Money Word Problems

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Question 1 of 7

1. Question

Frank earns

$$14$ per hour for the first

$3$ hours of work and

$$12.50$ an hour after that. How many hours did he work to earn

$$117$ ?

$x=$ (6)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of hours worked after

$3$ hrs:

$x$

Translate the problem into an equation based on the diagram

$3($14)+x($12.50)$

$=$

$$117$

Solve for

$x$

$3($14)+x($12.50)$	$=$	$$117$
$42+12.5x$	$=$	$117$
$42+12.5x$ $-42$	$=$	$117$ $-42$	Subtract $42$ from both sides
$12.5x$	$=$	$75$
$12.5x$ $-:12.5$	$=$	$75$ $-:12.5$	Divide both sides by $12.5$
$x$	$=$	$6$

$x=6$

Question 2 of 7

2. Question

A school concert was attended by adults and students. The tickets cost

$$15$ per adult and

$$6$ per student. The total ticket sales was

$$2235$ . If

$95$ adults attended the concert, how many students were there?

(135)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of students in the concert:

$n$

Translate the problem into an equation based on the diagram

$95($15)+n($6)$

$=$

$$2235$

Solve for

$n$

$95($15)+n($6)$	$=$	$$2235$
$1425+6n$	$=$	$2235$
$1425+6n$ $-1425$	$=$	$2235$ $-1425$	Subtract $1425$ from both sides
$6n$	$=$	$810$
$6n$ $-:6$	$=$	$810$ $-:6$	Divide both sides by $6$
$n$	$=$	$135$

$135$

Question 3 of 7

3. Question

I have

$60$ coins. Some are

$10¢$ and the rest are

$20¢$ coins. Altogether, they total

$$10.80$ . How many of each of the coins do I have?

Number of $10¢$ coins: (12)

Number of $20¢$ coins: (48)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of

$10¢$ coins:

$n$

number of

$20¢$ coins:

$60-n$

Translate the problem into an equation based on the diagram and make sure all values are in the same units

$10¢(n)+20¢(60-n)$	$=$	$$10.80$
$10¢(n)+20¢(60-n)$	$=$	$1080¢$

Solve for

$n$

$10¢(n)+20¢(60-n)$	$=$	$1080¢$
$10n+1200-20n$	$=$	$1080$
$1200-10n$	$=$	$1080$
$1200-10n$ $-1200$	$=$	$1080$ $-1200$	Subtract $1200$ from both sides
$-10n$	$=$	$-120$
$-10n$ $-:(-10)$	$=$	$-120$ $-:(-10)$	Divide both sides by $-10$
$n$	$=$	$12$	number of $10¢$ coins

Solve for

$60-n$

	$60-n$
$=$	$60-12$	Substitute $n$
$=$	$48$	number of $20¢$ coins

Number of

$10¢$ coins:

$12$

Number of

$20¢$ coins:

$48$

Question 4 of 7

4. Question

A bank teller orders a payroll in

$$20$ and

$$50$ notes. She needs

$82$ notes totalling

$$2450$ . Calculate how many of each note she must order.

Number of $$20$ notes: (55)

Number of $$50$ notes: (27)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of

$$20$ notes:

$x$

number of

$$50$ notes:

$82-x$

Translate the problem into an equation based on the diagram

$$20(x)+$50(82-x)$

$=$

$$2450$

Solve for

$x$

$$20(x)+$50(82-x)$	$=$	$$2450$
$20x+4100-50x$	$=$	$2450$
$4100-30x$	$=$	$2450$
$4100-30x$ $-4100$	$=$	$2450$ $-4100$	Subtract $4100$ from both sides
$-30x$	$=$	$-1650$
$-30x$ $-:(-30)$	$=$	$-1650$ $-:(-30)$	Divide both sides by $-30$
$x$	$=$	$55$	number of $$20$ notes

Solve for

$82-x$

	$82-x$
$=$	$82-55$	Substitute $x$
$=$	$27$	number of $$50$ notes

Number of

$$20$ notes:

$55$

Number of

$$50$ notes:

$27$

Question 5 of 7

5. Question

Anna has

$$8$ more than Julie, and Pina has

$$15$ less than Anna. If they have

$$37$ altogether, how much does each person have?

Anna: $$$ (20)

Julie: $$$ (12)

Pina: $$$ (5)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

Anna:

$x$

Julie:

$x-8$

Pina:

$x-15$

Translate the problem into an equation based on the diagram

$x+(x-8)+(x-15)$

$=$

$$37$

Solve for

$x$

$x+(x-8)+(x-15)$	$=$	$$37$
$3x-23$	$=$	$37$
$3x-23$ $+23$	$=$	$37$ $+23$	Add $23$ to both sides
$3x$	$=$	$60$
$3x$ $-:3$	$=$	$60$ $-:3$	Divide both sides by $3$
$x$	$=$	$$20$	Anna’s money

Solve for

$x-8$

	$x-8$
$=$	$20-8$	Substitute $x$
$=$	$$12$	Julie’s money

Solve for

$x-15$

	$x-15$
$=$	$20-15$	Substitute $x$
$=$	$$5$	Pina’s money

Anna:

$$20$

Julie:

$$12$

Pina:

$$5$

Question 6 of 7

6. Question

James earns

$$20$ a day more than Tom and

$$27$ a day less than Bob. The

$3$ friends’ total earnings for one day is

$$733$ . Find the daily earning of each friend.

James: $$$ (242)

Tom: $$$ (222)

Bob: $$$ (269)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

James:

$x$

Tom:

$x-20$

Bob:

$x+27$

Translate the problem into an equation based on the diagram

$x+(x-20)+(x+27)$

$=$

$$733$

Solve for

$x$

$x+(x-20)+(x+27)$	$=$	$$733$
$3x+7$	$=$	$733$
$3x+7$ $-7$	$=$	$733$ $-7$	Subtract $7$ from both sides
$3x$	$=$	$726$
$3x$ $-:3$	$=$	$726$ $-:3$	Divide both sides by $3$
$x$	$=$	$$242$	James’ daily earnings

Solve for

$x-20$

	$x-20$
$=$	$242-20$	Substitute $x$
$=$	$$222$	Tom’s daily earnings

Solve for

$x+27$

	$x+27$
$=$	$242+27$	Substitute $x$
$=$	$$269$	Bob’s daily earnings

James:

$$242$

Tom:

$$222$

Bob:

$$269$

Question 7 of 7

7. Question

Zoe has a certain number of

$10¢$ coins and

$4$ times that number are her

$50¢$ coins. The total value of all her coins is

$$37.80$ . How many of each coin does she have?

number of $10¢$ coins: (18)

number of $50¢$ coins: (72)

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A word problem can be drawn as a diagram and then translated into an equation for easier solving.

First, draw a diagram of the problem in order to understand it better

number of

$10¢$ coins:

$n$

Translate the problem into an equation based on the diagram, then make sure all units are the same

$10¢(n)+50¢(4n)$	$=$	$$37.80$
$10¢(n)+50¢(4n)$	$=$	$3780¢$

Solve for

$n$

$10¢(n)+50¢(4n)$	$=$	$3780¢$
$10n+200n$	$=$	$3780$
$210n$	$=$	$3780$
$210n$ $-:210$	$=$	$3780$ $-:210$	Divide both sides by $210$
$n$	$=$	$18$	number of $10¢$ coins

Solve for

$4n$

	$4n$
$=$	$4(18)$	Substitute $n$
$=$	$72$	number of $50¢$ coins

number of

$10¢$ coins:

$18$

number of

$50¢$ coins:

$72$

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