Area

## Area of Shapes 1

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- Question 1 of 5
##### 1. Question

Find the area of the Square- `\text(Area )=` (36) `m^2`

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Help Video##### Area of a Square Formula

`\text(Area )=`*`\text(side)`*`times`*`\text(side)`*In a regular square, all sides are equal##### Identify the known lengths

*`\text(side)=6`*Solve for the area using the Area of a Square formula`\text(Area)` `=` *`\text(side)`*`times`*`\text(side)`*Area of a Square formula `=` *`6`*`times`*`6`*Plug in the known lengths `=` `36` The given measurements are in metres, so the area is measured as square metres`\text(Area)=36 m^2` - Question 2 of 5
##### 2. Question

Find the area of the Triangle- `\text(Area )=` (36) `m^2`

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Help Video##### Area of a Triangle Formula

`\text(Area )=1/2 times`*`\text(base)`*`times`*`\text(height)`*##### Identify the known lengths

*`\text(base)=8`**`\text(height)=9`*Solve for the area using the Area of a Triangle formula`\text(Area)` `=` `1/2 times` *`\text(base)`*`times`*`\text(height)`*Area of a Triangle formula `=` `1/2 times ` *`8`*`times`*`9`*Plug in the known lengths `=` `36 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=36 m^2` - Question 3 of 5
##### 3. Question

Find the area of the ParallelogramThe given measurements are in centimetres- `\text(Area )=` (40) `cm^2`

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Help Video##### Area of a Parallelogram Formula

`\text(Area )=`*`\text(base)`*`times`*`\text(height)`*##### Identify the known lengths

*`\text(base)=8`**`\text(height)=5`*Solve for the area using the Area of a Parallelogram formula`\text(Area)` `=` *`\text(base)`*`times`*`\text(height)`*Area of a Parallelogram formula `=` *`8`*`times`*`5`*Plug in the known lengths `=` `40 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=40 cm^2` - Question 4 of 5
##### 4. Question

Find the area of the TrapeziumThe given measurements are in metres- `\text(Area )=` (36) `m^2`

##### Hint

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Help Video##### Area of a Trapezium Formula

`\text(Area)=1/2 times`*`\text(height)`*`times (`*`\text(base)_1`*`+`*`\text(base)_2`*`)`##### Identify the known lengths

*`\text(height)=4`**`\text(base)_1=6`**`\text(base)_2=12`*Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times` *`\text(height)`*`times (`*`\text(base)_1`*`+`*`\text(base)_2`*`)`Area of a Trapezium formula `=` `1/2 times` *`4`*`times (`*`6`*`+`*`12`*`)`Plug in the known lengths `=` `36 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=36 m^2` - Question 5 of 5
##### 5. Question

Find the area of the Kite- `\text(Area )=` (850) `cm^2`

##### Hint

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Help Video##### Area of a Kite Formula

`\text(Area)= 1/2 times`*`x`*`times`*`y`*##### Identify the known lengths

*`x=85`**`y=20`*Solve for the area using the Area of a Kite formula`\text(Area)` `=` `1/2 times` *`x`*`times`*`y`*Area of a Kite formula `=` `1/2 times ` *`85`*`times`*`20`*Plug in the known lengths `=` `850 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=850 cm^2`