Information
You have already completed the quiz before. Hence you can not start it again.
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Loading...
-
Question 1 of 6
Incorrect
Loaded: 0%
Progress: 0%
0:00
Imaginary numbers have the properties i=√−1 or i2=−1.
Remove the negative from the root in √−36 and then simplify.
|
= |
√−1×√36 |
Separate out the √−1 from the root. |
|
= |
i×√36 |
Replace √−1 with i. |
|
= |
i×(√36) |
Simplify √36. |
|
= |
i×6 |
Rearrange the answer so that the i is on the right-hand side. |
|
= |
6i |
-
Question 2 of 6
Incorrect
Loaded: 0%
Progress: 0%
0:00
Imaginary numbers have the properties i=√−1 or i2=−1.
Remove the negative from the root in √−5 and then simplify.
|
= |
√−1×√5 |
Separate out the √−1 from the root. |
|
= |
i×√5 |
Replace √−1 with i. |
|
= |
i×√5 |
Rearrange the answer so that the i is on the right-hand side. |
|
= |
i√5 |
|
-
Question 3 of 6
Incorrect
Loaded: 0%
Progress: 0%
0:00
Imaginary numbers have the properties i=√−1 or i2=−1.
Remove the negative from the root in √−48 and then simplify.
|
= |
√−1×√48 |
Separate out the √−1 from the root. |
|
= |
i×√48 |
Replace √−1 with i. |
|
= |
i×(√48) |
Simplify √48=√16×√3. |
|
= |
i×(√16)×(√3) |
Simplify `sqrt(16). |
|
= |
i×(4)×(√3) |
Rearrange the answer so that the i is on the right-hand side. |
|
= |
4i√3 |
-
Question 4 of 6
Incorrect
Loaded: 0%
Progress: 0%
0:00
Imaginary numbers have the properties i=√−1 or i2=−1.
Remove the negative from the root in √−108 and then simplify.
|
= |
√−1×√108 |
Separate out the √−1 from the root. |
|
= |
i×√108 |
Replace √−1 with i. |
|
= |
i×√108 |
√108=√36×√3. |
|
= |
i×(√36)×(√3) |
Simplify √36. |
|
= |
i×(6)×(√3) |
Rearrange the answer so that the i is on the right-hand side. |
|
= |
6i√3 |
-
Question 5 of 6
Simplify
√−10×√−15
Incorrect
Loaded: 0%
Progress: 0%
0:00
Imaginary numbers have the properties i=√−1 or i2=−1.
Remove the negative from the root in √−10 and √−15 and then simplify.
|
= |
√−1×√10×√−1×√15 |
Separate out the √−1 from the root. |
|
= |
i×√10×i×√15 |
Replace √−1 with i. |
|
= |
i×(√5×√2)×i×(√5×√3) |
√10=√5×√2 and √15=√5×√3. |
|
= |
−1×5×√6 |
Simplify. |
|
= |
−5√6 |
-
Question 6 of 6
Incorrect
Loaded: 0%
Progress: 0%
0:00
Imaginary numbers have the properties i=√−1 or i2=−1.
Remove the negative from the root in √−14 and then simplify.
|
= |
√−1×√14 |
Separate out the √−1 from the root. |
|
= |
i×√14 |
Replace √−1 with i. |
|
= |
i×1√4 |
Simplify √14. |
|
= |
i×12 |
Rearrange the answer so that the i is on the right-hand side. |
|
= |
12i |