Compass Bearings and True Bearings 1

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Question 1 of 5

1. Question
Using the image below, find the value of the following:
- $(i)$ Bearing of A from O $=$ (60) $°$
  
  $(ii)$ Bearing of B from O $=$ (199) $°$
  
  $(iii)$ Bearing of C from O $=$ (328) $°$
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When solving for bearings, start from North and move clockwise.

$(i)$    Bearing of $A$ from $O$

Notice that when starting from North and heading to East, the two lines form a complementary angle.

Since complementary angles add up to $90°$ , we can simply subtract the measure of $angle A O E$ , which is $30°$ , to get the bearing of $A$ from $O$ .

$90°-30°$ $=$ $60°$

$(ii)$    Bearing of $B$ from $O$

Notice that when starting from North and heading to South, the two lines form a supplementary angle.

Since supplementary angles add up to $180°$ , we can simply add the measure of $angle S O B$ , which is $19°$ , to get the bearing of $B$ from $O$ .

$180°+19°$ $=$ $199°$

$(iii)$    Bearing of $C$ from $O$

Notice that when starting from North and heading all the way back to North, it forms a revolution.

Since a revolution is equal to $360°$ , we can simply subtract the measure of $angle C O N$ , which is $32°$ , to get the bearing of $C$ from $O$ .

$360°-32°$ $=$ $328°$

$(i) 60°$

$(ii) 199°$

$(iii) 328°$
Question 2 of 5

2. Question
Find the compass bearing and true bearing of $A$ from $O$
- $(i)$ Compass Bearing $=$ (N) (19) $°$ (E)
  
  $(ii)$ True Bearing $=$ (19) $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $=N$ __ $W$

Northeast Quadrant $=N$ __ $E$

Southwest Quadrant $=S$ __ $W$

Southeast Quadrant $=S$ __ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $\text(Compass Bearing)$

Notice that line $A$ is located on the Northeast Quadrant.

Using the chart, we can write the compass bearing of $A$ from $O$ by using $N$ __ $E$ . Then get the angle that spans from the vertical line ( $N$ ) to $A$ , which is $19°$

Therefore, the compass bearing of $A$ from $O$ is $N 19° E$

$(ii)$ $\text(True Bearing)$

Notice that line $A$ is $19°$ from the starting point, which is from the North line.

That means that the true bearing of $A$ from $O$ is simply $19°T$ .

$T$ stands for True North.

$(i)$ Compass Bearing $= N 19° E$

$(ii)$ True Bearing $=19°T$
Question 3 of 5

3. Question
Find the compass bearing and true bearing of $A$ from $O$
- $(i)$ Compass Bearing $=$ (N) (34) $°$ (W)
  
  $(ii)$ True Bearing $=$ (326) $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $=N$ __ $W$

Northeast Quadrant $=N$ __ $E$

Southwest Quadrant $=S$ __ $W$

Southeast Quadrant $=S$ __ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $\text(Compass Bearing)$

Notice that line $A$ is located on the Northwest Quadrant.

Using the chart, we can write the compass bearing of $A$ from $O$ by using $N$ __ $W$ . Then get the angle that spans from the vertical line ( $N$ ) to $A$ , which is $34°$

Therefore, the compass bearing of $A$ from $O$ is $N 34° W$

$(ii)$ $\text(True Bearing)$

Notice that when starting from North and heading all the way back to North, it forms a revolution.

Since a revolution is equal to $360°$ , we can simply subtract the measure of $angle A O N$ , which is $34°$ , to get the bearing of $A$ from $O$ .

Don’t forget to add $T$ to the bearing to indicate True North.

$360°-34°$ $=$ $326°T$

$(i)$ Compass Bearing $= N 34° W$

$(ii)$ True Bearing $=326°T$
Question 4 of 5

4. Question
Find the compass bearing and true bearing of $A$ from $O$
- $(i)$ Compass Bearing $=$ (N) (73) $°$ (W)
  
  $(ii)$ True Bearing $=$ (287) $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $=N$ __ $W$

Northeast Quadrant $=N$ __ $E$

Southwest Quadrant $=S$ __ $W$

Southeast Quadrant $=S$ __ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $\text(Compass Bearing)$

Notice that line $A$ is located on the Northwest Quadrant.

Using the chart, we can write the compass bearing of $A$ from $O$ by using $N$ __ $W$ . Then get the angle that spans from the vertical line ( $N$ ) to $A$ .

Notice that line $N$ and line $W$ form a complementary angle. Therefore, we can find the value of the angle by subtracting $17°$ from the value of a complementary angle, which is $90°$ .

$90°-17°$ $=$ $73°$

Therefore, the compass bearing of $A$ from $O$ is $N 73° W$

$(ii)$ $\text(True Bearing)$

Notice that when starting from North and heading all the way back to North, it forms a revolution.

Since a revolution is equal to $360°$ , we can simply subtract the measure of $angle A O N$ , which is $73°$ , to get the bearing of $A$ from $O$ .

Don’t forget to add $T$ to the bearing to indicate True North.

$360°-73°$ $=$ $287°T$

Alternatively, we can add the value of $3$ quadrants and $17°$ to get the same value.

$(3xx90°)+17°$ $=$ $270°+17°$

$=$ $287°T$

$(i)$ Compass Bearing $= N 73° W$

$(ii)$ True Bearing $=287°T$
Question 5 of 5

5. Question
Find the compass bearing and true bearing of $A$ from $O$
- $(i)$ Compass Bearing $=$ (S) (12) $°$ (E)
  
  $(ii)$ True Bearing $=$ (168) $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $=N$ __ $W$

Northeast Quadrant $=N$ __ $E$

Southwest Quadrant $=S$ __ $W$

Southeast Quadrant $=S$ __ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $\text(Compass Bearing)$

Notice that line $A$ is located on the Southeast Quadrant.

Using the chart, we can write the compass bearing of $A$ from $O$ by using $S$ __ $E$ . Then get the angle that spans from the vertical line ( $N$ ) to $A$ .

Notice that line $N$ and line $W$ form a supplementary angle. Therefore, we can find the value of the angle by subtracting $168°$ from the value of a supplementary angle, which is $180°$ .

$180°-168°$ $=$ $12°$

Therefore, the compass bearing of $A$ from $O$ is $S 12° E$

$(ii)$ $\text(True Bearing)$

Starting clockwise from North, line $A$ gives us $168°$ .

Therefore, the true bearing of $A$ from $O$ is $168°T$

$(i)$ Compass Bearing $= S 12° E$

$(ii)$ True Bearing $=168°T$

Compass Bearings and True Bearings 1

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Quiz summary

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1. Question

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2. Question

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Compass Bearing Quadrants

3. Question

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Compass Bearing Quadrants

4. Question

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Compass Bearing Quadrants

5. Question

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Compass Bearing Quadrants

Quizzes

$(3xx90°)+17°$	$=$	$270°+17°$
	$=$	$287°T$