Rates 4

Question 1 of 4

A dog is running at

30 km/hour

$30 \text(km/hour)$ . How long will the dog take to travel

120 km

$120 \text(km)$ ?

(4) $hours$ $\text(hours)$

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Mute

Speed-Distance-Time Formula

Speed = \frac{Distance}{Time}

$\color{#00880a}{\text{Speed}}=\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

First, derive the formula to solve for the time.

$\color{#00880a}{\text{Speed}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

$\color{#9a00c7}{\text{Distance}}$	$=$ $=$	$\color{#00880a}{\text{Speed}}\cdot\color{#e65021}{\text{Time}}$	Cross multiply

$\color{#e65021}{\text{Time}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#00880a}{\text{Speed}}}$	Divide both sides by Speed

Next, substitute the known values to the derived formula.

$Speed$ $\text(Speed)$	$=$ $=$	$30 km/hour$ $30 \text(km/hour)$
$Distance$ $\text(Distance)$	$=$ $=$	$120 km$ $120 \text(km)$

$\color{#e65021}{\text{Time}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#00880a}{\text{Speed}}}$

	$=$ $=$	$\frac{\color{#9a00c7}{120\;\text{km}}}{\color{#00880a}{30\;\text{km/hour}}}$	Substitute known values

	$=$ $=$	$4 hours$ $4 \text(hours)$	km cancels out

Time = 4 hours

$\text(Time)=4 \text(hours)$

Question 2 of 4

A jet flies at a speed of

680 km/hour

$680 \text(km/hour)$ . Use the speed-distance-time formula to determine how far it can travel in

30

$30$ minutes.

(340) $km$ $\text(km)$

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Mute

Speed-Distance-Time Formula

Speed = \frac{Distance}{Time}

$\color{#00880a}{\text{Speed}}=\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

First, derive the formula to solve for the distance.

$\color{#00880a}{\text{Speed}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

$\color{#9a00c7}{\text{Distance}}$	$=$ $=$	$\color{#00880a}{\text{Speed}}\cdot\color{#e65021}{\text{Time}}$	Cross multiply

Next, substitute the known values to the derived formula.

$Speed$ $\text(Speed)$	$=$ $=$	$\frac{680 km}{hour}$ $(680 \text(km))/(\text(hour))$

$Time$ $\text(Time)$	$=$ $=$	$\frac{1}{2} hour$ $1/2 \text(hour)$

$\color{#9a00c7}{\text{Distance}}$	$=$ $=$	$\color{#00880a}{\text{Speed}}\cdot\color{#e65021}{\text{Time}}$

	$=$ $=$	$\color{#00880a}{\frac{680\;\text{km}}{\text{hour}}}\cdot\color{#e65021}{\frac{1}{2}\text{hours}}$	Substitute known values

	$=$ $=$	$340 km$ $340 \text(km)$	Hours cancel out

Distance = 340 km

$\text(Distance)=340 \text(km)$

Question 3 of 4

A train travelled

360 km

$360\text(km)$ in

1

$1$ hour and

20

$20$ minutes. What is the speed of the train?

(270) $km/hour$ $\text(km/hour)$

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Mute

Speed-Distance-Time Formula

Speed = \frac{Distance}{Time}

$\color{#00880a}{\text{Speed}}=\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

First, convert the minutes into hours.

1 hour

$1 \text(hour)$

=

$=$

60 minutes

$60 \text(minutes)$

$20 \times \frac{1}{60}$ $20xx1/(60)$	$=$ $=$	$\frac{20}{60}$ $20/60$

	$=$ $=$	$\frac{1}{3}$ $1/3$	Simplify

The total time is

1 \frac{1}{3} hours

$1 1/3 \text(hours)$ .

Next, substitute the known values to the formula.

$Distance$ $\text(Distance)$	$=$ $=$	$360 km$ $360 \text(km)$

$Time$ $\text(Time)$	$=$ $=$	$1 \frac{1}{3} hour$ $1 1/3 \text(hour)$

$\color{#00880a}{\text{Speed}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

	$=$ $=$	$\frac{\color{#9a00c7}{360\;\text{km}}}{\color{#e65021}{1\frac{1}{3}\;\text{hours}}}$	Substitute known values

	$=$ $=$	$270 km/hour$ $270 \text(km/hour)$	Evaluate

Speed = 270 km/hour

$\text(Speed)=270 \text(km/hour)$

Question 4 of 4

A car is travelling at

80 km/hour

$80 \text(km/hour)$ . How long will it take to travel

500 km

$500 \text(km)$ ?

Round your answer in decimal form

(6.25) $hours$ $\text(hours)$

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Mute

Speed-Distance-Time Formula

Speed = \frac{Distance}{Time}

$\color{#00880a}{\text{Speed}}=\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

First, derive the formula to solve for the time.

$\color{#00880a}{\text{Speed}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#e65021}{\text{Time}}}$

$\color{#9a00c7}{\text{Distance}}$	$=$ $=$	$\color{#00880a}{\text{Speed}}\cdot\color{#e65021}{\text{Time}}$	Cross multiply

$\color{#e65021}{\text{Time}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#00880a}{\text{Speed}}}$	Divide both sides by Speed

Next, substitute the known values to the derived formula.

$Speed$ $\text(Speed)$	$=$ $=$	$80 km/hour$ $80 \text(km/hour)$
$Distance$ $\text(Distance)$	$=$ $=$	$500 km$ $500 \text(km)$

$\color{#e65021}{\text{Time}}$	$=$ $=$	$\frac{\color{#9a00c7}{\text{Distance}}}{\color{#00880a}{\text{Speed}}}$

	$=$ $=$	$\frac{\color{#9a00c7}{500\;\text{km}}}{\color{#00880a}{80\;\text{km/hour}}}$	Substitute known values

	$=$ $=$	$6.25 hours$ $6.25 \text(hours)$	km cancels out

Time = 6.25 hours

$\text(Time)=6.25 \text(hours)$

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1. Question

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Keep Going!

Speed-Distance-Time Formula

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Exceptional!

Speed-Distance-Time Formula

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Well Done!

Speed-Distance-Time Formula

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Speed-Distance-Time Formula

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