Area of Shapes 4
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Question 1 of 5
1. Question
Find the area of the Trapezium `\text(Area )=` (45) `m^2`
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Area of a Trapezium Formula
`\text(Area)=1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)`Identify the known lengths
`\text(height)=6``\text(base)_1=5``\text(base)_2=10`Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)` Area of a Trapezium formula `=` `1/2 times``6``times (``5``+``10``)` Plug in the known lengths `=` `45 m^2` `\text(Area)=45 m^2` 
Question 2 of 5
2. Question
If the area of the Rhombus is `400 cm^2` and the diagonal `BD` is `50 cm`, find the length of the diagonal `AC` `AC=` (16) `cm`
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Area of a Rhombus Formula
`\text(Area)``=1/2 times``x``times``y`Identify the known lengths
`\text(Area)=400 cm^2``BD=x=50 cm`Let `AC=y`. To find the value of `AC`, solve using the Rhombus formula and get `y` by itself.Substitute the known values to the Area of a Rhombus formula`\text(Area)` `=` `1/2 times``x``times``y` Area of a Rhombus Formula `400` `=` `1/2 times``50``times``y` Evaluate `400` `=` `25 times y` Finally, get `y` on one side of the equation to get its value`400``divide 25` `=` `25 times y``divide 25` Divide both sides by `25` `16` `=` `25``times y``divide 25` `times 25 divide 25` cancels out `16` `=` `y` `y` `=` `16 cm` `AC` `=` `16 cm` `y=AC` `AC=16 cm` 
Question 3 of 5
3. Question
Find the area of the Trapezium `\text(Area )=` (110) `cm^2`
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Area of a Trapezium Formula
`\text(Area)=1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)`Identify the known lengths
`\text(height)=10``\text(base)_1=8``\text(base)_2=14`Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)` Area of a Trapezium formula `=` `1/2 times``10``times (``8``+``14``)` Plug in the known lengths `=` `110 cm^2` `\text(Area)=110 cm^2` 
Question 4 of 5
4. Question
Find the area of the Parallelogram `\text(Area )=` (459) `cm^2`
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Area of a Parallelogram Formula
`\text(Area )=``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=17``\text(height)=27`Solve for the area using the Area of a Parallelogram formula`\text(Area)` `=` `\text(base)``times``\text(height)` Area of a Parallelogram formula `=` `17``times``27` Plug in the known lengths `=` `459 cm^2` `\text(Area)=459 cm^2` 
Question 5 of 5
5. Question
Find the area of the Kite `\text(Area )=` (16) `m^2`
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Area of a Kite Formula
`\text(Area)= 1/2 times``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=4``\text(height)=8`Solve for the area using the Area of a Kite formula`\text(Area)` `=` `1/2 times``\text(base)``times``\text(height)` Area of a Kite formula `=` `1/2 times ``4``times``8` Plug in the known lengths `=` `16 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=16 m^2`