Two Step Equations 3

Topics

Algebra 1

Equations

Two Step Equations

Two Step Equations 3

Try VividMath Premium to unlock full access

Start Free Trial

Lets see your results!

Points

Score

Time

Retry Quiz

Answered
Review

Question 1 of 5

1. Question
Solve

$- 2 y - 13 = - 11$ $-2y-13=-11$
- $y =$ $y=$ (-1)
Hint

Help Video
Correct

Fantastic!
Incorrect
Need Text
Play
Current Time 0:00
/
Duration Time 0:00
Remaining Time -0:00
Stream TypeLIVE
Loaded: 0%
Progress: 0%
0:00
Fullscreen
Video Acceleration:
On
Off

00:00
Mute
Playback Rate
1x
2x
1.5x
1.25x
1x
0.75x
0.5x
Subtitles
subtitles off
Captions
captions off
English
Chapters
Chapters

Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

To solve for $y$ $y$ , it needs to be alone on one side.

Start by moving $13$ $13$ to the other side by adding $13$ $13$ to both sides of the equation.

$- 2$ $-2$ $y$ $y$ $- 13$ $-13$ $=$ $=$ $- 11$ $-11$

$- 2$ $-2$ $y$ $y$ $- 13$ $-13$ $+ 13$ $+13$ $=$ $=$ $- 11$ $-11$ $+ 13$ $+13$

$- 2$ $-2$ $y$ $y$ $=$ $=$ $2$ $2$ $- 13 + 13$ $-13+13$ cancels out

Next, remove $- 2$ $-2$ by dividing both sides of the equation by $- 2$ $-2$ .

$- 2$ $-2$ $y$ $y$ $=$ $=$ $2$ $2$

$- 2$ $-2$ $y$ $y$ $\div - 2$ $-:-2$ $=$ $=$ $2$ $2$ $\div - 2$ $-:-2$

$y$ $y$ $=$ $=$ $- 1$ $-1$ $- 2 \div - 2$ $-2-:-2$ cancels out

Check our work

To confirm our answer, substitute $y = - 1$ $y=-1$ to the original equation.

$- 2 y - 13$ $-2y-13$ $=$ $=$ $- 11$ $-11$

$- 2 (- 1) - 13$ $-2(-1)-13$ $=$ $=$ $- 11$ $-11$ Substitute $y = - 1$ $y=-1$

$2 - 13$ $2-13$ $=$ $=$ $- 11$ $-11$

$- 11$ $-11$ $=$ $=$ $- 11$ $-11$

Since the equation is true, the answer is correct.

$y = - 1$ $y=-1$
Question 2 of 5

2. Question
Solve for $r$ $r$

$- 4 r - 1 = 31$ $-4r-1=31$
- $r =$ $r=$ (-8)
Correct

Well Done!

Incorrect

To solve for $r$ $r$ , get $r$ $r$ by itself

Add $1$ $1$ to both sides of the equation

$- 4 r - 1$ $-4r-1$ $+ 1$ $+1$ $=$ $=$ $31$ $31$ $+ 1$ $+1$

$- 4 r$ $-4r$ $- 1$ $-1$ $+ 1$ $+1$ $=$ $=$ $32$ $32$ $- 1 + 1$ $-1+1$ cancels out

$- 4 r$ $-4r$ $=$ $=$ $32$ $32$

Finally, divide both sides of the equation by $- 4$ $-4$

$- 4 r$ $-4r$ $\div - 4$ $divide -4$ $=$ $=$ $32$ $32$ $\div - 4$ $divide -4$

$- 4$ $-4$ $r$ $r$ $\div - 4$ $divide -4$ $=$ $=$ $- 8$ $-8$ $- 4 \div - 4$ $-4 divide -4$ cancels out

$r$ $r$ $=$ $=$ $- 8$ $-8$

$r = - 8$ $r=-8$

Question 3 of 5

Solve

\frac{x}{3} + 4 = 7

$x/3 +4=7$

$x =$ $x=$ (9)

Incorrect

Need Text

Play

Remaining Time -0:00

Stream TypeLIVE

Loaded: 0%

Progress: 0%

0:00

Fullscreen

00:00

Mute

Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

To solve for $x$ $x$ , it needs to be alone on one side.

