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Find the Fraction of a Quantity: Word Problems 1Find the Fraction of a Quantity: Word Problems 1
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Question 1 of 4
1. Question
In a pile of `21` books, `1/7` are fiction. How many fiction books are there?- (3) fiction books
Hint
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To multiply fractions, simply multiply the numerators and denominators separately.To get a fraction of a quantity, simply multiply the fraction to the quantity.Fraction of fiction books: `1/7`No. of books: `21``1/7``xx``21` `=` `1/7xx21/1` `=` $$\frac{1}{7\div\color{#CC0000}{7}}\times\frac{21\div\color{#CC0000}{7}}{1}$$ Reduce the fractions `=` `1/1xx3/1` `=` `3/1` `=` `3` fiction books In the pile of `21` books, `3` are fiction.`3` fiction books -
Question 2 of 4
2. Question
How many oranges are needed to feed `12` soccer players at half time if
each player eats `3/4` of an orange?- (9) oranges
Hint
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To multiply fractions, simply multiply the numerators and denominators separately.To get a fraction of a quantity, simply multiply the fraction to the quantity.Orange for each player: `3/4`No. of players: `12``3/4``xx``12` `=` `3/4xx12/1` `=` `36/4` `=` `36-:4` `=` `9` oranges `9` oranges are needed to feed `12` soccer players `3/4` of an orange each.`9` oranges -
Question 3 of 4
3. Question
Tom bought `2 4/5`kg of potatoes and used half of the bag. How many kilos of potatoes did he use?Hint
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To multiply fractions, simply multiply the numerators and denominators separately.Transforming a Fraction from Mixed to Improper
`=` $$\frac{(\color{#9a00c7}{c}\times\color{#00880A}{a})+\color{#007DDC}{b}}{\color{#9a00c7}{c}}$$ Transforming an Improper to Mixed Fraction
$$\frac{\color{#007DDC}{b}}{\color{#9a00c7}{c}}=\color{#00880A}{Q}\frac{\color{#e65021}{R}}{\color{#9a00c7}{c}}$$`(``b``-:``c``)=``Q` and `R` is the remainderTo get a fraction of a quantity, simply multiply the fraction to the quantity.Used potatoes: half or `1/2`Amount of potatoes: `2 4/5`kg`1/2``xx``2 4/5` `=` $$\frac{1}{2}\times\color{#00880A}{2}\frac{\color{#007DDC}{4}}{\color{#9a00c7}{5}}$$ Convert the fraction from mixed to improper `=` $$\frac{1}{2}\times\frac{(\color{#9a00c7}{5}\times\color{#00880A}{2})+\color{#007DDC}{4}}{\color{#9a00c7}{5}}$$ `=` $$\frac{1}{2}\times\frac{10+4}{5}$$ `=` $$\frac{1}{2}\times\frac{14}{5}$$ `=` $$\frac{1}{2\div\color{#CC0000}{2}}\times\frac{14\div\color{#CC0000}{2}}{5}$$ Reduce the fractions `=` `1/1xx7/5` `=` `7/5` Convert the fraction from improper to mixed by dividing the numerator by the denominatorArrange the numbers for long division`5` goes into `7` once. So write `1` above the line.Multiply `1` to `5` and write the answer below `7`Subtract `5` from `7` and write the answer one line belowSince `5` cannot go into `2` anymore, `2` is left as the Remainder and `1` is the QuotientSubstitute values into the given formula$$\frac{\color{#007DDC}{b}}{\color{#9a00c7}{c}}$$ `=` $$\color{#00880A}{Q}\frac{\color{#e65021}{R}}{\color{#9a00c7}{c}}$$ $$\frac{\color{#007DDC}{7}}{\color{#9a00c7}{5}}$$ `=` $$\color{#00880A}{1}\frac{\color{#e65021}{2}}{\color{#9a00c7}{5}}$$ Tom used `1 2/5kg`.`1 2/5kg` of potatoes -
Question 4 of 4
4. Question
From a squad of `15` players, `1/3` are sick. How many are healthy?- (10) players
Hint
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To multiply fractions, simply multiply the numerators and denominators separately.First, get the fraction of healthy players in the squad.Total population: `3/3`Fraction of sick: `1/3``3/3-1/3` `=` `2/3` `2/3` of the squad are healthy.To get a fraction of a quantity, simply multiply the fraction to the quantity.Fraction of healthy players: `2/3`Total no. of players: `15``2/3``xx``15` `=` `2/3xx15/1` `=` $$\frac{2}{3\div\color{#CC0000}{3}}\times\frac{15\div\color{#CC0000}{3}}{1}$$ Reduce the fractions `=` `2/1xx5/1` `=` `10/1` `=` `10` players `10` players in the squad are healthy.`10` players
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- Comparing Fractions 1
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- Mixed and Improper Fractions 1
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- Add and Subtract Fractions 1
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- Add and Subtract Fractions 4
- Multiply and Divide Fractions 1
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