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Fraction Word Problems: Addition and Subtraction 2Fraction Word Problems: Addition and Subtraction 2
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Question 1 of 4
1. Question
Arnold decided to give out a certain amount of money. He gave `1/4` of this money to his daughter, `3/5` to his wife and the rest to a charity. What fraction of the money is left for the charity?Write fractions in the format “a/b” (3/20)
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Add fractions with unlike denominators by transforming the fractions so that they have like denominatorsFirst, list down the values stated in the problemDaughter `=` `1/4` Wife `=` `3/5` Use cross method to add the two fractions.First, multiply the two denominators. Use the product as a denominator for a new fraction.`1/4``+``3/5` `=` `☐/(4times5)` `=` `☐/20` To get the numerator, cross multiply the given addition problem and add the products.$$\frac{\color{#00880A}{1}}{\color{#9a00c7}{4}}+\frac{\color{#9a00c7}{3}}{\color{#00880A}{5}}$$ `=` $$\frac{(\color{#00880A}{1\times5})+(\color{#9a00c7}{4\times3})}{20}$$ `=` `(5+12)/20` `=` `17/20` Finally, subtract this fraction from `1`. `1` represents the whole sum of money`117/20` `=` `20/2017/20` Subtract the numerators `=` `3/20` Keep the same denominator Arnold would be giving `3/20` of the money to charity.`3/20` 
Question 2 of 4
2. Question
Georgia loves chocolate. She ate `1/3` of her chocolate bar, then gave away `1/4` to her friend. How much remains of her chocolate bar?Write fractions in the format “a/b” (5/12)
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Add fractions with unlike denominators by transforming the fractions so that they have like denominatorsFirst, list down the values stated in the problemAte `=` `1/3` Gave `=` `1/4` Use cross method to add the two fractions.First, multiply the two denominators. Use the product as a denominator for a new fraction.`1/3``+``1/4` `=` `☐/(3times4)` `=` `☐/12` To get the numerator, cross multiply the given addition problem and add the products.$$\frac{\color{#00880A}{1}}{\color{#9a00c7}{3}}+\frac{\color{#9a00c7}{1}}{\color{#00880A}{4}}$$ `=` $$\frac{(\color{#00880A}{1\times4})+(\color{#9a00c7}{3\times1})}{12}$$ `=` `(4+3)/12` `=` `7/12` Finally, subtract this fraction from `1`. `1` represents the whole chocolate bar`17/12` `=` `12/127/12` Subtract the numerators `=` `5/12` Keep the same denominator `5/12` remains of Georgia’s chocolate bar.`5/12` 
Question 3 of 4
3. Question
Julie’s fuel tank is half full. She went to some shops and used a further `1/5` of the tank. How much fuel remains in the tank?Write fractions in the format “a/b” (3/10)
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Add fractions with unlike denominators by transforming the fractions so that they have like denominatorsFirst, list down the values stated in the problemInitial amount of fuel that was used `=` `1/2` (Since the tank was half full) Further fuel used `=` `1/5` Use cross method to add the two fractions.First, multiply the two denominators. Use the product as a denominator for a new fraction.`1/2``+``1/5` `=` `☐/(2times5)` `=` `☐/10` To get the numerator, cross multiply the given addition problem and add the products.$$\frac{\color{#00880A}{1}}{\color{#9a00c7}{2}}+\frac{\color{#9a00c7}{1}}{\color{#00880A}{5}}$$ `=` $$\frac{(\color{#00880A}{1\times5})+(\color{#9a00c7}{2\times1})}{10}$$ `=` `(5+2)/10` `=` `7/10` Finally, subtract this fraction from `1`. `1` represents the whole sum of money`17/10` `=` `10/107/10` Subtract the numerators `=` `3/10` Keep the same denominator `3/10` of the fuel tank remains.`3/10` 
Question 4 of 4
4. Question
A bucket is half full. If `1` litre is added it becomes three quarters full. How many litres is in the bucket when it is full? (4)`L`
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Add fractions with unlike denominators by transforming the fractions so that they have like denominatorsFirst, list down the values stated in the problemInitial amount `=` `1/2` (half full) Amount after adding `1L` `=` `3/4` (three quarters full) We can find the fraction that is equivalent to `1L` by subtracting these fractionsSince `4` is a multiple of `2`, `4` is the `LCD``3/4````1/2` `=` $$\frac{3}{4}\frac{1\times\color{#CC0000}{2}}{2\times\color{#CC0000}{2}}$$ Multiply by `2` so that the denominator becomes `4` `=` $$\frac{3}{4}\frac{2}{4}$$ Subtract the numerators `=` $$\frac{1}{4}$$ Keep the same denominator This means that `1L` is equivalent to `1/4` of the bucket.Equate `1/4` and `1L` and multiply both sides so that `1/4` becomes `1`. Here, `1` represents a full bucket.`1/4` `=` `1L` `1/4``xx4` `=` `1L``xx4` `1/4xx4/1` `=` `4L` `4/4` `=` `4L` `1` `=` `4L` A full bucket contains `4L`.`4L`
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