Proportions 2
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Question 1 of 4
1. Question
Jane invested `$9000` for a business while Lorraine invested `$5000`. If Jane’s profit was `$3600`, how much would Lorraine’s profit be? `$` (2000)
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A ratio compares quantities of the same type given in the same units.Write the problem in equation form and let `x` be the unknown value`9000:5000` `=` `3600:x` Convert the ratios into fraction form and solve for `x`.`9000:5000` `=` `3600:x` `9000/5000` `=` `(3600)/x` Convert to fraction form `9/5` `=` `(3600)/x` Simplify `9(x)` `=` `3600(5)` Cross multiply `9x``divide9` `=` `18000``divide9` Divide both sides by `9` `x` `=` `2000` `$2000` 
Question 2 of 4
2. Question
A shop sold shoes at a ratio of `4` to males and `7` to females. If the total pairs of shoes sold to females was `28`, how many were sold to males? (16)
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A ratio compares quantities of the same type given in the same units.Write the problem in equation form and let `x` be the unknown value`4:7` `=` `x:28` Convert the ratios into fraction form and solve for `x`.`4:7` `=` `x:28` `4/7` `=` `x/(28)` Convert to fraction form `7(x)` `=` `4(28)` Cross multiply `7x``divide7` `=` `112``divide7` Divide both sides by `7` `x` `=` `16` `16` 
Question 3 of 4
3. Question
A sum of money is divided to a ratio of `3:4:5`. If the largest amount is `$20`, how much would the smallest amount be? `$` (12)
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A ratio compares quantities of the same type given in the same units.We are given the largest amount of money, which is `$20`Divide this value by the number of parts of its ratio, which is `5``20divide5` `=` `4` This would be the value of each part.Multiply this value by the number of parts of the smallest ratio, which is `3`.`3xx4` `=` `12` Therefore, the smallest amount in the ratio would be `$12`.`$12` 
Question 4 of 4
4. Question
The proper mixture of concrete requires `13` parts cement, `16` parts sand and `10` parts water. If the sand needed is `96 \text(kg),` then how much cement and water is needed?
`\text(Cement)=` (78)`\text(kg)``\text(Water)=` (60)`\text(kg)`
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A ratio compares quantities of the same type given in the same units.The amount of sand needed for the mixture is `96 \text(kg)`.Divide this value by the number of parts of its ratio, which is `16`.`96divide16` `=` `6` This would be the value of each part.Multiply this value by the number of parts of both cement and water.Cement:`13xx6` `=` `78` Water:`10xx6` `=` `60` `\text(Cement)=78 \text(kg)``\text(Water)=60 \text(kg)` 
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