii)` Missing value: `y=25 2/3` 