Area of Shapes Mixed Review 1
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Question 1 of 6
1. Question
Find the area of the Trapezium
The given measurements are in metres- `\text(Area )=` (80) `m^2`
Hint
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Area of a Trapezium Formula
`\text(Area)=1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)`Identify the known lengths
`\text(height)=8``\text(base)_1=7``\text(base)_2=13`
Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)` Area of a Trapezium formula `=` `1/2 times``8``times (``7``+``13``)` Plug in the known lengths `=` `80 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=80 m^2` -
Question 2 of 6
2. Question
Find the area of the Trapezium
- `\text(Area )=` (72) `cm^2`
Correct
Nice Job!
Incorrect
Area of a Trapezium Formula
`\text(Area)=1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)`Identify the known lengths
`\text(height)=6``\text(base)_1=9``\text(base)_2=15`
Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)` Area of a Trapezium formula `=` `1/2 times``6``times (``9``+``15``)` Plug in the known lengths `=` `72 cm^2` `\text(Area)=72 cm^2` -
Question 3 of 6
3. Question
Find the area of the Parallelogram
- `\text(Area )=` (108) `m^2`
Hint
Help VideoCorrect
Well Done!
Incorrect
Area of a Parallelogram Formula
`\text(Area )=``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=12``\text(height)=9`
Solve for the area using the Area of a Parallelogram formula`\text(Area)` `=` `\text(base)``times``\text(height)` Area of a Parallelogram formula `=` `12``times``9` Plug in the known lengths `=` `108 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=108 m^2` -
Question 4 of 6
4. Question
Find the area of the Kite
- `\text(Area )=` (88) `cm^2`
Correct
Correct!
Incorrect
Area of a Kite Formula
`\text(Area)= 1/2 times``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=8``\text(height)=22`Solve for the area using the Area of a Kite formula`\text(Area)` `=` `1/2 times``\text(base)``times``\text(height)` Area of a Kite formula `=` `1/2 times ``8``times``22` Plug in the known lengths `=` `88 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=88 cm^2` -
Question 5 of 6
5. Question
Find the area of the Rhombus
The given measurements are in metres- `\text(Area )=` (152) `m^2`
Correct
Great Work!
Incorrect
Area of a Rhombus Formula
`\text(Area)= 1/2 times``x``times``y`Identify the known lengths
`x=19``y=16`Solve for the area using the Area of a Rhombus formula`\text(Area)` `=` `1/2 times``x``times``y` Area of a Rhombus formula `=` `1/2 times ``19``times``16` Plug in the known lengths `=` `152 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=152 m^2` -
Question 6 of 6
6. Question
Find the area of the Triangle
- `\text(Area )=` (44) `mm^2`
Correct
Keep Going!
Incorrect
Area of a Triangle Formula
`\text(Area )=1/2 times``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=8``\text(height)=11`Solve for the area using the Area of a Triangle formula`\text(Area)` `=` `1/2 times``\text(base)``times``\text(height)` Area of a Triangle formula `=` `1/2 times ``8``times``11` Plug in the known lengths `=` `44 mm^2` The given measurements are in millimetres, so the area is measured as square millimetres`\text(Area)=44 mm^2`