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Solve Equations with Variables on Both Sides using the Distributive Property>
Solve Equations – Variables on Both Sides (Distributive Property) 1Solve Equations – Variables on Both Sides (Distributive Property) 1
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Question 1 of 4
1. Question
Solve6(2m+5)-5(3m+2)=266(2m+5)−5(3m+2)=26- m=m= (-2)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccTo solve for mm, it needs to be alone on one side.Start by expanding the left side of the equation by using the Distributive Property.66(2(2mm +5)+5) -5−5(3(3mm +2)+2) == 2626 66(2(2mm)+)+66(5)(5) -5−5(3(3mm)) -5−5(2)(2) == 2626 1212mm +30-15+30−15mm -10−10 == 2626 -3−3mm +20+20 == 2626 Next, move 2020 to the other side by subtracting 2020 from both sides of the equation.-3−3mm +20+20 == 2626 -3−3mm +20+20 -20−20 == 2626 -20−20 -3−3mm == 66 20-2020−20 cancels out Finally, remove -3−3 by dividing both sides of the equation by -3−3.-3−3mm == 66 -3−3mm÷-3÷−3 == 66÷-3÷−3 mm == -2−2 -3÷-3−3÷−3 cancels out Check our workTo confirm our answer, substitute m=-2m=−2 to the original equation.6(2m+5)-5(3m+2)6(2m+5)−5(3m+2) == 2626 6(2(-2)+5)-5(3(-2)+2)6(2(−2)+5)−5(3(−2)+2) == 2626 Substitute m=-2m=−2 6(-4+5)-5(-6+2)6(−4+5)−5(−6+2) == 2626 6(1)-5(-4)6(1)−5(−4) == 2626 6+206+20 == 2626 2626 == 2626 Since the equation is true, the answer is correct.m=-2m=−2 -
Question 2 of 4
2. Question
Solve8(2y+3)-4(3y+2)=328(2y+3)−4(3y+2)=32- y=y= (4)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccTo solve for yy, it needs to be alone on one side.Start by expanding the left side of the equation by using the Distributive Property.88(2(2yy +3)-+3)−44(3(3yy +2)+2) == 3232 88(2(2yy)+)+88(3)(3) -4−4(3(3yy)) -4−4(2)(2) == 3232 1616yy +24-12+24−12yy-8−8 == 3232 44yy +16+16 == 3232 Next, move 1616 to the other side by subtracting 1616 from both sides of the equation.44yy +16+16 == 3232 44yy +16+16 -16−16 == 3232 -16−16 44yy == 1616 16-1616−16 cancels out Finally, remove 44 by dividing both sides of the equation by 44.44yy == 1616 44yy÷4÷4 == 1616÷4÷4 yy == 44 4÷44÷4 cancels out Check our workTo confirm our answer, substitute y=4y=4 to the original equation.8(2y+3)-4(3y+2)8(2y+3)−4(3y+2) == 3232 8[2(4)+3]-4[3(4)+2]8[2(4)+3]−4[3(4)+2] == 3232 Substitute y=4y=4 8(8+3)-4(12+2)8(8+3)−4(12+2) == 3232 8(11)-4(14)8(11)−4(14) == 3232 88-5688−56 == 3232 3232 == 3232 Since the equation is true, the answer is correct.y=4y=4 -
Question 3 of 4
3. Question
Solve9(m+1)=3(m-3)9(m+1)=3(m−3)- m=m= (-3)
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- English
Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccTo solve for mm, it needs to be alone on one side.Start by expanding the left side of the equation by using the Distributive Property.99((mm +1)+1) == 33((mm -3)−3) 99((mm)+)+99(1)(1) == 33((mm)+)+33(-3)(−3) 99mm +9+9 == 33mm -9−9 Next, move 99 to the other side by subtracting 99 from both sides of the equation.99mm +9+9 == 33mm -9−9 99mm +9+9 -9−9 == 33mm -9−9 -9−9 99mm == 33mm -18−18 9-99−9 cancels out Now, move 3m3m to the other side by subtracting 3m3m from both sides of the equation.99mm == 33mm -18−18 99mm -3m−3m == 33mm -18−18 -3m−3m 66mm == -18−18 3m-3m3m−3m cancels out Finally, remove 66 by dividing both sides of the equation by 66.66mm == -18−18 66mm÷6÷6 == -18−18÷6÷6 mm == -3−3 6÷66÷6 cancels out Check our workTo confirm our answer, substitute m=-3m=−3 to the original equation.9(m+1)9(m+1) == 3(m-3)3(m−3) 9(-3+1)9(−3+1) == 3(-3-3)3(−3−3) Substitute m=-3m=−3 9(-2)9(−2) == 3(-6)3(−6) -18−18 == -18−18 Since the equation is true, the answer is correct.m=-3m=−3 -
Question 4 of 4
4. Question
Solve2a+5=6(a-4)-3a2a+5=6(a−4)−3a- a=a= (29)
Hint
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Subtitles- subtitles off
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- English
Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccTo solve for aa, it needs to be alone on one side.Start by expanding the right side of the equation by using the Distributive Property.22aa +5+5 == 6(a -4)-3a 2a +5 = 6a -6(4)-3a 2a +5 = 3a -24 Next, move 2a to the other side by subtracting 2a from both sides of the equation.2a +5 = 3a -24 2a +5 -2a = 3a -24 -2a 5 = a -24 2a-2a cancels out Now, move -24 to the other side by adding 24 to both sides of the equation.5 = a -24 5 +24 = a -24 +24 29 = a -24+24 cancels out a = 29 Check our workTo confirm our answer, substitute a=29 to the original equation.2a+5 = 6(a-4)-3a 2(29)+5 = 6(29-4)-3(29) Substitute a=29 58+5 = 6(25)-87 63 = 150-87 63 = 63 Since the equation is true, the answer is correct.a=29
Quizzes
- One Step Equations – Add and Subtract 1
- One Step Equations – Add and Subtract 2
- One Step Equations – Add and Subtract 3
- One Step Equations – Add and Subtract 4
- One Step Equations – Multiply and Divide 1
- One Step Equations – Multiply and Divide 2
- One Step Equations – Multiply and Divide 3
- One Step Equations – Multiply and Divide 4
- Two Step Equations 1
- Two Step Equations 2
- Two Step Equations 3
- Two Step Equations 4
- Multi-Step Equations 1
- Multi-Step Equations 2
- Solve Equations using the Distributive Property 1
- Solve Equations using the Distributive Property 2
- Solve Equations using the Distributive Property 3
- Equations with Variables on Both Sides 1
- Equations with Variables on Both Sides 2
- Equations with Variables on Both Sides 3
- Equations with Variables on Both Sides (Fractions) 1
- Equations with Variables on Both Sides (Fractions) 2
- Solve Equations – Variables on Both Sides (Distributive Property) 1
- Solve Equations – Variables on Both Sides (Distributive Property) 2
- Solve Equations – Variables on Both Sides (Distributive Property) 3
- Solve Equations – Variables on Both Sides (Distributive Property) 4
- Writing Equations 1
- Writing Equations 2
- Writing Equations 3
- Writing Equations 4
- Equation Word Problems (Age) 1
- Equation Word Problems (Money) 1
- Equation Word Problems (Harder) 1
- Equation Problems with Substitution 1
- Equation Problems (Geometry) 1
- Equation Problems (Geometry) 2
- Equation Problems (Perimeter)
- Equation Problems (Area)
- Solve for a Variable or Formula 1
- Solve for a Variable or Formula 2
- Solve for a Variable or Formula 3