Area of Shapes 2

Topics

Pre - Algebra

Area

Area of Shapes

Area of Shapes 2

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Question 1 of 6

Find the area of the Rectangle

$Area =$ $\text(Area )=$ (28.6) $c m^{2}$ $cm^2$

Incorrect

Area of a Rectangle Formula

Area =

$\text(Area )=$ $base$ $\text(base)$

\times

$times$ $height$ $\text(height)$

Identify the known lengths

$base = 6.5$ $\text(base)=6.5$

$height = 4.4$ $\text(height)=4.4$

Solve for the area using the Area of a Rectangle formula

$Area$ $\text(Area)$	$=$ $=$	$base$ $\text(base)$ $\times$ $times$ $height$ $\text(height)$	Area of a Rectangle formula
	$=$ $=$	$6.5$ $6.5$ $\times$ $times$ $4.4$ $4.4$	Plug in the known lengths
	$=$ $=$	$28.6 c m^{2}$ $28.6 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

Area = 28.6 c m^{2}

$\text(Area)=28.6 cm^2$

Question 2 of 6

Find the area of the Triangle

The given measurements are in cm

$Area =$ $\text(Area )=$ (48) $c m^{2}$ $cm^2$

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Area of a Triangle Formula

Area = \frac{1}{2} \times

$\text(Area )=1/2 times$ $base$ $\text(base)$

\times

$times$ $height$ $\text(height)$

Identify the known lengths

$base = 12$ $\text(base)=12$

$height = 8$ $\text(height)=8$

Solve for the area using the Area of a Triangle formula

$Area$ $\text(Area)$	$=$ $=$	$\frac{1}{2} \times$ $1/2 times$ $base$ $\text(base)$ $\times$ $times$ $height$ $\text(height)$	Area of a Triangle formula

	$=$ $=$	$\frac{1}{2} \times$ $1/2 times$ $12$ $12$ $\times$ $times$ $8$ $8$	Plug in the known lengths

	$=$ $=$	$48 c m^{2}$ $48 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

Area = 48 c m^{2}

$\text(Area)=48 cm^2$

Question 3 of 6

Find the area of the Parallelogram

$Area =$ $\text(Area )=$ (5.89) $c m^{2}$ $cm^2$

Incorrect

Area of a Parallelogram Formula

Area =

$\text(Area )=$ $base$ $\text(base)$

\times

$times$ $height$ $\text(height)$

Identify the known lengths

$base = 3.1$ $\text(base)=3.1$

$height = 1.9$ $\text(height)=1.9$

Solve for the area using the Area of a Parallelogram formula

$Area$ $\text(Area)$	$=$ $=$	$base$ $\text(base)$ $\times$ $times$ $height$ $\text(height)$	Area of a Parallelogram formula
	$=$ $=$	$3.1$ $3.1$ $\times$ $times$ $1.9$ $1.9$	Plug in the known lengths
	$=$ $=$	$5.89 c m^{2}$ $5.89 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

Area = 5.89 c m^{2}

$\text(Area)=5.89 cm^2$

Question 4 of 6

Find the area of the Trapezium

$Area =$ $\text(Area )=$ (99) $c m^{2}$ $cm^2$

Incorrect

Area of a Trapezium Formula

Area = \frac{1}{2} \times

$\text(Area)=1/2 times$ $height$ $\text(height)$

\times (

$times ($ ${base}_{1}$ $\text(base)_1$

+

$+$ ${base}_{2}$ $\text(base)_2$

)

$)$

Identify the known lengths

$height = 9$ $\text(height)=9$

${base}_{1} = 8$ $\text(base)_1=8$

${base}_{2} = 14$ $\text(base)_2=14$

Solve for the area using the Area of a Trapezium formula

$Area$ $\text(Area)$	$=$ $=$	$\frac{1}{2} \times$ $1/2 times$ $height$ $\text(height)$ $\times ($ $times ($ ${base}_{1}$ $\text(base)_1$ $+$ $+$ ${base}_{2}$ $\text(base)_2$ $)$ $)$	Area of a Trapezium formula

	$=$ $=$	$\frac{1}{2} \times$ $1/2 times$ $9$ $9$ $\times ($ $times ($ $8$ $8$ $+$ $+$ $14$ $14$ $)$ $)$	Plug in the known lengths

	$=$ $=$	$99 c m^{2}$ $99 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

Area = 99 c m^{2}

$\text(Area)=99 cm^2$

Question 5 of 6

5. Question
Find the area of the Kite

The given measurements are in centimetres
- $Area =$ $\text(Area )=$ (120) $c m^{2}$ $cm^2$
Hint

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Area of a Kite Formula

$Area = \frac{1}{2} \times$ $\text(Area)= 1/2 times$ $x$ $x$ $\times$ $times$ $y$ $y$

Identify the known lengths

$x = 20$ $x=20$

$y = 6$ $y=6$ $+$ $+$ $6$ $6$ $=$ $=$ $12$ $12$

Solve for the area using the Area of a Kite formula

$Area$ $\text(Area)$ $=$ $=$ $\frac{1}{2} \times$ $1/2 times$ $x$ $x$ $\times$ $times$ $y$ $y$ Area of a Kite formula

$=$ $=$ $\frac{1}{2} \times$ $1/2 times$ $20$ $20$ $\times$ $times$ $12$ $12$ Plug in the known lengths

$=$ $=$ $120 c m^{2}$ $120 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

$Area = 120 c m^{2}$ $\text(Area)=120 cm^2$
Question 6 of 6

6. Question
Find the area of the Rhombus

The given measurements are in centimetres
- $Area =$ $\text(Area )=$ (75) $c m^{2}$ $cm^2$
Hint

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Area of a Rhombus Formula

$Area = \frac{1}{2} \times$ $\text(Area)= 1/2 times$ $x$ $x$ $\times$ $times$ $y$ $y$

Identify the known lengths

$x = 10$ $x=10$

$y = 15$ $y=15$

Solve for the area using the Area of a Rhombus formula

$Area$ $\text(Area)$ $=$ $=$ $\frac{1}{2} \times$ $1/2 times$ $x$ $x$ $\times$ $times$ $y$ $y$ Area of a Rhombus formula

$=$ $=$ $\frac{1}{2} \times$ $1/2 times$ $10$ $10$ $\times$ $times$ $15$ $15$ Plug in the known lengths

$=$ $=$ $75 c m^{2}$ $75 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

$Area = 75 c m^{2}$ $\text(Area)=75 cm^2$

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Quiz summary

Information

1. Question

Correct!

Area of a Rectangle Formula

Identify the known lengths

2. Question

Hint

Excellent!

Area of a Triangle Formula

Identify the known lengths

3. Question

Correct!

Area of a Parallelogram Formula

Identify the known lengths

4. Question

Hint

Well Done!

Area of a Trapezium Formula

Identify the known lengths

5. Question

Hint

Well Done!

Area of a Kite Formula

Identify the known lengths

6. Question

Hint

Great Work!

Area of a Rhombus Formula

Identify the known lengths

Quizzes

$Area$ $\text(Area)$	$=$ $=$	$\frac{1}{2} \times$ $1/2 times$ $x$ $x$ $\times$ $times$ $y$ $y$	Area of a Kite formula

	$=$ $=$	$\frac{1}{2} \times$ $1/2 times$ $20$ $20$ $\times$ $times$ $12$ $12$	Plug in the known lengths

	$=$ $=$	$120 c m^{2}$ $120 cm^2$