Surface Area of Shapes 2
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Question 1 of 7
1. Question
Find the surface area of the figureRound your answer to two decimal places- Surface Area = (617.92) cm2
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Chapters- Chapters
Area of a Triangle Formula
Area =12×base×heightArea of a Rectangle Formula
Area =length×heightShowing and Labelling the Surfaces
We need to add the areas of all the faces of the figure: the two triangles and the three rectanglesFirst, to find the area of the triangle, get the height that is perpendicular to its base.Label the sides of the right triangle formed within a triangleUse the Pythagorean Theorem Formula to solve for a, which is equal to the heighta2+b2 = c2 Pythagoras’ Theorem Formula h2+42 = 72 Plug in the known lengths h2+16 = 49 Evaluate 42 and 72 h2 = 33 Subtract 16 from both sides height = 5.74 cm Take the square root of both sides Next, solve for the area of the triangles using the Area of a Triangle formulaNote that there are two triangles with the same lengths, so we will multiply this area by 2 for the surface areaAreatriangles = 12×base×height = 12×8×5.74=22.96 cm2 Now, solve for the area of the rectangles using the Area of a Rectangle formulaNote that there are two rectangles with the same lengths, so we will multiply the first area by 2 for the surface areaAreaequal rectangles = length×height = 7×26=182 cm2 Areamiddle rectangle = length×height = 8×26=208 cm2 Finally, add all the areas to find the surface area of the figureSA = (2×22.96)+(2×182)+208 Plug in the areas SA = 617.92 cm2 The given measurements are in centimetres, so the area is measured as square centimetresSA=617.92 cm2 -
Question 2 of 7
2. Question
What is the surface area of this Rectangular Prism?
- Surface Area= (320)mm2
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Surface Area of a Rectangular Prism
SA=2×(width×height+depth×height+width×depth)Labelling the given lengths
width=12height=7depth=4Use the formula to find the surface areaSA = 2×(width×height+depth×height+width×depth) Surface area of a Rectangular Prism formula = 2×(12×7+4×7+12×4) Plug in the known lengths = 320 Simplify = 320 mm2 The given measurements are in millimetres, so the surface area is measured as millimetres squaredVolume=320 mm2 -
Question 3 of 7
3. Question
Find the surface area of the ConeRound your answer to 1 decimal placeUse π=3.141592654- Surface Area = (7710.7, 7706.8, 7713.8) cm2
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Surface Area of a Closed Cone
SA =π×radius2 +π×radius×lengthWe need to used the slanted length of the coneShowing and Labelling the Surfaces
We need to add the areas of all the faces of the cone: the curved face and the circular baseFirst, recall that the radius is equal to half of the diameterradius = 12×52 radius = 26 Now, use can use the formula to find the surface area of the closed coneUse π=3.141592654 See π explainedSA = π×radius2 +π×radius×length Surface Area formula SA = π×262 +π×26×68.4 Plug in the known lengths SA = 7710.725 SA = 7710.7 cm2 Rounded to one decimal place The given measurements are in centimetres, so the area is measured as square centimetresSA=7710.7 cm2The answer will depend on which π you use.In this solution we used: π=3.141592654.Using Answer π=3.141592654 7710.7 cm2 π=3.14 7706.8 cm2 π=227 7713.8 cm2 -
Question 4 of 7
4. Question
What is the surface area of this cone?
Round your answer to 1 decimal placeUse π≈3.14- Surface Area= (653.1)m2
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Surface Area of a Cone
SA=π×radius2+π×radius×lengthLabelling the given lengths
length=18radius=8Use the formula to find the surface areaπ≈3.14SA = π×radius2+π×radius×length Surface area of a cone formula = 3.14×82+3.14×8×18 Plug in the known lengths = 3.14×64+3.14×8×18 Simplify = 200.96+452.16 = 653.1 m2 Rounded to 1 decimal place The given measurements are in metres, so the surface area is measured as metres squaredSurface Area=653.1 m2 -
Question 5 of 7
5. Question
What is the surface area of this cone?
Use π≈3.14- Surface Area= (785)mm2
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Surface Area of a Cone
SA=π×radius2+π×radius×lengthLabelling the given lengths
length=15diameter=20First, recall that the radius is equal to half the diameterradius = 12×20 radius = 10 Use the formula to find the surface areaπ≈3.14SA = π×radius2+π×radius×length Surface area of a cone formula = 3.14×102+3.14×10×15 Plug in the known lengths = 3.14×100+3.14×10×15 Simplify = 314+471 = 785 mm2 The given measurements are in millimetres, so the surface area is measured as millimetres squaredSurface Area=785 mm2 -
Question 6 of 7
6. Question
Find the surface area of the SphereRound your answer to 1 decimal placeUse π=3.141592654- Surface Area = (1520.5, 1519.8, 1521.1) cm2
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Surface Area of a Sphere
SA =4×π×radius2Showing and Labelling the Surfaces
First, recall that the radius is equal to half of the diameterradius = 12×22 radius = 11 Now, you can use the formula to find the surface area of the sphereUse π=3.141592654 See π explainedSA = 4×π×radius2 Surface Area formula SA = 4×π×112 Plug in the known lengths SA = 1520.53084 SA = 1520.5 cm2 Rounded to one decimal place The given measurements are in centimetres, so the area is measured as square centimetresSA=1520.5 cm2The answer will depend on which π you use.In this solution we used: π=3.141592654.Using Answer π=3.141592654 1520.5 cm2 π=3.14 1519.8 cm2 π=227 1521.1 cm2 -
Question 7 of 7
7. Question
What is the surface area of this sphere?
Round your answer to 1 decimal placeUse π≈3.14- Surface Area= (615.4)cm2
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Surface Area of a Sphere
SA=4×π×radius2Labelling the given lengths
diameter=14First, recall that the radius is equal to half the diameterradius = 12×14 radius = 7 Use the formula to find the surface areaπ≈3.14SA = 4×π×radius2 Surface area of a sphere formula = 4×3.14×72 Plug in the known lengths = 4×3.14×49 Simplify = 615.44 = 615.4 cm2 Rounded to 1 decimal place The given measurements are in centimetres, so the surface area is measured as centimetres squaredSurface Area=615.4 cm2
Quizzes
- Volume of Shapes 1
- Volume of Shapes 2
- Volume of Shapes 3
- Volume of Shapes 4
- Volume of Composite Shapes 1
- Volume of Composite Shapes 2
- Surface Area of Shapes 1
- Surface Area of Shapes 2
- Surface Area of Shapes 3
- Surface Area and Volume Mixed Review 1
- Surface Area and Volume Mixed Review 2
- Surface Area and Volume Mixed Review 3
- Surface Area and Volume Mixed Review 4