Equations of a Line
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Question 1 of 7
1. Question
Graph the lines `y=3` and `x=4`Hint
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Fantastic!
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A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineStart by working out the `\text(y-values)` for each `\text(x-value)` in the table of values.`x` `0` `1` `2` `y` Substitute the `\text(x-values)` into the given equation to find the corresponding `\text(y-value)`Because there is no `x` in the equation `y=3`, the answer will not change even if `x` does.`x` `0` `1` `2` `y` `3` `3` `3` Now, we can plot the points given from the table of values
To graph the line, simply connect the plotted points
Do the same for `x=4`. Just like the first equation, no matter what `\text(y-value)` we have,
the `\text(x-value)` is equal to `4`. This means that the line cuts through the `\text(x-axis)`.
To graph the line, simply connect the plotted points
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Question 2 of 7
2. Question
Graph the line `y=2x+1`Hint
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Nice Job!
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A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineStart by working out the `\text(y-values)` for each `\text(x-value)` in the table of values.`x` `0` `1` `2` `y` Substitute the `\text(x-values)` into the given equation to find the corresponding `\text(y-value)`For the `\text(x-value)=0``y` `=` `2``x``+1` Given Equation `y` `=` `2``(0)``+1` Plug in `x=0` `y` `=` `1` We can now add `y=1` to the table under `x=0``x` `0` `1` `2` `y` `1` Repeat this process for each `\text(x-value)``x` `0` `1` `2` `y` `1` `3` `5` Now, we can plot the points given from the table of values
To graph the line, simply connect the plotted points
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Question 3 of 7
3. Question
Find the equation of the line
Hint
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Correct!
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A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineFind the ordered pairs `(``x``,``y``)` from the line.
`x` `0` `1` `2` `y` `0` `2` `4` Find the multiplier from the difference of consecutive `y` values.`2``-``0` `=` `2` `4``-``2` `=` `2` Multiplier is `2` Write a formula with the multiplier `(2)` and let `b` be the constant.`y=``2``x +-` `b`Since the line passes through the origin, `b=0`.This means the equation of the line is `y=2x`.`y=2x` -
Question 4 of 7
4. Question
Find the equation of the line
Hint
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Great Work!
Incorrect
A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineFind the ordered pairs `(``x``,``y``)` from the line.
`x` `0` `1` `2` `y` `1` `3` `5` Find the multiplier from the difference of consecutive `y` values.`3``-``1` `=` `2` `5``-``3` `=` `2` Multiplier is `2` Write a formula with the multiplier `(2)` and let `b` be the constant.`y=``2``x +-` `b`Since the line cuts through the `\text(y-axis)` at `1`, `b=1`.This means the equation of the line is `y=2x+1`.`y=2x+1` -
Question 5 of 7
5. Question
Find the equation of the line
Hint
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Keep Going!
Incorrect
A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineFind the ordered pairs `(``x``,``y``)` from the line.
`x` `0` `1` `2` `y` `4` `2` `0` Find the multiplier from the difference of consecutive `y` values.`2``-``4` `=` `-2` `0``-``2` `=` `-2` Multiplier is `-2` Write a formula with the multiplier `(-2)` and let `b` be the constant.`y=``-2``x +-` `b`Since the line cuts through the `\text(y-axis)` at `4`, `b=4`.This means the equation of the line is `y=-2x+4`.`y=-2x+4` -
Question 6 of 7
6. Question
Find the equation of the line
Hint
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Excellent!
Incorrect
A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineFind the ordered pairs `(``x``,``y``)` from the line.
`x` `0` `1` `2` `y` `3` `4` `5` Find the multiplier from the difference of consecutive `y` values.`5``-``4` `=` `1` `4``-``3` `=` `1` Multiplier is `1` Write a formula with the multiplier `(1)` and let `b` be the constant.`y=``1``x +-` `b``y=x +-` `b`Since the line cuts through the `\text(y-axis)` at `3`, `b=3`.This means the equation of the line is `y=x+3`.`y=x+3` -
Question 7 of 7
7. Question
Find the equation of the line
Hint
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Well Done!
Incorrect
A table of values is used to find the ordered pairs `(``x``,``y``)` of points on a lineFind the ordered pairs `(``x``,``y``)` from the line.
`x` `0` `1` `2` `y` `0` `1/2` `1` Find the multiplier from the difference of consecutive `y` values.`1/2``-``0` `=` `1/2` `1``-``1/2` `=` `1/2` Multiplier is `1/2` Write a formula with the multiplier `(1/2)` and let `b` be the constant.`y=``1/2``x +-` `b`Since the line cuts through the `\text(y-axis)` at `0`, `b=0`.This means the equation of the line is `y=1/2x`.`y=1/2x`