Equation Word Problems (Age) 1
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Question 1 of 5
1. Question
Luke is 55 years younger than his brother James. The sum of their ages is 3535. How old is Luke?- (15) years old
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ First, label the values and form an equation using the information given.James’ age=x=xLuke’s age=x-5=x−5 (since he is 55 years younger)James’ age and Luke’s age add up to 3535 xx ++ x-5x−5 == 3535 Simplify the equation:x+x-5x+x−5 == 3535 2x-52x−5 == 3535 To solve for xx, it needs to be alone on one side.Start by moving -5−5 to the other side by adding 55 to both sides of the equation.22xx -5−5 == 3535 22xx -5−5 +5+5 == 3535 +5+5 22xx == 4040 -5+5−5+5 cancels out Next, remove 22 by dividing both sides of the equation by 22.22xx == 4040 22xx÷2÷2 == 4040÷2÷2 xx == 2020 2÷22÷2 cancels out James is 2020 years old.Now that we know James’ age, we can compute for Luke’s as well.Luke’s age == xx -5−5 == 2020 -5−5 Substitute x=20x=20 == 1515 Luke is 1515 years old.1515 years old -
Question 2 of 5
2. Question
Sophia is 44 years younger than her sister Irene. The sum of their ages is 3232 years. How old are they?-
Sophia is (14) years oldIrene is (18) years old
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ First, label the values and form an equation using the information given.Sophia’s age=x=xIrene’s age=x+4=x+4 (since she is 44 years older)Sophia’s age and Irene’s age add up to 3232 xx ++ x+4x+4 == 3232 Simplify the equation:x+x+4x+x+4 == 3232 2x+42x+4 == 3232 To solve for xx, it needs to be alone on one side.Start by moving 44 to the other side by subtracting 44 from both sides of the equation.22xx +4+4 == 3232 22xx +4+4 -4−4 == 3232 -4−4 22xx == 2828 4-44−4 cancels out Next, remove 22 by dividing both sides of the equation by 22.22xx == 2828 22xx÷2÷2 == 2828÷2÷2 xx == 1414 2÷22÷2 cancels out Substitute x=14x=14 to get the age of Sophia and Irene.Sophia’s age == xx == 1414 years old Irene’s age == xx +4+4 == 1414 +4+4 == 1818 years old Sophia is 1414 years oldIrene is 1818 years old -
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Question 3 of 5
3. Question
When Grace was 66 years old, her mother was 2525 years old. Now, Grace’s mother is twice as old as Grace. How old is Grace now?- (19) years old
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccKeywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ First, find the difference between Grace’s age and her mother’s based on the given information.Grace’s age=6=6Her mother’s age=25=25Her Mother’s Age -− Grace’s Age == 25-625−6 == 1919 Use the information gathered so far to label the values and form an equation.Her mother’s age=x=xGrace’s age=x-19=x−19 (since she is 1919 years younger)Grace’s mother is twice as old as Grace xx == 2×2× x-19x−19 Simplify the equation:xx == 2×(x-19)2×(x−19) xx == 2(x-19)2(x−19) To solve for xx, it needs to be alone on one side.Start by expanding the right side of the equation using the Distributive Property.xx == 22((xx -19)−19) xx == 22xx -−22(19)(19) xx == 22xx -38−38 Next, move 2x2x to the other side by subtracting 2x2x from both sides of the equation.xx == 22xx -38−38 xx -2x−2x == 22xx -38−38 -2x−2x -−xx == -38−38 2x-2x2x−2x cancels out Make both sides positive by multiplying -1−1.-−xx == -38−38 -−xx×-1×−1 == -38−38×-1×−1 xx == 3838 Substitute x=38x=38 to get the age of Grace and her mother.Her mother’s age == xx == 3838 years old Grace’s age == xx -19−19 == 3838 -19−19 == 1919 years old 1919 years old -
Question 4 of 5
4. Question
When Jack was born, his father was 2828 years old. His father is now 33 times as old as Jack. What are their ages now?-
Jack is (14) years oldHis father is (42) years old
