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Question 1 of 5
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
Get nn alone to the left side and all constants to the right.
Start by moving 55 to the other side by subtracting 55 from both sides of the equation.
nn +5+5 |
== |
13-13−nn |
nn +5+5 -5−5 |
== |
13-13−nn -5−5 |
nn |
== |
8-8−nn |
5-55−5 cancels out |
Next, move -n−n to the other side by adding nn to both sides of the equation.
nn |
== |
8-8−nn |
nn +n+n |
== |
8-8−nn +n+n |
22nn |
== |
88 |
-n+n−n+n cancels out |
Finally, remove 22 by dividing 22 from both sides.
22nn |
== |
88 |
22nn÷2÷2 |
== |
88÷2÷2 |
nn |
== |
44 |
2÷22÷2 cancels out |
Check our work
To confirm our answer, substitute n=4n=4 to the original equation.
n+5n+5 |
== |
13-n13−n |
4+54+5 |
== |
13-413−4 |
Substitute n=4n=4 |
99 |
== |
99 |
Since the equation is true, the answer is correct.
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Question 2 of 5
Solve for xx
10x-5=x+410x−5=x+4
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To solve for xx, get xx by itself
Subtract xx from both sides of the equation
10x-510x−5 -x−x |
== |
x+4x+4 -x−x |
10x-510x−5 -x−x |
== |
xx+4+4 -x−x |
x-xx−x cancels out |
9x-59x−5 |
== |
44 |
Next, add 55 to both sides of the equation
9x-59x−5 +5+5 |
== |
44 +5+5 |
9x9x-5−5 +5+5 |
== |
44 +5+5 |
-5+5−5+5 cancels out |
9x9x |
== |
99 |
Finally, divide both sides of the equation by 99
9x9x÷9÷9 |
== |
99÷9÷9 |
99xx÷9÷9 |
== |
99÷9÷9 |
×9÷9×9÷9 cancels out |
xx |
== |
11 |
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Question 3 of 5
Solve for xx
4x+5=-8x-74x+5=−8x−7
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To solve for xx, get xx by itself
Add 8x8x to both sides of the equation
4x+54x+5 +8x+8x |
== |
-8x-7−8x−7 +8x+8x |
4x+54x+5 +8x+8x |
== |
-8x−8x-7−7 +8x+8x |
-8x+8x−8x+8x cancels out |
12x+512x+5 |
== |
-7−7 |
Next, subtract 55 from both sides of the equation
12x+512x+5 -5−5 |
== |
-7−7 -5−5 |
12x12x+5+5 -5−5 |
== |
-7−7 -5−5 |
5-55−5 cancels out |
12x12x |
== |
-12−12 |
Finally, divide both sides of the equation by 1212
12x12x÷12÷12 |
== |
-12−12÷12÷12 |
1212xx÷12÷12 |
== |
-12−12÷12÷12 |
×12÷12×12÷12 cancels out |
xx |
== |
-1−1 |
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Question 4 of 5
Solve for pp
p-5+3p=-9p−5+3p=−9
Incorrect
To solve for pp, get pp by itself
Combine like terms to simplify.
pp -5−5+3p+3p |
== |
-9−9 |
(p+3p)(p+3p) -5−5 |
== |
-9−9 |
4p-54p−5 |
== |
-9−9 |
Add 55 to both sides of the equation
4p-54p−5 +5+5 |
== |
-9−9 +5+5 |
4p4p-5−5 +5+5 |
== |
-9−9 +5+5 |
-5+5−5+5 cancels out |
4p4p |
== |
-4−4 |
4p4p÷4÷4 |
== |
-4−4÷4÷4 |
Divide both sides by 44 |
44pp÷4÷4 |
== |
-4−4÷4÷4 |
×4÷4×4÷4 cancels out |
pp |
== |
-1−1 |
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Question 5 of 5
Solve for rr
-12=-2r-4r−12=−2r−4r
Incorrect
To solve for rr, get rr by itself
Combine like terms to simplify.
-12−12 |
== |
-2r-4r−2r−4r |
-12−12 |
== |
-6r−6r |
Get the rr variable on one side of the equation
-12−12÷(-6)÷(−6) |
== |
-6r÷(-6) |
Divide both sides by -6 |
-12÷(-6) |
= |
-6r÷(-6) |
×(-6)÷(-6) cancels out |
2 |
= |
r |
r |
= |
2 |