Interpret Grouped Frequency Tables

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Question 1 of 6

A bus depot conducted a survey on how many passengers were on each bus through an

$8$ hour period. How many buses had less than

$20$ passengers?

$\text(Class)$	$\text(Class Centre) (c.c.)$	$\text(Frequency) (f)$	$f⋅c.c.$
$0-4$	$2$	$5$	$10$
$5-9$	$7$	$9$	$63$
$10-14$	$12$	$13$	$156$
$15-19$	$17$	$10$	$170$
$20-24$	$22$	$7$	$154$
$25-29$	$27$	$2$	$54$

(37) $\text(buses)$

Question 2 of 6

A bus depot conducted a survey on how many passengers were on each bus through an

$8$ hour period. Find the modal class.

$\text(Class)$	$\text(Class Centre) (c.c.)$	$\text(Frequency) (f)$	$f⋅c.c.$
$0-4$	$2$	$5$	$10$
$5-9$	$7$	$9$	$63$
$10-14$	$12$	$13$	$156$
$15-19$	$17$	$10$	$170$
$20-24$	$22$	$7$	$154$
$25-29$	$27$	$2$	$54$

$\text(Modal Class )=$ (10) $-$ (14)

Question 3 of 6

A bus depot conducted a survey on how many passengers were on each bus through an

$8$ hour period. Find the mean.

$\text(Class)$	$\text(Class Centre) (c.c.)$	$\text(Frequency) (f)$	$f⋅c.c.$
$0-4$	$2$	$5$	$10$
$5-9$	$7$	$9$	$63$
$10-14$	$12$	$13$	$156$
$15-19$	$17$	$10$	$170$
$20-24$	$22$	$7$	$154$
$25-29$	$27$	$2$	$54$

Round off your answer to one decimal place.

$\text(Mean )=$ (13.2)

Incorrect

Help Video

Mean Formula

$\text{Mean}=\frac{\color{#314EC4}{\sum f⋅c.c.}}{\color{#9202AA}{\sum f}}$

Remember

A grouped frequency distribution table is used for larger data sets and uses classes with intervals to group the scores.

First, find the sum of both the Frequency and $f⋅c.c.$ columns.

$sum f$	$=$	$5+9+13+10+7+2$
	$=$	$46$

$sum f⋅x$	$=$	$10+63+156+170+154+54$
	$=$	$607$

Class	Class Centre $(c.c.)$	Frequency $(f)$	$f⋅c.c$
0-4	2	5	10
5-9	7	9	63
10-14	12	13	156
15-19	17	10	170
20-24	22	7	154
25-29	27	2	54
		$\text(Total) =46$	$\text(Total) =607$

Finally, use the formula to compute for the mean.

$\text(Mean)$	$=$	$\frac{\color{#314EC4}{\sum f⋅c.c.}}{\color{#9202AA}{\sum f}}$	Mean Formula

$\text(Mean)$	$=$	$\frac{\color{#314EC4}{607}}{\color{#9202AA}{46}}$	Substitute values

$\text(Mean)$	$=$	$13.2$	Rounded to one decimal place

$\text(Mean)=13.2$

Question 4 of 6

The mass of

$32$ students was measured and the results are shown. Complete the grouped frequency distribution table and find the mean.

Class	Class Centre $(c.c.)$	Frequency $(f)$
51-55	53	1
56-60	58	4
61-65	63	8
66-70	68	10
71-75	73	6
76-80	78	2
81-85	83	1
		$\text(Total) =32$

Round off your answer to one decimal place.

$\text(Mean )=$ (67.1)

Incorrect

Help Video

Mean Formula

$\text{Mean}=\frac{\color{#314EC4}{\sum f⋅c.c.}}{\color{#9202AA}{\sum f}}$

Remember

A grouped frequency distribution table is used for larger data sets and uses classes with intervals to group the scores.

First, to complete the table, fill in the $f⋅c.c$ column by multiplying $f$ and $c.c.$ on each row.

Class	Class Centre $(c.c.)$	Frequency $(f)$	$f⋅c.c$
51-55	53	1	53
56-60	58	4	232
61-65	63	8	504
66-70	68	10	680
71-75	73	6	438
76-80	78	2	156
81-85	83	1	83
		$\text(Total) =32$

Next, find the sum of $f⋅c.c.$ column.

$sum f⋅x$	$=$	$53+232+504+680+438+156+83$
	$=$	$2146$

Class	Class Centre $(c.c.)$	Frequency $(f)$	$f⋅c.c$
51-55	53	1	53
56-60	58	4	232
61-65	63	8	504
66-70	68	10	680
71-75	73	6	438
76-80	78	2	156
81-85	83	1	83
		$\text(Total) =32$	$\text(Total) =2146$

Finally, use the formula to compute for the mean.

$\text(Mean)$	$=$	$\frac{\color{#314EC4}{\sum f⋅c.c.}}{\color{#9202AA}{\sum f}}$	Mean Formula

$\text(Mean)$	$=$	$\frac{\color{#314EC4}{2146}}{\color{#9202AA}{32}}$	Substitute values

$\text(Mean)$	$=$	$67.1$	Rounded to one decimal place

$\text(Mean)=67.1$

Question 5 of 6

A bus depot conducted a survey on how many passengers were on each bus through an

$8$ hour period. Find the median class.

$\text(Class)$	$\text(Class Centre) (c.c.)$	$\text(Frequency) (f)$
$0-4$	$2$	$5$
$5-9$	$7$	$9$
$10-14$	$12$	$13$
$15-19$	$17$	$10$
$20-24$	$22$	$7$
$25-29$	$27$	$2$
		$\text(Total) =46$

$\text(Median Class )=$ (10)- (14)

Class	Class Centre $(c.c.)$	Frequency $(f)$	Cumulative Frequency
0-4	2	5	5
5-9	7	9	5+9=14
10-14	12	13	14+13=27
15-19	17	10	27+10=37
20-24	22	7	37+7=44
25-29	27	2	44+2=46
		$\text(Total) =46$

Class	Class Centre $(c.c.)$	Frequency $(f)$	Cumulative Frequency
0-4	2	5	5
5-9	7	9	5+9=14
10-14	12	13	14+13=27
15-19	17	10	27+10=37
20-24	22	7	37+7=44
25-29	27	2	44+2=46
		$\text(Total) =46$

Question 6 of 6

The mass of

$32$ students was measured and the results are shown. Find the median class.

$\text(Class)$	$\text(Class Centre) (c.c.)$	$\text(Frequency) (f)$
$51-55$	$53$	$1$
$56-60$	$58$	$4$
$61-65$	$63$	$8$
$66-70$	$68$	$10$
$71-75$	$73$	$6$
$76-80$	$78$	$2$
$81-85$	$83$	$1$
		$\text(Total) =32$

$\text(Median Class )=$ (66)- (70)

$\text(Total Buses)$	$=$	$5+9+13+10$
	$=$	$37$

Interpret Grouped Frequency Tables

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Quiz summary

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1. Question

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Well Done!

2. Question

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Nice Job!

3. Question

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Excellent!

Mean Formula

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Mean Formula

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5. Question

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6. Question

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Quizzes

Class	Class Centre $(c.c.)$	Frequency $(f)$	Cumulative Frequency
51-55	53	1	1
56-60	58	4	1+4=5
61-65	63	8	5+8=13
66-70	68	10	13+10=23
71-75	73	6	23+6=29
76-80	78	2	29+2=31
81-85	83	1	31+1=32
		$\text(Total) =32$