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ Use the information gathered so far to label the values and form an equation.Jack’s age=x=xHis father’s age=x+28=x+28 (since he was 2828 years old when Jack was born)His father is 33 times as old as Jack x+28x+28 == 3×3× xx Simplify the equation:x+28x+28 == 3×x3×x x+28x+28 == 3x3x To solve for xx, it needs to be alone on one side.Start by moving xx to the other side by subtracting xx from both sides of the equation.xx +28+28 == 33xx xx +28+28 -x−x == 33xx -x−x 2828 == 22xx x-xx−x cancels out Next, remove 22 by dividing both sides of the equation by 22.2828 == 22xx 2828÷2÷2 == 22xx÷2÷2 1414 == xx 2÷22÷2 cancels out xx == 1414 Substitute x=14x=14 to get the age of Jack and his father.Jack’s age == xx == 1414 years old His father’s age == xx +28+28 == 1414 +28+28 == 4242 years old Jack is 1414 years oldHis father is 4242 years old -
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Question 5 of 5
5. Question
Alan’s age is 66 times that of Noah’s. Their combined ages is 4242 years. Three years ago, how old were they?-
Noah was (3) years oldAlan was (33) years old
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Subtitles- subtitles off
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- English
Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ Use the information gathered so far to label the values and form an equation.Noah’s age=x=xAlan’s age=6x=6x (since he 66 times as old as Noah)Alan and Noah’s combined ages is 4242 x+6xx+6x == 4242 Simplify the equation:x+6xx+6x == 4242 7x7x == 4242 To solve for xx, it needs to be alone on one side.Remove 77 by dividing both sides of the equation by 77.77xx == 4242 77xx÷7÷7 == 4242÷7÷7 xx == 66 7÷77÷7 cancels out Substitute x=6x=6 to get Noah and Alan’s age now.Noah’s age == xx == 66 years old Alan’s age == 66xx == 6(6(66)) == 3636 years old Finally, subtract 33 from each of their current ages to get Noah and Alan’s age three years ago.Noah’s age 33 years ago == 66 -3−3 == 33 years old Alan’s age 33 years ago == 3636 -3−3 == 3333 years old Noah was 33 years oldAlan was 3333 years old -
Quizzes
- One Step Equations – Add and Subtract 1
- One Step Equations – Add and Subtract 2
- One Step Equations – Add and Subtract 3
- One Step Equations – Add and Subtract 4
- One Step Equations – Multiply and Divide 1
- One Step Equations – Multiply and Divide 2
- One Step Equations – Multiply and Divide 3
- One Step Equations – Multiply and Divide 4
- Two Step Equations 1
- Two Step Equations 2
- Two Step Equations 3
- Two Step Equations 4
- Multi-Step Equations 1
- Multi-Step Equations 2
- Solve Equations using the Distributive Property 1
- Solve Equations using the Distributive Property 2
- Solve Equations using the Distributive Property 3
- Equations with Variables on Both Sides 1
- Equations with Variables on Both Sides 2
- Equations with Variables on Both Sides 3
- Equations with Variables on Both Sides (Fractions) 1
- Equations with Variables on Both Sides (Fractions) 2
- Solve Equations – Variables on Both Sides (Distributive Property) 1
- Solve Equations – Variables on Both Sides (Distributive Property) 2
- Solve Equations – Variables on Both Sides (Distributive Property) 3
- Solve Equations – Variables on Both Sides (Distributive Property) 4
- Writing Equations 1
- Writing Equations 2
- Writing Equations 3
- Writing Equations 4
- Equation Word Problems (Age) 1
- Equation Word Problems (Money) 1
- Equation Word Problems (Harder) 1
- Equation Problems with Substitution 1
- Equation Problems (Geometry) 1
- Equation Problems (Geometry) 2
- Equation Problems (Perimeter)
- Equation Problems (Area)
- Solve for a Variable or Formula 1
- Solve for a Variable or Formula 2
- Solve for a Variable or Formula 3


