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Trigonometry Mixed Review: Part 2>
Trigonometry Mixed Review: Part 2 (1)Trigonometry Mixed Review: Part 2 (1)
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Question 1 of 8
1. Question
Solve for side aaRound your answer as a whole number- a=a= (13) mm
Hint
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Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find side aaasinAasinA == csinCcsinC Sine Rule Formula asin24°asin24° == 23sin46°23sin46° Plug in the values aa×sin46°×sin46° == sin24°×23sin24°×23 Cross multiply aa == sin24°×23sin46°sin24°×23sin46° Divide sin46°sin46° from each side to isolate aa aa == 13 m13 m Rounded to a whole number a=13 ma=13 m -
Question 2 of 8
2. Question
Solve for angle ZZRound your answer to the nearest degree- ∠Z=∠Z= (36)°°
Hint
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Need TextPlayCurrent Time 0:00/Duration Time 0:00Remaining Time -0:00Stream TypeLIVELoaded: 0%Progress: 0%0:00Fullscreen00:00MutePlayback Rate1x- 2x
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Chapters- Chapters
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find angle ZZysinYysinY == zsinZzsinZ Sine Rule Formula 39.7sin122°39.7sin122° == 27.5sinZ27.5sinZ Plug in the values sinsinZZ×39.7×39.7 == 27.5×sin122°27.5×sin122° Cross multiply sinsinZZ == 27.5×sin122°39.727.5×sin122°39.7 Divide 39.739.7 from each side to isolate sinAsinA sinsinZZ == 0.58740.5874 Evaluate Use the inverse function for sinsin on your calculator to get ZZ by itselfZZ == sin-1(0.5874)sin−1(0.5874) The inverse of sinsin is sin-1sin−1 ZZ == 35.972735.9727 Use the shift sinsin function on your calculator ZZ == 36°36° Rounded to the nearest degree ∠Z=36°∠Z=36° -
Question 3 of 8
3. Question
Find the length of aaRound your answer as a whole number- a=a= (41)mm
Hint
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Cosine Rule (finding a length)
a2a2==b2b2++c2c2-2−2bbcc×cos×cosAACosine Rule (finding an angle)
cosA=a2+b2−c22abcosA=a2+b2−c22abRemember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Cosine Rule (finding a length) to find the length of aaa2a2 == b2b2++c2c2-2−2bbcc×cos×cosAA Cosine Rule Formula a2a2 == 262262++212212-2−2(26)(26)(21)(21)×cos×cos121°121° Plug in the values a2a2 == 441+676-1092×cos121°441+676−1092×cos121° Evaluate a2a2 == 1679.4215781679.421578 √a2√a2 == √1679.421578√1679.421578 Take the square root of both sides aa == 4141 Rounded to a whole number a=41 ma=41 m -
Question 4 of 8
4. Question
Solve for angle BBRound your answer to the nearest minute- ∠B=∠B= (87)°° (16)′'
Hint
Help VideoCorrect
Well Done!
Incorrect
Cosine Rule (finding a length)
b2b2==a2a2++c2c2-2−2aacc×cos×cosBBCosine Rule (finding an angle)
cosB=a2+c2−b22accosB=a2+c2−b22acRemember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Cosine Rule (finding an angle) to solve for BBcoscosBB == a2+c2−b22aca2+c2−b22ac Cosine Rule Formula coscosBB == 72+62−922(7)(6)72+62−922(7)(6) Plug in known values coscosBB == 49+36-818449+36−8184 Evaluate coscosBB == 0.04760.0476 Use the inverse function for coscos on your calculator to get BB by itselfBB == cos-1(0.0476)cos−1(0.0476) The inverse of coscos is cos-1cos−1 BB == 87.2787.27 Use the shift coscos function on your calculator BB == 87°16′12”87°16'12” Use the degrees button on your calculator BB == 87°16’87°16’ Round up the minutes B=87°16’B=87°16’ -
Question 5 of 8
5. Question
Solve for side aaRound your answer to two decimal places- a=a= (28.73) cmcm
Correct
Excellent!
Incorrect
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find side aaasinAasinA == csinCcsinC Sine Rule Formula asin67°asin67° == 17sin33°17sin33° Plug in the values aa×sin33°×sin33° == sin67°×17sin67°×17 Cross multiply aa == sin67°×17sin33°sin67°×17sin33° Divide sin33°sin33° from each side to isolate aa aa == 28.73 cm28.73 cm Rounded to two decimal places a=28.73 cma=28.73 cm -
Question 6 of 8
6. Question
Find the length of ccRound your answer as a whole number- c=c= (39)cmcm
Correct
Correct!
