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Question 1 of 7
Which of the following shows the formula for the surface area of a cylinder?
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A surface area is the total area of the outside faces of a figure.
First, we need to show the surfaces of the cylinder.
Since we are looking for the area, we can use the formula for Area of a Circle for the two circles
|
Area |
= |
(π×r2)×2 |
Multiply by 2 since there are two circles |
Area |
= |
2πr2 |
Next, notice that the curved side creates a rectangle that has a length equal to the circumference of a circle
Hence, we can use the formula for the circumference of a circle as the value of length
|
Area |
= |
length × height |
Area of a Rectangle formula |
Area |
= |
(2πr)×h |
Substitute the circumference formula to length |
Area |
= |
2πrh |
Finally, add the two formula to get the formula for the Surface Area of a cylinder
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Question 2 of 7
What is the surface area of this cube?
Incorrect
Labelling the given lengths
Use the formula to find the surface area
SA |
= |
6×side2 |
Surface area of a cube formula |
|
|
= |
6×32 |
Plug in the known lengths |
|
|
= |
6×9 |
Simplify |
|
= |
54 |
|
= |
54 cm2 |
|
The given measurements are in centimetres, so the surface area is measured as centimetres squared
Volume=54 cm2
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Question 3 of 7
What is the surface area of this cube?
Incorrect
Labelling the given lengths
Use the formula to find the surface area
SA |
= |
6×side2 |
Surface area of a cube formula |
|
|
= |
6×62 |
Plug in the known lengths |
|
|
= |
6×36 |
Simplify |
|
= |
216 |
|
= |
216 m2 |
|
The given measurements are in metres, so the surface area is measured as metres squared
Volume=216 m2
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Question 4 of 7
Find the surface area of the Sphere
Round your answer to 1 decimal place
Use π=3.141592654
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Showing and Labelling the Surfaces
Use the formula to find the surface area of the sphere
SA |
= |
4×π×radius2 |
Surface Area formula |
SA |
= |
4×π×352 |
Plug in the known lengths |
SA |
= |
15393.804 |
SA |
= |
15393.8 cm2 |
Rounded to one decimal place |
The given measurements are in centimetres, so the area is measured as square centimetres
SA=15393.8 cm2
The answer will depend on which π you use.
In this solution we used: π=3.141592654.
π=3.141592654 |
15393.8 cm2 |
π=3.14 |
15386 cm2 |
π=227 |
15400 cm2 |
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Question 5 of 7
What is the surface area of this Rectangular Prism?
Incorrect
Labelling the given lengths
width=4
height=12
depth=9
Use the formula to find the surface area
SA |
= |
2×(width×height+depth×height+width×depth) |
|
|
= |
2×(4×12+9×12+4×9) |
|
|
= |
384 |
Simplify |
|
|
|
|
= |
384 cm2 |
|
The given measurements are in centimetres, so the surface area is measured as centimetres squared
Volume=384 cm2
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Question 6 of 7
Find the surface area of the Pyramid
The given measurements are in units
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Showing and Labelling the Surfaces
We need to add the areas of all the faces of the pyramid: the four triangles and the square base
Since the triangle sides are slanted, we need to find the slanted height (which is also the perpendicular height) of the triangles first.
Label the sides of the right triangle formed within the pyramid
Use the Pythagorean Theorem Formula to solve for c, which is equal to the height
a2+b2 |
= |
c2 |
Pythagoras’ Theorem Formula |
122+52 |
= |
h2 |
Plug in the known lengths |
169 |
= |
h2 |
height |
= |
13 cm |
Take the square root of both sides |
Next, solve for the area of the triangles using the Area of a Triangle formula
Note that there are four sides of the pyramid with the same lengths, so we will multiply this area by 4 for the surface area
Areatriangles |
= |
12×base×height |
|
|
= |
12×10×13=65 cm2 |
Now, solve for the area of the square base using the Area of a Square formula
Areasquare |
= |
side×side |
|
= |
10×10=100 cm2 |
Finally, add all the areas to find the surface area of the figure
SA |
= |
(4×65)+100 |
Plug in the areas |
SA |
= |
360 cm2 |
The given measurements are in centimetres, so the area is measured as square centimetres
SA=360 cm2
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Question 7 of 7
Find the surface area of the open Cylinder
Round your answer to 2 decimal places
Use π=3.141592654
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Showing and Labelling the Surfaces
We need to add the areas of all the faces of the figure: the curved face and the circular base
Since this is an Open Cylinder we will edit the original formula.
Surface Area of a Cylinder |
= |
2πrh+2πr2 |
Surface Area of an Open Cylinder |
= |
2πrh+πr2 |
Notice we eliminate the 2 |
Now, recall that the radius is equal to half of the diameter
radius |
= |
12×12 |
|
radius |
= |
6 |
Finally, use the formula to solve for the surface area of the open cylinder
SA |
= |
2πrh +πr2 |
Formula for the surface area |
SA |
= |
2×π×6×19 +π×62 |
Plug in the known lengths |
SA |
= |
829.38046 |
SA |
= |
829.38 m2 |
Rounded to two decimal places |
The given measurements are in metres, so the area is measured as square metres
SA=829.38 m2
The answer will depend on which π you use.
In this solution we used: π=3.141592654.
π=3.141592654 |
829.38 m2 |
π=3.14 |
828.96 m2 |
π=227 |
829.71 m2 |