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Question 1 of 4
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
To solve for y, it needs to be alone on one side.
Start by expanding the left side of the equation by using the Distributive Property.
-7(3-y) |
= |
-28 |
-7(3)-(-7)(y) |
= |
-28 |
-21+7y |
= |
-28 |
Next, move -21 to the other side by adding 21 to both sides of the equation.
-21+7y |
= |
-28 |
-21+7y +21 |
= |
-28 +21 |
7y |
= |
-7 |
-21+21 cancels out |
Finally, remove 7 by dividing both sides of the equation by 7.
7y |
= |
-7 |
7y÷7 |
= |
-7÷7 |
y |
= |
-1 |
7÷7 cancels out |
Check our work
To confirm our answer, substitute y=-1 to the original equation.
-7(3-y) |
= |
-28 |
-7[3-(-1)] |
= |
-28 |
Substitute y=-1 |
-7(3+1) |
= |
-28 |
-7(4) |
= |
-28 |
-28 |
= |
-28 |
Since the equation is true, the answer is correct.
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Question 2 of 4
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To solve for x, get x by itself
Subtract 5 from both sides of the equation
5-(3-2x) -5 |
= |
10 -5 |
5-(3-2x)-5 |
= |
10 -5 |
5-5 cancels out |
-3+2x |
= |
5 |
Distribute negative sign |
Next, add 3 to both sides of the equation
-3+2x +3 |
= |
5 +3 |
-3+2x +3 |
= |
5 +3 |
-3+3 cancels out |
2x |
= |
8 |
Finally, divide both sides of the equation by 2
2x÷2 |
= |
8÷2 |
2x÷2 |
= |
8÷2 |
×2÷2 cancels out |
x |
= |
4 |
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Question 3 of 4
Incorrect
To solve for k, get k by itself
Distribute the value inside the parenthesis.
-9(-8+k) |
= |
252 |
((-8)×(-9))+(k×(-9)) |
= |
252 |
72-9k |
= |
252 |
Get the k variable on one side of the equation
72-9k -72 |
= |
252 -72 |
Subtract 72 from both sides |
72-9k -72 |
= |
252 -72 |
72-72 cancels out |
-9k |
= |
180 |
-9k÷(-9) |
= |
180÷(-9) |
Divide both sides by -9 |
-9k÷(-9) |
= |
180÷(-9) |
×(-9)÷(-9) cancels out |
k |
= |
-20 |
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Question 4 of 4
Solve for a
-12(a+11)=-108
Incorrect
To solve for a, get a by itself
Distribute the value inside the parenthesis.
-12(a+11) |
= |
-108 |
(a×(-12))+(11×(-12)) |
= |
-108 |
-12a-132 |
= |
-108 |
Get the k variable on one side of the equation
-12a-132 +132 |
= |
-108 +132 |
Add 132 to both sides |
-12a-132 +132 |
= |
-108 +132 |
-132+132 cancels out |
-12a |
= |
24 |
-12a÷(-12) |
= |
24÷(-12) |
Divide both sides by -12 |
-12a÷(-12) |
= |
24÷(-12) |
×(-12)÷(-12) cancels out |
a |
= |
-2 |