Incorrect
Cosine Rule (finding a length)
c2c2==a2a2++b2b2-2−2aabb×cos×cosCCCosine Rule (finding an angle)
cosC=a2+b2−c22abcosC=a2+b2−c22abRemember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Cosine Rule (finding a length) to find the length of ccc2c2 == a2a2++b2b2-2−2aabb×cos×cosCC Cosine Rule Formula c2c2 == 182182++282282-2−2(18)(18)(28)(28)×cos×cos144°144° Plug in the values c2c2 == 324+784-1008×cos144°324+784−1008×cos144° Evaluate c2c2 == 1517.9905361517.990536 √c2√c2 == √1517.990536√1517.990536 Take the square root of both sides cc == 39 cm39 cm Rounded to a whole number c=39 cmc=39 cm -
Question 7 of 8
7. Question
Solve for side ccRound your answer to two decimal places- c=c= (7.35) kmkm
Hint
Help VideoCorrect
Fantastic!
Incorrect
Need TextPlayCurrent Time 0:00/Duration Time 0:00Remaining Time -0:00Stream TypeLIVELoaded: 0%Progress: 0%0:00Fullscreen00:00MutePlayback Rate1x- 2x
- 1.5x
- 1.25x
- 1x
- 0.75x
- 0.5x
Subtitles- subtitles off
Captions- captions off
- English
Chapters- Chapters
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find side ccbsinBbsinB == csinCcsinC Sine Rule Formula 5.8sin47°5.8sin47° == csin68°csin68° Plug in the values cc×sin47°×sin47° == sin68°×5.8sin68°×5.8 Cross multiply cc == sin68°×5.8sin47°sin68°×5.8sin47° Divide sin47°sin47° from each side to isolate cc cc == 7.35 km7.35 km Rounded to two decimal places c=7.35 kmc=7.35 km -
Question 8 of 8
8. Question
Solve for angle BBRound your answer to the nearest decimal degree- ∠B=∠B= (38)°°
Correct
Great Work!
Incorrect
Remember
- Uppercase letters represent angles in the triangle
- Lowercase letters represent the side lengths
Labelling the triangle
We can use the Sine Rule to find angle BBbsinBbsinB == csinCcsinC Sine Rule Formula 11sinB11sinB == 17sin108°17sin108° Plug in the values sinsinBB×17×17 == 11×sin108°11×sin108° Cross multiply sinsinBB == 11×sin108°1711×sin108°17 Divide 1717 from each side to isolate sinBsinB sinsinBB == 0.6150.615 Evaluate Use the inverse function for sinsin on your calculator to get BB by itselfBB == sin-1(0.615)sin−1(0.615) The inverse of sinsin is sin-1sin−1 BB == 37.95137.951 Use the shift sinsin function on your calculator BB == 38°38° Rounded to a whole number ∠B=38°∠B=38°
Quizzes
- Intro to Trigonometric Ratios (SOH CAH TOA) 1
- Intro to Trigonometric Ratios (SOH CAH TOA) 2
- Round Angles (Degrees, Minutes, Seconds)
- Evaluate Trig Expressions using a Calculator 1
- Evaluate Trig Expressions using a Calculator 2
- Trig Ratios: Solving for a Side 1
- Trig Ratios: Solving for a Side 2
- Trig Ratios: Solving for an Angle
- Angles of Elevation and Depression
- Trig Ratios Word Problems: Solving for a Side
- Trig Ratios Word Problems: Solving for an Angle
- Area of Non-Right Angled Triangles 1
- Area of Non-Right Angled Triangles 2
- Law of Sines: Solving for a Side
- Law of Sines: Solving for an Angle
- Law of Cosines: Solving for a Side
- Law of Cosines: Solving for an Angle
- Trigonometry Word Problems 1
- Trigonometry Word Problems 2
- Trigonometry Mixed Review: Part 1 (1)
- Trigonometry Mixed Review: Part 1 (2)
- Trigonometry Mixed Review: Part 1 (3)
- Trigonometry Mixed Review: Part 1 (4)
- Trigonometry Mixed Review: Part 2 (1)
- Trigonometry Mixed Review: Part 2 (2)
- Trigonometry Mixed Review: Part 2 (3)