Start by moving

4

$4$ to the other side by subtracting

4

$4$ from both sides of the equation.

$\frac{\color{#00880A}{x}}{3}+4$	$=$ $=$	$7$ $7$

$\frac{\color{#00880A}{x}}{3}+4\color{#CC0000}{-4}$	$=$ $=$	$7$ $7$ $- 4$ $-4$

$\frac{\color{#00880A}{x}}{3}$	$=$ $=$	$3$ $3$	$4 - 4$ $4-4$ cancels out

Next, remove

\frac{1}{3}

$1/3$ by multiplying both sides of the equation by

3

$3$ .

$\frac{\color{#00880A}{x}}{3}$	$=$ $=$	$3$ $3$

$\frac{\color{#00880A}{x}}{3}\color{#CC0000}{\times3}$	$=$ $=$	$3$ $3$ $\times 3$ $xx3$

$x$ $x$	$=$ $=$	$9$ $9$	$\frac{1}{3} \times 3$ $1/3 times3$ cancels out

Check our work

To confirm our answer, substitute

x = 9

$x=9$ to the original equation.

$\frac{x}{3} + 4$ $x/3 +4$	$=$ $=$	$7$ $7$

$\frac{9}{3} + 4$ $9/3 +4$	$=$ $=$	$7$ $7$	Substitute $x = 9$ $x=9$

$3 + 4$ $3+4$	$=$ $=$	$7$ $7$
$7$ $7$	$=$ $=$	$7$ $7$

Since the equation is true, the answer is correct.

x = 9

$x=9$

Question 4 of 5

Solve

\frac{x}{7} + 3 = - 2

$x/7 +3=-2$

$x =$ $x=$ (-35)

Incorrect

Need Text

Play

Remaining Time -0:00

Stream TypeLIVE

Loaded: 0%

Progress: 0%

0:00

Fullscreen

00:00

Mute

Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

To solve for $x$ $x$ , it needs to be alone on one side.

Start by moving

3

$3$ to the other side by subtracting

3

$3$ from both sides of the equation.

$\frac{\color{#00880A}{x}}{7}+3$	$=$ $=$	$- 2$ $-2$

$\frac{\color{#00880A}{x}}{7}+3\color{#CC0000}{-3}$	$=$ $=$	$- 2$ $-2$ $- 3$ $-3$

$\frac{\color{#00880A}{x}}{7}$	$=$ $=$	$- 5$ $-5$	$3 - 3$ $3-3$ cancels out

Next, remove

\frac{1}{7}

$1/7$ by multiplying both sides of the equation by

7

$7$ .

$\frac{\color{#00880A}{x}}{7}$	$=$ $=$	$- 5$ $-5$

$\frac{\color{#00880A}{x}}{7}\color{#CC0000}{\times7}$	$=$ $=$	$- 5$ $-5$ $\times 7$ $xx7$

$x$ $x$	$=$ $=$	$- 35$ $-35$	$\frac{1}{7} \times 7$ $1/7 times7$ cancels out

Check our work

To confirm our answer, substitute

x = - 35

$x=-35$ to the original equation.

$\frac{x}{7} + 3$ $x/7 +3$	$=$ $=$	$- 2$ $-2$

$\frac{- 35}{7} + 3$ $(-35)/7 +3$	$=$ $=$	$- 2$ $-2$	Substitute $x = - 35$ $x=-35$

$- 5 + 3$ $-5+3$	$=$ $=$	$- 2$ $-2$
$- 2$ $-2$	$=$ $=$	$- 2$ $-2$

Since the equation is true, the answer is correct.

x = - 35

$x=-35$

Question 5 of 5

Solve

\frac{t}{5} - 3 = - 6

$t/5 -3=-6$

$t =$ $t=$ (-15)

Incorrect

Need Text

Play

Remaining Time -0:00

Stream TypeLIVE

Loaded: 0%

Progress: 0%

0:00

Fullscreen

00:00

Mute

Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

To solve for $t$ $t$ , it needs to be alone on one side.

