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Question 1 of 5
Find the volume of the figure
Incorrect
Labelling the given lengths
Smaller Rectangle
length=30
width=20
depth=12
Larger Rectangle
length=60
width=25 (55-30)
depth=12
First, find the area of the smaller rectangle
Area |
= |
length×width |
|
= |
30×20=600 cm2 |
Next, find the area of the larger rectangle
Area |
= |
length×width |
|
= |
60×25=1500 cm2 |
Next, add the area of the smaller rectangle and the area of the larger rectangle
|
= |
600+1500 |
Plug in the two areas |
|
= |
2100 cm2 |
Finally, multiply the area by the depth to find the volume
Volume |
= |
area×depth |
Finding the volume |
|
= |
2100×12 |
Plug in the known lengths |
|
= |
25200 cm3 |
The given measurements are in centimetres, so the volume is measured as centimetres cubed
Volume=25200 cm3
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Question 2 of 5
Find the volume of the figure
Round your answer to the nearest whole number
Use π=3.141592654
Incorrect
Labelling the given lengths
Cone
radius=18
height=62
Rectangular Prism
length=46
breadth=46
height=5
First, find the area of the rectangle
Area |
= |
length×breadth |
|
= |
46×46=2116 cm2 |
Next, multiply the area by the height to find the volume
Volume |
= |
area×height |
Finding the volume |
|
= |
2116×5 |
Plug in the known lengths |
|
= |
10580 cm3 |
Next, use the formula to find the volume of the cone
Volume |
= |
13×π×radius2×height |
|
|
= |
13×3.141592654×182×62 |
|
|
= |
21036.10441 cm3 |
Finally, add the volume of the cube and the volume of the cone
|
= |
10580+21036.10441 |
Plug in the two volumes |
|
= |
31616.10441 |
|
= |
31616 cm3 |
Rounded to the nearest whole number |
The given measurements are in centimetres, so the volume is measured as centimetres cubed
Volume=31616 cm3
The answer will depend on which π you use.
In this solution we used: π=3.141592654.
π=3.141592654 |
31616 cm3 |
π=3.14 |
31605 cm3 |
π=227 |
31625 cm3 |
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Question 3 of 5
Find the volume of the figure
Round your answer to 2 decimal places
Use π=3.141592654
Incorrect
Labelling the given lengths
radius=?
diameter=6
height=13
We need to add volume of the hemisphere and the cone
First, recall that the radius is equal to half of the diameter
Next, use the formula to find the volume of the hemisphere
Volume |
= |
12×43×π×radius3 |
|
|
= |
12×43×3.141592654×33 |
|
|
= |
56.54866 cm3 |
Next, use the formula to find the volume of the cone
Volume |
= |
13×π×radius2×height |
|
|
= |
13×3.141592654×32×13 |
|
|
= |
122.52211 cm3 |
Finally, add the volume of the sphere and the volume of the cone
|
= |
56.54866+122.52211 |
Plug in the two volumes |
|
= |
179.07078 |
|
= |
179.07 cm3 |
Rounded to 2 decimal places |
The given measurements are in centimetres, so the volume is measured as centimetres cubed
Volume=179.07 cm3
The answer will depend on which π you use.
In this solution we used: π=3.141592654.
π=3.141592654 |
179.07 cm3 |
π=3.14 |
178.98 cm3 |
π=227 |
179.14 cm3 |
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Question 4 of 5
Find the volume of the figure
Note: The cylinder is hollow
Round your answer to 2 decimal places
Use π=3.141592654
Incorrect
Labelling the given lengths
Outer Cylinder
radius=?
diameter=12
height=22
Inner Cylinder
radius=2
height=22
We need to find the volume of the figure, not including its hollow part
First, recall that the radius is equal to half of the diameter
radius |
= |
12×12 |
|
radius(Larger Circle) |
= |
6 |
Next, use the formula to find the area of the Outer Circle
Area |
= |
π×radius2 |
|
= |
3.141592654×62 |
|
= |
113.09733 cm2 |
Next, find the area of the Inner Circle
Area |
= |
π×radius2 |
|
= |
3.141592654×22 |
|
= |
12.56637 cm2 |
Now, subtract the area of the Inner Circle from the Outer Circle
|
= |
113.09733-12.56637 |
Plug in the two areas |
|
= |
100.53096 cm2 |
Finally, multiply the area by the height to find the volume
Volume |
= |
area×height |
Finding the volume |
|
= |
100.53096×22 |
Plug in the known lengths |
|
= |
2211.68122 |
|
= |
2211.68 cm3 |
Rounded to 2 decimal places |
The given measurements are in centimetres, so the volume is measured as centimetres cubed
Volume=2211.68 cm3
The answer will depend on which π you use.
In this solution we used: π=3.141592654.
π=3.141592654 |
2211.68 cm3 |
π=3.14 |
2210.56 cm3 |
π=227 |
2212.57 cm3 |
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Question 5 of 5
Find the volume of the figure
Round your answer to two decimal places
Incorrect
Labelling the given lengths
Short Cylinders
radius=?
diameter=12
height=2
Long Cylinder
radius=?
diameter=3
height=8
First, recall that the radius is equal to half of the diameter
radius |
= |
12×12 |
|
radius(short cylinders) |
= |
6 |
|
|
|
radius |
= |
12×3 |
|
radius(long cylinder) |
= |
1.5 |
Next, use the formula to find the volume of the two short cylinders
Volume |
= |
3.141592654×radius2×height |
|
= |
3.141592654×62×2 |
|
= |
226.19467 |
Since there are two short cylinders, we multiply our answer by two.
Volume |
= |
226.19467×2 |
|
= |
452.38934 cm3 |
Now, use the formula to find the volume of the long cylinder
Volume |
= |
3.141592654×radius2×height |
|
= |
3.141592654×1.52×8 |
|
= |
56.54866 cm3 |
Finally, add the volume of the two short cylinders and the volume of the long cylinder
|
= |
452.38934+56.54866 |
Plug in the two volumes |
|
= |
508.938 |
|
= |
508.94 cm3 |
Rounded to 2 decimal places |
The given measurements are in centimetres, so the volume is measured as centimetres cubed
Volume=508.94 cm3
The answer will depend on which π you use.
In this solution we used: π=3.141592654.
π=3.141592654 |
508.94 cm3 |
π=3.14 |
508.68 cm3 |
π=227 |
509.14 cm3 |