Start by moving

3

$3$ to the other side by adding

3

$3$ to both sides of the equation.

$\frac{\color{#00880A}{t}}{5}-3$	$=$ $=$	$- 6$ $-6$

$\frac{\color{#00880A}{t}}{5}-3\color{#CC0000}{+3}$	$=$ $=$	$- 6$ $-6$ $+ 3$ $+3$

$\frac{\color{#00880A}{t}}{5}$	$=$ $=$	$- 3$ $-3$	$- 3 + 3$ $-3+3$ cancels out

Next, remove

\frac{1}{5}

$1/5$ by multiplying both sides of the equation by

5

$5$ .

$\frac{\color{#00880A}{t}}{5}$	$=$ $=$	$- 3$ $-3$

$\frac{\color{#00880A}{t}}{5}\color{#CC0000}{\times5}$	$=$ $=$	$- 3$ $-3$ $\times 5$ $xx5$

$t$ $t$	$=$ $=$	$- 15$ $-15$	$\frac{1}{5} \times 5$ $1/5 times5$ cancels out

Check our work

To confirm our answer, substitute

t = - 15

$t=-15$ to the original equation.

$\frac{t}{5} - 3$ $t/5 -3$	$=$ $=$	$- 6$ $-6$

$\frac{- 15}{5} - 3$ $(-15)/5 -3$	$=$ $=$	$- 6$ $-6$	Substitute $t = - 15$ $t=-15$

$- 3 - 3$ $-3-3$	$=$ $=$	$- 6$ $-6$
$- 6$ $-6$	$=$ $=$	$- 6$ $-6$

Since the equation is true, the answer is correct.

$t=-15$

Two Step Equations 3

Try VividMath Premium to unlock full access

Quiz summary

Information

1. Question

Hint

Fantastic!

Inverse Operations

2. Question

Well Done!

3. Question

Hint

Good Job!

Inverse Operations

4. Question

Hint

Great Work!

Inverse Operations

5. Question

Hint

Excellent!

Inverse Operations

Quizzes

$- 2$ $-2$ $y$ $y$ $- 13$ $-13$	$=$ $=$	$- 11$ $-11$
$- 2$ $-2$ $y$ $y$ $- 13$ $-13$ $+ 13$ $+13$	$=$ $=$	$- 11$ $-11$ $+ 13$ $+13$
$- 2$ $-2$ $y$ $y$	$=$ $=$	$2$ $2$	$- 13 + 13$ $-13+13$ cancels out

$- 2 y - 13$ $-2y-13$	$=$ $=$	$- 11$ $-11$
$- 2 (- 1) - 13$ $-2(-1)-13$	$=$ $=$	$- 11$ $-11$	Substitute $y = - 1$ $y=-1$
$2 - 13$ $2-13$	$=$ $=$	$- 11$ $-11$
$- 11$ $-11$	$=$ $=$	$- 11$ $-11$

$- 4 r - 1$ $-4r-1$ $+ 1$ $+1$	$=$ $=$	$31$ $31$ $+ 1$ $+1$
$- 4 r$ $-4r$ $- 1$ $-1$ $+ 1$ $+1$	$=$ $=$	$32$ $32$	$- 1 + 1$ $-1+1$ cancels out
$- 4 r$ $-4r$	$=$ $=$	$32$ $32$

$- 4 r$ $-4r$ $\div - 4$ $divide -4$	$=$ $=$	$32$ $32$ $\div - 4$ $divide -4$
$- 4$ $-4$ $r$ $r$ $\div - 4$ $divide -4$	$=$ $=$	$- 8$ $-8$	$- 4 \div - 4$ $-4 divide -4$ cancels out
$r$ $r$	$=$ $=$	$- 8$ $-8$